Abstract: During the lab a better agent for absorbing Procion Red Dye was trying to be found. Using the different dilutions of a stock solution and a spectrophotometer an Absorbance vs. Concentration graph was created and using the trendline from that graph it was determined which agent‚ zeolite‚ magnetic zeolite‚ or charcoal were better at absorbing the dye. From the results collected it was found that charcoal was the best at absorbing the dye‚ when moles of dye per gram of agent used were calculated
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challenges? What solutions has it chosen? Are there any solutions that the company hasn’t considered? Google has partially identified the challenges it faces‚ but then again‚ can always use more improvement to ensure that they stay ahead of the competition. On several occassions the company has chosen to approach these challenges head on making sure to correct the problem directly and making sure that the solution works and that customers are satisfied. Google has had several solutions to its problems
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that passing through. Biological substances such bromophenol blue and methyl orange‚ are the common substances to be used in testing of interaction of substance with the light. These solutions called pigments where they usually can absorb the visible of light that passing through it. The cleared compounds or solution also can absorb the light that is not seen through the naked eyes. The wavelength specifically used to test the absorbance level is 400 to 600 those are in nanometer unit‚ in this experiment
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Spectrophotometry was used in the lab to determine whether non-magnetized zeolite‚ magnetized zeolite‚ or charcoal was the more effective sequestration agent for Procion Red Dye. A calibration curve was created with the known concentrations and the absorbances of the Procion Red Dye dilutions at λmax. The slope of the calibration curve was used to determine the concentration of the analytes. As a result‚ charcoal was shown to be the more effective sequestration agent. Introduction PAHs‚ polycyclic
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First hand investigation of the Dissolution of Solutes Background Information Molar heat of solution * The molar heat of solution of a substance is the heat absorbed when one mole of the substance dissolves in a large excess of water. It is expressed in kJ/mol. * The specific heat of water is a constant‚ with a value of 4.18 J/ g*oC. AIM: To determine the molar heat of solution for two different solids Equipment: * A calorimeter (made using 2 Styrofoam cups with a cardboard lid)
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was: If the pH level of the solution is more basic‚ then the potato membrane will weigh less due to osmosis. Our null hypothesis was: If the pH level of a solution is either acidic or basic‚ then it will have no effect on the weight. The independent variable was the different solutions of different pH values. The dependent variable was the weight of the potato‚ which was measured in grams. The baseline of this experiment is the weight of the potato when in the milk solution because milk has a neutral
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determine the protein concentration of the solution from the standard curve by diluting the solution. Dilution itself is a process of lessening a solute’s concentration in a solution. In this experiment‚ dilution can be done by reducing the amount of protein solution from 1.0 ml to 0.2 ml. Without the process of dilution‚ the absorbance will end up being an extrapolated value causing the result to be unreliable. Part 2 6.
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x 30cm) String for tying dialysis tubing Clear plastic drinking cups Sharpie Markers Funnels Glucose/starch solution Distilled water IKI solution Glucose TesTape 0‚ .2‚ .4‚ .6‚ .8‚ and 1 Molar Sucrose Solution Cork Borer Potatoes Scale Exercise 1: Diffusion Fill a dialysis bag with a sugar/starch solution and immerse the bag in a dilute iodine solution. Water‚ sugar‚ starch‚ and iodine molecules will all be in motion‚ and each molecule will move to a region of its lower
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solvent. The higher the solute in solvent‚ then there will be a higher rate of osmosis through the diffusion gradient forming a hypertonic or hypotonic solution. Solvent with equal or no solute forms an isotonic solution. Materials: Distilled water‚ sucrose‚ dialysis tubing‚ string‚ 250 ml beaker. Procedure: To demonstrate and isotonic solution we needed 3 inches of dialysis tubing. We tied off one end of the dialysis tubing to create a bag‚ filled it with distilled water‚ and tie of other end
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Introduction: To determine the biological changes that occur to potato cores over a period of time in different solutions of sucrose and to relate these changes to the phenomenon of osmosis. Method: We soaked several discs of potato cuted using a cork borer with around 1 centimeter of diameter and 2 milimeters of lenght into sucrose solutions with a different range of concentrations from 0 to 1.0M. Then we weighed all the potato cylinders on an electronic balance
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