forced damped transverse vibration of a beam and verify Dunkerley’s empirical formula. According to Dunkerley’s empirical formula‚ 1f2=1fb2+1fω2 where f referring to the natural frequency of heavy beam with central load fb referring to the natural frequency of heavy beam only fω referring to the natural frequency of light beam with central load M By using the results of light damping‚ Dunkerley’s empirical formula would be studied and verified by comparing the calculated resonant frequency
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acceleration due to gravity at the Earth’s surface (g) g’ = (re2 / r2) g Acceleration due to gravity inside the Earth Here let r represent the radius of the point inside the earth. The formula for finding out the acceleration due to gravity at this point becomes: g’ = ( r / re )g In both the above formulas‚ as expected‚ g’ becomes equal to g when r = re. PROPERTIES OF MATTER Density The mass of a substance contained in unit volume is its density
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Physics “FORMULAS LIST “ | | | | | | | Quantity |Symbol |Formula | |% Error | |% Error = ( |A-M| ) x 100 /A | |% Uncertainty | |% Uncertainty = (Uncertainty
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Prepared by : Tan “Formula One Cars Details” Formula A formula one car is a single-seat ‚open cockpit‚ open – wheel racing car with substantial font and rear wings ‚ and an engine positioned behind the driver ‚ intended to be used in competition ar Formula One racing events . The regulations governing the cats are unique to the championships . The Formula One regulations specify that cars must be constructed by racing team themselves ‚ through the design and manufacture and outsourced
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9. A concrete highway is built of slabs 14 m long (20Cº). How wide should the expansion cracks be (at 20Cº) between the slabs to prevent buckling if the temperature range is -30Cº to +50Cº? I know I use the formula: L = LoT L = ? (Change in length of the slabs. We are solving for this.) = 12e-6 (Coefficient of expansion. I looked it up on page 388.) Lo = 14 m (Initial length of slabs.) T = 30 Cº (50Cº - 20Cº) (Change in temperaure. You only care about the hottest number
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Muhil Arumugam Gold 3 Calculating the Formula of a Hydrate through Experimentation Purpose The purpose of this lab is to determine the formula of a given hydrate through collecting and calculating experimental data. Data Mass (g) of crucible 29.9g Mass (g) of crucible with hydrate 32.35g Mass (g) of crucible and anhydrous salt 31.39g Questions and Calculations 1. What was the mass of the original hydrate? 2.45g of hydrate Calculations: Mass of crucible with hydrate (32.35g) - Mass of crucible
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How to Prepare and Deliver Presentations Date: February 22‚ 2015 To: All Employees of Easy to Be Green From: Lisa Harris‚ HR Staff Assistant Subject: Instructions on how to prepare and deliver presentations. It has come to the attention of Human Resources that several employees do not know how to properly prepare and deliver presentations. Easy to Be Green is in the process up training courses for employees on how to prepare and deliver presentations; however this will take
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Return on Shareholders Funds (ROSF) Ratio Definition: The Return On Shareholders Funds (ROSF) ratio is a measure of the profit for the period which is available to the ordinary shareholders with the ordinary shareholders’ stake in a business. Formula: Return On Shareholders Funds = ((Net profit after taxation & preference dividend) / (Ordinary share capital + Reserves)) * 100% Example 1: If the net income of PPC Ltd is $80‚000 whereas shareholder’s funds are $500‚000. Then‚ the ROSF =
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bond angles. (Note that the angles ‚ ‚ ‚ and are always zero.) The surface area of a sphere is: Archimedes first derived this formula[citation needed] from the fact that the projection to the lateral surface of a circumscribed cylinder (i.e. the Lambert cylindrical equal-area projection) is area-preserving; it equals the derivative of the formula for the volume with respect to r because the total volume inside a sphere of radius r can be thought of as the summation of the surface area
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CHAPTER 1 ELECTRICAL FORMULAS OHM’S LAW/POWER FORMULAS R x I2 E x I P R P E E2 RxI R P I P x R E I P I E R E R P I2 E2 P P = Power = Watts R = Resistance = Ohms I = Current = Amperes E = Force = Volts 1-1 OHM’S LAW DIAGRAM AND FORMULAS E I E = I x R I = E ÷ R R = E ÷ I R Voltage = Current x Resistance Current = Voltage ÷ Resistance Resistance = Voltage ÷ Current POWER DIAGRAM AND FORMULAS P E I = P ÷ E E = P ÷ I P = I x E I Current = Power ÷ Voltage
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