VECTOR & RELATIVE VELOCITY Set 1 1. What is the total displacement of a trip in which a person travels 10 km[N] and then 24 km[E]? 2. What is the total displacement of a trip of 50 km[W] followed by a trip of 100 km[N30°E]? 3. What is the total displacement of a trip of 100 km[N30°E] followed by a trip of 50 km[W]? What is significant about the result when compared to the answer for question 2? 4. A small boy goes to a store 2 blocks[N]‚ 3 blocks[E]‚ l block[S]‚ 5 blocks[W]
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released until it strikes the ground. 4. The time it takes for the ball to hit the ground depends on v0 ‚ g and h. 004 10.0 points The velocity of a projectile at launch has a horizontal component vh and a vertical component vv . When the projectile is at the highest point of its trajectory‚ identify the vertical and the horizontal components of its velocity and the vertical component of its acceleration. Consider air resistance to be negligible. 4. It cannot be determined. 002 10.0 points
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from the origin. Position –Time Graph Graph increased with time and then become constant Velocity-Time Graph Graph increased and decreased with time and then become zero Acceleration –Time Graph Graph increased and decreased with time some time becomes positive and some tie negative then zero. 2. In red make a prediction for the distance-time‚ velocity-time and acceleration-time graphs for each situation. b. The man is sleeping under the tree. When
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09-1 Velocity Cellular Case Power Starterpack is part of Velocity Cellular Services that provides both the wireless services and products (cellular phones) to its clients. At the beginning of a cell phone contract‚ a cellular phone is sold with a wireless service that will generate cash for the service provider for the length of the contract; making Velocity Cellular Service multiple deliverables. Power Starterpack compromises of a single deliverable because the only service it is providing
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Lab #3: Initial Velocity of a Projectile | | | Abhishek Samdaria | Pd.4 and 5 | | Lab #3: Initial Velocity of a Projectile Theory: How can we determine the initial velocity of a projectile? Experimental Design: The purpose behind this experiment was to determine the initial velocity of a projectile. Projection motion consists of kinematics of motion in the x and y directions. With two dimension kinematics‚ there are the x and y components in any given velocity. In projectile
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at a velocity of 80 km/h when he sees an old woman crossing the road 45 m away. He immediately steps hard on the brakes to get the maximum acceleration of 7.5 m/square second. how far will he go before stopping? Will he hit the old woman? 3. the time a male bungee jumper if freely falling is 1.5 seconds (a) What is the velocity of the jumper at the end of 1.5 s? (b) how high did he fall? 4. A juggler tosses three balls alternately vertically upward. each ball has an initial velocity of 5
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Introduction: This lab is an experiment in terminal velocity‚ the speed an object cannot surpass due to frictional forces. To begin‚ it is important to note that the objects in this lab are not in a free-fall scenario. A free-fall scenario is a situation where an object is dropped in a frictionless environment‚ and the only force that is acting upon it is the force of gravity. In a free fall environment‚ terminal velocity would not occur‚ because no frictional forces would act on the object to
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30’+60’ = 90’=5400s=1.5h 40km+40km=80km vavg= 80000m/5400s=13.168724279835390946502057613169 m/s = 48 km/h 2. The coordinate of an object is given as a function of time by x = 7t – 3t2‚ where x is in meters and t is in seconds. Its average velocity over the interval from t = 0 to t = 2 s is: A) 5 m/s B) –5 m/s C) 11 m/s D) –11 m/s E) –14.5 m/s vt= 7-6t = 7-12=-5 m/s 3. The coordinate of a particle in meters is given by x(t) = 16t – 3.0t3‚ where the time t is in seconds. The
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same height‚ fall at the same velocity. Apparatus - 2 Marbles of different mass‚ one steel and one nylon - Dropping Mechanism with a lever to hold the marble and pull for drop - Bee Spi (measures velocity in kilometers per hour.) - Box to catch the marble on the way down Procedure The dropping mechanism was set up‚ with the BeeSpi attached to it at 26.5” from the lever that drops it so that the marble would fall through it‚ therefore recording the velocity in km/h. There was also a box
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the displacement y of the stone? | The stone‚ starting with zero velocity at the top of the building‚ is accelerated downward by gravity. | | Reasoning The upward direction is chosen as the positive direction. The initial velocity v0 of the stone is zero‚ because the stone is dropped from rest. The acceleration due to gravity is negative‚ since it points downward in the negative direction. Solution | 2). After 3.00 s of free-fall‚ what is the velocity v of the stone? Solution 1). A football game
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