solve k = 20.275 d) P ( 17 < X < 21) P ( (17 -18)/2.5 < Z < ( 21-18)/2.5) P ( -0.4 < Z < 1.2) = 0.8849 – 0.3446 = 0.5403 ( 4 decimal places) 4. In a sample of 25 observations from a Normal Distribution with mean 98.6 and standard deviation 17.2‚ find: Ans: a) n = 25‚ [pic] = ( = 98.6‚ [pic] = /n = 17.2/(25 = 3.44 [pic]( N
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SALES AND DISTRIBUTION MANAGEMENT ASSIGNMENT MORGAN & BOSS OFFICE EQUIPMENT DIVISION SUBMITTED BY ANGANA (F13005) ASHISH CHANDY (F13015) CHRISTINA IMMACULATE (F13021) DHANYA ANN ROY (F13025)
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Utilitarianism is a consequentialist theory‚ which means that it judges the morality of an action based on the consequences that follow from it rather than on external moral duties. Philosophers who adhere to utilitarianism regard the maximisation of utility as the key determent for understanding whether an action is right or not . In this essay I will argue that the amount of utility produces by an action is not an ideal way of determining its morality. This will be done by firstly clarifying the
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Determine two to three (2-3) methods of using stocks and options to create a risk-free hedge portfolio I found the research of this question to be extremely interesting. The simplest form of purchasing securities in order to reduce portfolio risk is hedging. These securities are intended to have negative correlation to the remainder of our portfolio so that it can help offset any other potential losses in our portfolio. We can hedge by buying a put option. We can buy stock with one put option with
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Assignment- 1 Evaluate and Determine Marketing Mix 1. Introduction about Braaap: At age 16 Smith had a vision to establish mini motocross Superlight MX in Australia. In 2004 he identified the need to develop an affordable Superlight pit bike which could be ridden and jumped confidently by adults. Evermore determined Smith set about designing his own bikes and researched the market extensively. He frequently travelled to mainland Australia where he participated in motocross events to build his
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Statistics MGSC-372 Review Normal Distribution The Normal Distribution aka The Gaussian Distribution The Normal Distribution y 1 f ( x) e 2 1 x 2 2 x Areas under the Normal Distribution curve -3 -2 - 68% 95% 99.7% + +2 +3 X = N( ‚ 2 ) Determining Normal Probabilities Since each pair of values for and represents a different distribution‚ there are an infinite number of possible normal distributions. The number of statistical tables
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CHARACTERISTICS OF SERVICES The services have unique characteristics which make them different from that of goods. The most common characteristics of services are: Intangibility. Inseparability. Perish ability. Variability Intangibility Services are activities performed by the provider‚ unlike physical products they cannot be seen‚ tasted‚ felt‚ heard or smelt before they are consumed. Since‚ services are not tangibles‚ they do not have features that appeal to the customer’s senses‚ their
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International Distribution Strategies Name: Institution: Date: Table of Contents 1.0 Introduction .................................................................................................................. 5 2.0 International distribution channels ................................................................................. 7 2.1 what is an international distribution channel of consumer goods? ............................... 8 2.2 The design
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Chapter 3: The Legal Aspects of Purchasing A need is requested by a specific department and the purchasing person satisfies the need. The potential source is evaluated in terms of quality‚ price‚ and delivery performance. The purchasing manager makes the purchase and the treasurer of the company sends the check after an invoice is received. However‚ the seller must know that the decision maker has given the purchasing manager the authority to make the purchase. This transaction is legally binding
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and used in the hydrolysis of glucose-6-phosphate (G6P). This catalyst the final step in glycogeneogeneis and glycogenolysis which is the key point of homeostatic regulating the blood glucose levels in our bodies. In the experiment‚ we will determine the activity of G6Pase. Frist‚ we will extract the G6Pase from pig liver sample. Then‚ we will assay for the liver G6Pase by enzymatic digestion and phosphate determination. Finally‚ we will measure the amount of protein present in the G6Pase by
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