technician services mailing machines at companies in the Phoenix area. Depending on the type of malfunction‚ the service call can take one‚ two‚ three‚ or four hours. The different types of malfunctions occur at about the same frequency. a. Develop a probability distribution for the duration of a service call Answer:
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is the probability that it will rain on the day of my daughter’s birthday party given the current weather forecast. The April average for total rainfall plus snowfall in Middletown‚ CT is eleven days( n.d.) An extended (10 day) weather forecast shows a 40% chance of rain on April 9‚ 2011 ( n.d.). According to the National Oceanic and Atmospheric Administration (NOAA)‚ the accuracy of 6-10 day precipitation forecasts for the continuous United States stands at 40%. Using probability statistical
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1 STAT 1770 MIDTERM-2 Date: March 19‚ 2010 Time: 12 30- 14 30 Instructions 1. This is a closed book exam. Name: _______________ I.D. #: _______________ 2. You are permitted to use a non programmable calculator approved by the instructor. 3. There are 31 multiple-choice questions in the part A of this exam. For each question exactly one of four answers provided is correct. For each multiple-choice question‚ circle one of the letters (a)-(d) corresponding to your chosen answer and record
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Strategies‚ Connecting‚ Representing‚ and Communicating. Unit 1 Unit 2 Unit 3 Unit 4 Unit 5 Counting and Probability Introducing probability vocabulary and notation in contexts involving simple counting Counting permutations and combinations Using mathematical notation to describe the number of permutations and combinations Solving counting problems Solving probability problems using counting principles Organization of Data for Analysis Connecting questions and the data needed to
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Shridharan PRACTICE PROBLEMS 1. (a) What is the probability that a leap year selected at random will contain 53 Tuesdays? (b) What is the probability that a leap year selected at random will contain 53 Sundays or 53 Mondays? 2. A bag contains 8 black‚ 3 red and 9 white balls. If 3 balls are drawn at random ‚ find the probability that (a) all are black‚ (b) 2 are black and 1 is white‚ (c) 1 of each colour‚ (d)
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Below shows the probabilities of obtaining at least three of a specific card for both pocket pairs and non pocket pairs. The calculations include anything at least trips (4ofAKind or FullHouse) and exclude community trips. Flushes and Straights are not taken into consideration. You can see that pocket pair hole cards have more than a 4x better chance of getting trips than non pocket pair hole cards. (C(n‚r) choose function) Pocket pair hole cards: 1 - [C(48‚5) / C(50‚5)] = 19.184%
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Angeline Foote 00215-‐0022 Mathematics SL Inter’l School of Tanganyika 2014 The Birthday Paradox: An Exploration of Probability Angeline Foote Candidate number: 00215-‐0022 Mathematics Standard Level Teacher: Mr. Michael Smith International School of Tanganyika 2014
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CASE STUDY: TEXAS HOLD’EM A. The probability that you are dealt pocket aces is 1/221‚ or 0.00452 to three significant digits. If you studied either Section 4.5 and 4.6 or Section 4.8‚ verify that probability. 1st Card- 4 cards that are aces out of the 52 cards in the deck. 2nd Card- You already got the 1st ace so now there’s only 3 aces out of 51 cards. 0.00452 is the probability of getting dealt "pocket aces". Therefore the probability is correct. B. Using the result from
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heads 4 times in a row. Let A represent the probability of rolling 4 heads. Therefor the probability of rolling a head four times is . b) There are 16 possible outcomes when tossing a coin 4 times. There are exactly 6 ways of tossing exactly 2 heads: Let A represent the probability of rolling exactly 2 heads. Therefor the probability of rolling exactly 2 heads is c) p’(rolling exactly 2 heads)=1-p(rolling exactly 2 heads) Therefor the probability of not rolling exactly 2 heads is 44.a)
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come up with an alternative course of action that will not just meet the required period‚ but will also take into consideration the total costs of the construction and will also satisfy the preference of Hill Construction regarding the minimum probability completion. III. POINT OF VIEW: The case was analyzed from the point of view of Bob Hill of Hill Construction. IV. AREAS OF CONSIDERATION: In analyzing the case‚ the following factors and concepts have been identified by the researchers to
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