squared deviations‚ (d) variance‚ and (e) standard deviation: 2‚ 2‚ 0‚ 5‚ 1‚ 4‚ 1‚ 3‚ 0‚ 0‚ 1‚ 4‚ 4‚ 0‚ 1‚ 4‚ 3‚ 4‚ 2‚ 1‚ 0 Answer: A) Mean = 2 B) Median = 2 C) Sum of squared deviations =-52 D). Variance = -2.47 E). Standard deviation = 1.57 12. For the following scores‚ find the (a) mean‚ (b) median‚ (c) sum of squared deviations‚ (d) variance‚ and (e) standard deviation: 1‚112; 1‚245; 1‚361; 1‚372; 1‚472 Answer: A) Mean = 1.361 B) Median = 1.3124 C) Sum of squared deviations = 0.07608920
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A business wants to estimate the true mean annual income of its customers. It randomly samples 220 of its customers. The mean annual income was $61‚400 with a standard deviation of $2‚200. Find a 95% confidence interval for the true mean annual income of the business’ customers. First we find E by doing Zc(standard deviation/square root of number of trials.) Now we add and subtract that number from the mean income to find both endpoints. The Zc of 95% is 1.96 so we would do 1.96((2200)/square
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c) Sum of square deviations is 56. d) Variance is 2.666 or 2.7 e) Standard deviation is 1.632 or 1.6 12. a) Mean is 1312.4 or 1312 b) Median is 1361 c) Sum of square deviations is 76092.2 d) Variance is 15218.44 e) Standard deviation is 123.363 13. a) Mean is 3.166 b) Median is 3.25 c) Sum of square deviations is 0.44738 d) Variance is 0.074 e) Standard deviation is 0.272 16. a) Governor-Mean is 43 and Standard deviation is 5.916 CEO- Mean
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caffeinated beverages consumed by Americans each day‚ based on data from the National Sleep Foundation. Determine whether or not the data represent a probability distribution. *If the data represent a probability distribution‚ find its mean and standard deviation. * If the data don’t represent a probability distribution‚ identify the requirement(s) for a probability distribution that is not satisfied. The data does not represent a probability distribution because all the probabilities are between
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statistics Mean: 2 Median: 2 sum of squared deviations: 56 Variance: 2.8 standard deviation: 1.67332 12. Calculate descriptive statistics Mean: 1‚112 the mean is 56.5; 1‚1245 the mean is 123; 1‚1361 the mean is 181; 1‚1372 the mean is 186.5; 1‚1472 the mean is 236.5 Median: 1‚112 the median is 56.5; 1‚1245 the median is 123; 1‚1361 the median is 181; 1‚372 the median is 186.5; 1‚1472 the median is 236.5 sum of squared deviations: 1‚112 is 6160.5; 1‚1245 is 29768; 1‚361 is 64800;
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291.00 up to $15‚906.00 for the period of the said year. Its average price is $6‚165.26 with a standard deviation of $2‚949.50. It can be seen that prices are not close by to one another. With regards to mileage‚ the majority of the automobiles runs 41 miles for every gallon of gasoline‚ while the least runs only for 12 miles. The mean of mileage has resulted to 21.30 mpg‚ with a standard deviation of 5.79 mpg. As to the variable repair record it can be seen that only 69 were observed out of the 74
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Recession 0.1 5.5% -27.0% 27% 6% -17% 0% Below Average 0.2 5.5% -7% 13% -14% -3% Average 0.4 5.5% 15% 0 3% 10% 7.50% Above Average 0.2 5.5% 30% -11% 41% 25% Boom 0.1 5.5% 45% -21% 26% 38% 12% r(hat) - expected return 1.00% 9.80% 10.50% σ (std deviation) 0.0% 13.20% 18.80% 15.20% 3.40% CV 13.20% 1.90% 1.4% 0.50% beta -0.87% 88.00% CDIB’s economic forecasting staff has developed probability estimates for the state of the economy; and its security analysts have developed a sophisticated
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measure is the standard deviation. Standard Deviation: It is a measure of the values of the variables around its mean or it is the square root of the sum of the squared deviations from the mean divided by the number of observances. The arithmetic mean of the returns may be same for two companies but the returns may vary widely. This can be illustrated with an example. Now let us take two companies A and B to calculate the expected returns. COMPANY A standard deviation is affected by the association
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standard deviation of the probability distribution created by rolling a die. Either show work or explain how your answer was calculated. Descriptive Statistics: Die1 Variable Mean StDevDie1 3.450 1.317Mean: 3.50 Standard deviation: 1.317Calculations were derived by using the minitab and going into the Stat > Basic Statistics > Display Descriptive Statistics > Variables than select the C14 (Die1) > below enter the statistics and check mark only mean and standard deviation >
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whether the process is operating satisfactorily or corrective actions needs to be taken. Summary of Statistics Sample 1 Sample 2 Sample 3 Sample 4 Mean 11.96 12.10 12.14 12.15 Standard Error 0.04 0.04 0.04 0.02 Standard Deviation 0.22 0.23 0.23 0.16 Sample Variance 0.05 0.05 0.05 0.03 Sum 358.69 362.90 364.08 364.46 From the summary of statistics we can see that mean has an upward trend. Mean value differ from sample to sample. Here we can observe that mean
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