SUBJECT: CLINICAL CHEMISTRY TITLE: TOTAL BILIRUBIN & DIRECT BILIRUBIN LABORATORY: 19 & 20 INTENDED USE: 1. For the quantitative determination of total bilirubin in serum 2. For the quantitative determination of direct bilirubin in serum INTRODUCTION: One part of bile is a yellow (or brownish) substance called bilirubin. Bilirubin starts out as a product of the breakdown of red blood cells. When red blood cells break down‚ the heme molecule is converted into bilirubin
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attacked. Before we dive into the details of the reaction occurring in scheme 2 it will be important to understand the mechanism which I will provide below: The reason that no base is needed in scheme 2 is due to the two ester groups present in Maleate. Upon the initial attack of PBu3 we see that electrons are pushed onto what was originally one of the double bonded oxygen’s. In the next step‚ the electrons on the oxygen can be pushed down via resonance which causes the carbon-carbon double bond
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isn’t possible‚ we could take public transit. Still‚ if someone is unsatisfied with these options‚ we could try buying a hybrid or electrically run car. (If we had the money) 20. 21. a) 1-ethyl – 3-methylcyclopentane b) 4‚4-dimethyl-2-pentyne c) trans-3-heptene 22. To determine whether an organic unlabelled liquid is saturated or unsaturated is by dropping a small amount of iodine tincture in the liquids. Should the iodine color dissolve‚ then a reaction has taken place
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D.W.H.; Cradock‚ S.‚ Structural Methods in Inorganic Chemistry‚ Blackwell: Oxford‚ 1987 Pike‚ M Ronald; Singh‚ M Mono; Szafran Zvi. Microscale Inorganic Chemistry; A Comprehensive Laboratory Experience. New York 1991‚ p218-222. Reynolds‚ W. R‚ “Dimethyl Sulfoxide in Inorganic Chemistry” in Progress in Inorganic Chemistry‚ S. J. Lippard‚ Ed.‚ Interscience: New York‚ 1970‚ Vol 12‚ p. 1.
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UNIVERSITI TEKNOLOGI MARA COURSE INFORMATION Confidential Code Course Level Credit Hours Contact Hours : : : : : CHM 556 Organic Chemistry II Degree 4 3 hr (Lecture) 3 hr (Practical) 3 Core CHM 456 Part Course Status Pre-requisite : : : Course Outcomes : Upon completion of this course‚ students should be able to: 1. Determine functional groups present in organic compounds using Infrared Spectroscopy and interpret Nuclear Magnetic Resonance spectra and relate the information to structural
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Chapter 1 MULTIPLE CHOICE QUESTIONS Topic: Atomic Orbitals 1. A) B) C) D) E) In quantum mechanics a node (nodal surface or plane) is: a place where Ψ is negative. a place where Ψ is positive. a place where Ψ = 0. a place where Ψ2 is large. a place where Ψ2 is negative. Ans: C Topic: Atomic Orbitals‚ Molecular Orbitals 2. When the 1s orbitals of two hydrogen atoms combine to form a hydrogen molecule‚ how many molecular orbitals are formed? A) 1 B) 2 C) 3 D) 4 E) 5 Ans:
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SCH 4U1 FINAL EXAM REVIEW ATOMIC STRUCTURE AND MOLECULAR ARCHITECTURE 1. Describe the wave mechanical model of the atom. 2. Write the ground state electron configuration for Br. 3. Explain why the first ionization energy for Ne is significantly greater than Na. 4. Distinguish between ionization energy and electronegativity. 5. How does VSEPR Theory account for the fact that the bond angle in H2O is less than NH3? 6. Which of the following molecules are polar? Include diagrams
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Disinfectants Broad-spectrum microbicide for topical use in wounds‚ cuts‚ abrasions‚ burns; pre- & post-op disinfections. Prevention of infection in burns‚ laceration‚ cuts & abrasions‚ common skin infection 8. BIOFLU PHENYLEPHRINE HCl CHLOROPHENAMINE MALEATE PARACETAMOL Cough & Cold Preparations Relief of clogged nose‚ runny nose‚ postnasal drip‚ sneezing‚ headache‚ body aches & fever associated w/ common cold‚ allergic rhinitis‚ sinusitis‚ flu & other minor resp tract infections 9. BIOGESIC PARACETAMOL
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Carbon is denoted by the symbol C‚ is part of group 14 on the periodic table‚ and is the fourth most abundant element in the universe (by mass). Carbon has an electron configuration of 1s2‚ 2s2‚ 2p2. With 4 valance shell electrons it is expected to form 4 bonds‚ this means carbon is tetravalent. However the s orbitals do not form the same type of bond (with other atoms) as the p orbitals‚ this is because their shapes are different. For example CH4 would have the following bonds: C(s)-H(s)‚ C(s)-H(s)
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CHEMISTRY OF NATURAL PRODUCTS Terpenoids Sameena Bano Department of Chemistry Faculty of Science Jamia Hamdard New Delhi-110062 (24.09.2007) CONTENTS Introduction Classification of Terpenoids Isolation of mono and sesquiterpenoids General properties of Terpenoids General methods of structure elucidation Terpenoids Citral Menthol Camphor Eugenol Keywords Terpenes‚ isoprene‚ citral‚ menthol‚ camphor and eugenol 1 Introduction There are many different classes of naturally occurring
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