when combined with hydrogen peroxide? Aim: To see find out how the amount of catalase correlates with the amount of gas created when in combination with hydrogen peroxide. Materials: 15g of liver 25 ml of hydrogen peroxide 1 scale 1 bucket 1 100ml graduated cylinder 1 250ml flask with bung 1 50cm tube (able to fix onto top of flask) 1 stopwatch 1 100ml beaker 1 funnel 1 pipette 1 microscopy kit Variables: Independent: This is the amount of liver added to the hydrogen peroxide. The initial weight
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First recognized as a chemical compound in 1818‚ hydrogen peroxide is a clear‚ colorless liquid most often used for cleaning or disinfecting(Britannica‚ 2013). Since pure hydrogen peroxide is unstable‚ it is found in stores as an aqueous solution. The chemical formula for hydrogen peroxide is H₂O₂ which means there are two hydrogen atoms and two oxygen atoms in the compound(Liebeskind‚ 2013). Seed germination is simply the process in which a seedling sprouts from a seed and begins it’s growth. The
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Determination of the Enthalpy for Decomposition of Hydrogen Peroxide Objective: To construct a coffee cup calorimeter‚ measure its calorimeter constant‚ and determine the enthalpy of decomposition and formation of hydrogen peroxide. Background: This experiment is a classic thermodynamics lab. In it‚ we attempt to measure the enthalpy (H) of a chemical reaction. The main obstacle is that this is a quantity that cannot be measured directly. It instead is observed as heat from one substance is transferred
Free Thermodynamics Energy Hydrogen peroxide
Chemistry Catalyst Report Aim I am trying to investigate the effect of the mass of magnesium dioxide used on the speed of the reaction of 2H2O2(aq) 2H2O(l) + O2(g). I hypothesize that the speed of the reaction is proportional to the rate of decomposition. Independent Variable The mass of MnO2 used Dependent Variable The rate of decomposition through the amount of mass lost Controlled Variables Environment of the experiment Stay in the same place to carry out the experiment and finish the
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See What Factors Affect The Decomposition Of Hydrogen Peroxide By The Enzyme Catalase Which Is Found In The Liver" Introduction: Enzymes are biological catalysts. They speed up the chemical reactions which go on inside living things. Without them the reactions would be so slow that life would grind to a halt. Enzymes work by when a substrate molecule bumps into a molecule of the right enzyme‚ it fits into a depression on the surface of the enzyme molecule. This depression is called the active
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between volume of oxygen and the increase of hydrogen peroxide; as the amount of substrate increases‚ the more oxygen is produced from the enzymatic reaction of hydrogen peroxide. For example‚ when five drops of hydrogen peroxide was added‚ it can be seen that 16.2mL of oxygen collected in the gas syringe‚ whilst when 15 drops were added‚ 96.4mL of oxygen was indicated‚ strongly supporting the original hypothesis‚ which was that as more hydrogen peroxide was added to the yeast‚ the higher the rate
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rate of enzyme activity Enzymes speed up reactions. They have an area with a very particular shape called the ‘active site’. When the right molecule comes along (substrate molecule) it will fit perfectly into the active site and there will be a reaction. After the reaction the products then leave the active site. This process is often referred to as the lock and key theory as only one enzyme can carry out one type of reaction. The catalase enzyme speeds up the breakdown of hydrogen peroxide into
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Introduction: This experiment will investigate the factors that affect the rate of reaction of the enzyme catalyse‚ an enzyme found in food such as potato and liver. Catalyse is used to remove hydrogen peroxide from cells. The enzyme speeds up the rate of decomposition of hydrogen peroxide into water and oxygen. The reaction is: Catalyse is able to speed up the process because the enzyme lowers the activation energy of the reaction. This means that the free energy required for the reaction
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For many reactions involving liquids or gases‚ increasing the concentration of the reactants increases the rate of reaction. In a few cases‚ increasing the concentration of one of the reactants may have little noticeable effect of the rate. These cases are discussed and explained further down this page. Don’t assume that if you double the concentration of one of the reactants that you will double the rate of the reaction. It may happen like that‚ but the relationship may well be more complicated
Free Chemical reaction Chemical kinetics Reaction rate
this experiment was to determine the speed at which a reaction took place between an iodine and hydrogen peroxide solution. In addition to a change in concentration‚ a change in temperature and a catalyst variable was also introduced to conclude whether or not their presence affected the overall speed of the reaction. In order to determine the effects of these variables‚ several iodine and hydrogen peroxide reactions were prepared‚ (all at varying temperatures‚ volumes‚ and concentrations)‚ and reacted
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