mutually exclusive? a) PP (x) = 2 (năm 2 đã gần hoàn vốn) + (10000-6500-3000)/3000(se tra trong năm 3 nên chỉ cần tính them thời gian hoàn vốn năm 3) = 2.17 PP (y) = 2 + (10000-3500-3500)/3500 = 2.86 NPV(x) = -10‚000 + 6‚500/(1+0.12) + 3000/(1+0.12)^2 + 3000/(1+0.12)^3+ 1000/(1+0.12)^4 = 966 NPV(y) = -10000 + 3‚500/(1+0.12) + 3500/(1+0.12)^2 + 3500/(1+0.12)^3+ 3500/(1+0.12)^4 = 631 IRR (x) = 6‚500/(1+IRR) + 3000/(1+IRR)^2 + 3000/(1+IRR)^3+ 1000/(1+IRR)^4 – 10000 = 0 IRR (x) = 18% IRR (y) = 3‚500/(1+IRR)
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| COST ACCOUNTING APPLICATION ON EXPANSION OF BHATTI CLINIC AND BALANCED SCORE CARD APPLICATION | | | | | 5/21/2012 | GROUP NUMERICS TABLE OF CONTENTS INTRODUCTION 1 DR. ZAHID ISHAQ 1 SERVICES DELIVERED 1 STAFF AT CLINIC 1 INCOME STATEMENT EXPLANATION 1 REVENUE 1 COST OF SALES 2 EXPENSES 2 EXPANSION OF CURRENT BUSINESS 2 ASSUMPTIONS 3 DECISION FOR EXPANSION 4 BREAK EVEN ANALYSIS 4 MARGIN OF SAFETY 5 PORTER’S FIVE FORCES MODEL 6 Threat of Substitutes:
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destination pairing). Min: 12x11 + 6x12 + 5x13 + 20x21 + 11x22 + 9x23 + 30x31 + 26x32 + 28x33 3. Define the Constraints Equal use of transportation modes: (1) x11 + x12 + x13 = 3000 (2) x21 + x22 + x23 = 3000 (3) x31 + x32 + x33 = 3000 Destination material requirements: (4) x11 + x21 + x31 = 4000 (5) x12 + x22 + x32 = 2500
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000. The motorcycle plant assembles and sells 3000 motorcycles a year. Each engine costs $500‚ and Harley incurs uses holding cost of 20 percent. a) How many engines should Harley load onto each truck (i.e. what is the optimal order quantity)? D = 3‚000 S = 1‚000 C = 500 h = 0.2 Q* = SQRT((2DS)/(hC)) = SQRT((2*3000*1000)/(0.2*500)) = SQRT(6000000/100) = 244.979 b) What is the corresponding optimal order frequency? n* = D/Q* = 3000/244.979 = 12.247 c) What is the cycle inventory
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to an overall maximum of 3000 words in total). Supporting documentation is required to be produced as an individual contribution to the assessment (equivalent to an overall maximum of 3000 words in total) --------------------------------------------------------------------------------------------------- Maximum Word Limit and Assessment weighting for each aspect within the assessment: • Group Presentation: maximum 15 Power Point Slides (deemed to be equivalent to 3000 words): Assessment Weighting
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1- Explain the collecting‚ recording‚ classifying‚ summarizing‚ analyzing and reporting process of accounting. - Collecting:- Data obtained from various sources with the help of appropriate measures is called collection of data. - Recording:- Arranging the data into its chronological form is called recording of data. - Classifying:- Division of data according to nature of events is called classification of data. - Ledger is used for classifying transactions - Posting
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10MG TABLET CLAROCIN TABLET 500 MG 3000 5000 3000 2000 3000 1000 @ 32.00 @ 42.00 @ 65.00 @ 30.00 @ 50.00 @ 140.00 = 96‚000.00 = 210‚000.00 = 195‚000.00 = 60‚000.00 = 150‚000.00 = 140‚000.00 0000327 851‚000.00 (1‚145‚560.00) 16/08/14 SALES. SV/140805 BUILTY NO QPA 9532 EVAXOSURE 500 MG MIOSIL 5MG TABLET PINSURE 5 MG TABLET ROSIDEN 20MG CAPSULE ROSIDEN 20MG GEL (20GM) SULVO 25 MG 5000 3455 2995 1000 1000 3000 @ 45.00 @ 28.00 @ 13.00 @ 150
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Karynn Ortiz Week 2 HW Chapter 3. Problem 2 Consider an economy in which taxes‚ planned investment‚ government spending on goods and services‚ and net exports are autonomous‚ but consumption and planned investment change as the interest rate changes. You are given the following information concerning autonomous consumption‚ the magical propensity to consume‚ planned investment‚ government purchases and goods and services‚ and net exports. Ca =1500-10r c=0.6 T=1800 Ip=2400-50r G=2000
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Accounting 260 Major assignment Kowloon Tong ltd- Jordan ltd 1. Acquisition analysis at 1 July 2008 Net fair value of identifiable assets and liabilities of Jordan ltd = 60000 +30000 +21000+6000 +6000(1-30%) Inventory +1000(1-30%) Machinery +6000(1-30%) Land +8000(1-30%) Equipment
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<=5000 | 4 | Model 102 Assembly | 3Y <=4500 | 5 | Min no | X >= 0 | 6 | Min no | Y >=0 | Solving for C with above constraints‚ we get : X = 2000 and Y = 1000 Corresponding C will be : 2000(3000) + 5000(1000) = $ 1100000 So best product mix is manufacturing of 2000 Model 101 truck and 1000 Model 102 truck. Sol 1.B : Changing Engine Assembly capacity from 4000 to 4001 : X + 2Y <= 4001 Solving for C with new constraints
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