Chemistry Catalyst Report Aim I am trying to investigate the effect of the mass of magnesium dioxide used on the speed of the reaction of 2H2O2(aq) 2H2O(l) + O2(g). I hypothesize that the speed of the reaction is proportional to the rate of decomposition. Independent Variable The mass of MnO2 used Dependent Variable The rate of decomposition through the amount of mass lost Controlled Variables Environment of the experiment Stay in the same place to carry out the experiment and finish the
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Module name: Physical Chemistry (CP 4117) Experiment: Heat of decomposition of hydrogen peroxide Lecturer: Dr Cheow Name: Loganathan Admin number: 1246102 Contents No. | Contents | Page | 1 | Abstract – a precise summary about the whole experiment and report. | 3 | 2 | Introduction to the experiment - a brief outline and relevant theory for the experiment and calculation | 3-4 | 3 | Procedure for the experiment
Free Thermodynamics Enthalpy Temperature
Factors affecting the catalytic decomposition of Hydrogen peroxide Please refer to the additional files for tables/graphs. Aim- The purpose of this investigation is to investigate how certain factors affect the catalytic decomposition of Hydrogen peroxide. I will investigate the effect of altering the mass of catalyst used on the rate of the decomposition of Hydrogen peroxide. Introduction- The decomposition of Hydrogen peroxide is a process by which Hydrogen peroxide decomposes into water and Oxygen
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Determination of the Enthalpy for Decomposition of Hydrogen Peroxide Objective: To construct a coffee cup calorimeter‚ measure its calorimeter constant‚ and determine the enthalpy of decomposition and formation of hydrogen peroxide. Background: This experiment is a classic thermodynamics lab. In it‚ we attempt to measure the enthalpy (H) of a chemical reaction. The main obstacle is that this is a quantity that cannot be measured directly. It instead is observed as heat from one substance is transferred
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Hydrogen Peroxide & Inorganic Peroxy Compounds Hydrogen Peroxide Hydrogen peroxide (H2O2) is the simplest peroxide (a compound with an oxygen-oxygen single bond). It is also a strong oxidizer. Hydrogen peroxide is a clear liquid‚ slightly more viscous than water. In dilute solution‚ it appears colorless. Reactions Decomposition Hydrogen peroxide decomposes exothermically into water and oxygen gas spontaneously: 2 H2O2 → 2 H2O + O2 This process is thermodynamically favorable. It has
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Catalytic Decomposition of Hydrogen Peroxide by Potassium Iodide Brief Description: Two solutions are mixed resulting in an eruption of foam resembling a huge stream of toothpaste. This is the classic “Elephant Toothpaste” reaction. Purpose/Goal: Procedure presents an example of a catalyzed reaction. Explanation of Experiment: The rapid evolution of oxygen gas is produced by the following reaction: 2 H2O2 (aq) = 2 H2O (l) + O2 (g) + heat The decomposition of hydrogen peroxide in the
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Introduction: This experiment will investigate the factors that affect the rate of reaction of the enzyme catalyse‚ an enzyme found in food such as potato and liver. Catalyse is used to remove hydrogen peroxide from cells. The enzyme speeds up the rate of decomposition of hydrogen peroxide into water and oxygen. The reaction is: Catalyse is able to speed up the process because the enzyme lowers the activation energy of the reaction. This means that the free energy required for the reaction
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goggles and an apron or lab coat to protect our eyes and clothes. As we are using enzymes and Hydrogen Peroxide we need to be extra careful‚ ensuring they don’t come into contact with our eyes‚ skin or clothes. Catalyse is an enzyme found in all living cells. It makes Hydrogen Peroxide decompose into water and Oxygen. We will be measuring the amount of Oxygen released from the Hydrogen Peroxide. In order to do this we will use a measuring cylinder. This piece of apparatus measures the
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THE EFFECT OF CATALASE ON HYDROGEN PEROXIDE The aim of the experiments is to see if increasing the surface area of the enzyme Catalase‚ affects the relative activity of the substrate Hydrogen peroxide. Then to observe and measure the effect the Catalase has on the chemical breakdown of the hydrogen peroxide. My theory is if you keep increasing the surface area of Catalase‚ the more active sites are available to join with the substrate causing an increase in the breakdown of the hydrogen peroxide
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"To See What Factors Affect The Decomposition Of Hydrogen Peroxide By The Enzyme Catalase Which Is Found In The Liver" Introduction: Enzymes are biological catalysts. They speed up the chemical reactions which go on inside living things. Without them the reactions would be so slow that life would grind to a halt. Enzymes work by when a substrate molecule bumps into a molecule of the right enzyme‚ it fits into a depression on the surface of the enzyme molecule. This depression is called the
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