Sean Dowling Julia Phaltankar Mrs. Oakes Chemistry w/ Algebra 10/G February 18‚ 2015 Determining Empirical Formula Lab Introduction: One can find an empirical formula by taking a sample of a compound and dividing the number of moles of one element in the compound by the number of moles of another element in the compound to form a small wholenumber formula. For example‚ in a sample of a made up compound of oxygen and lead‚ one mole of lead has a molar mass of 207.2 g/mole‚ and oxygen
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Lab of Determining an Empirical Formula B2 Honors 12/18/13 Abstract In this lab‚ to help better understand the concepts of gram atomic masses and empirical formulas‚ we found the gram atomic masses and empirical formula of a binary compound. The two compounds should form a definite whole number ratio by mass. This ratio will also help determine the subscripts of the elements in the empirical formula. Errors in this experiment can stem from measuring wrong or doing equations incorrectly.
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The Synthesis and Determination of Empirical Formula for Magnesium Oxide Aim: To determine the empirical formula for magnesium oxide. Data Collection: Table 1 Mass of empty crucible‚ crucible + Mg (roughly 1cm pieces of a 15-cm piece of magnesium ribbon)‚ and crucible +MgxOy. (mass measured with an analytical balance). The mass of crucible + MgxOy was obtained after a continuous process of heating‚ letting cool‚ heating with water enough to immerse the content and letting cool of the Mg. Mass
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Experiment 9 Empirical Formula of Zinc Iodide Objectives Upon completion of this experiment‚ students should have learned: 1. The law of conservation of mass. 2. How to calculate an empirical formula. 3. The concept of limiting reagents. Introduction Synthesis and the determination of empirical formulas are two extremely important parts of chemistry. In this experiment‚ you will synthesize zinc iodide and determine its empirical formula. The molecular formula gives the actual
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LEARNING TASK NO. 4B Composition Stoichiometry Problems Mole Relationship from Chemical Formulas: a) Determine the number of moles of chloride ions in 2.53 mol ZnCl2. b) Calculate the number of moles of each element in 1.25 mol glucose (C6H12O6). c) How many molecules of oxygen atoms are present in 5.00 mol diphosphorus pentoxide? d) Calculate the number of moles of hydrogen atoms in 11.5 mol water. e) A sample of ethanol (C2H5OH) has a mass of 45.6 g.How many carbon atoms does the sample
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CHEMISTRY EXPERIMENTAL REPORT SALLY LI INTRODUCTION: In chemistry‚ compounds can be distinguished by using the empirical formula. The formula provides the simplest positive integer ratio of elements in a compound. The empirical formula is largely useful in determining the ratio of elements within ionic compounds where the structure is of a non-directional nature of bonding where any ion at any time could be surrounded by
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Steven Leung 9/19/06 Lab Report The Empirical Formula of a Copper Oxide Purpose: To convert an unknown copper oxide to copper (Cu) metal using natural gas to provide a reducing environment as shown below: Cu O (s) + CH (g) ¨ Cu (s) + Co (g) + H O (g) From the mass difference between the unknown copper oxide and the Cu metal generated at the completion of the reaction and the molar mass of Cu and oxygen‚ the empirical formula of the original copper oxide can be calculated. Materials:
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structure is derived. Firstly it is important to determine the percentage composition of elements to work out the empirical formula. The empirical formula was found to be C10H12O and the mass of the unknown was 148.09 m/z which when calculating the molecular weight of the empirical formula it did equal 148.09 g mol -1. This means that the empirical formula is also the molecular formula. As 12.01x10 carbons +1.008x12 hydrogens + 16= 148.09 09 g mol -1. From this knowledge the unknown molecule must
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A) January 18‚ 2011B) Empirical Formula C) The purpose is to determine the empirical formula of a metallic oxide. D) Pre Lab Questions: After heating the metal‚ the crucible and contents should mass less than it did before it was heated. This is because heating the crucible may rid of other residue that was left in it; bringing it a to a constant mass. A yellow flame will deposit soot on the crucible. This would be a problem because the soot left on the crucible would vary from our constant
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Determination of the Formula of Magnesium Oxide. Introduction: Magnesium is a mental‚ it is known to react with oxygen. Magnesium reacts vigorously when heated in the presence of air‚ which is why we have chosen high heat in our method to facilitate combustion. This oxidation reaction produces magnesium oxide gaining oxygen from the air. When sharing of electrons occur a chemical bond is made and the atoms combine to form a molecule. So‚ the predicted molecular formula: Mg + O2--------->
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