Matthew Saldanha Bio DCP lab-Catalase experiment Aim: To investigate enzyme kinetics‚ using different concentration of the enzyme. Hypothesis: The assay system used in the lab consists of a filter paper disc coated with the enzyme and the dropped into a papercup of substrate (Hydrogen Peroxide). As the hydrogen breaks down the hydrogen peroxide into hydrogen and oxygen gas‚ the bubbles of oxygen gas collect underneath the filter and make it
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Experiment 4: Enzyme Kinetics. Results/Discussion Week 1 Part A: Table 1. Enzyme activity for each assay of 4-nitroaniline formation. Rate of 4-nitroaniline formation Name of trial Abs/sec Abs/min M/min mol/min µmol/min #1 0.00003 0.0018 2.05x10-7 2.15 x10-10 2.15 x10-4 # 2 0.00010 0.0060 6.81x10-7 7.15x10-10 7.15x10-4 # 3 0.00020 0.0120 1.36x10-6 1.43x10-9 1.43x10-3 # 4 0.00030 0.0180 2.00x10-6 2.10x10-9 2.10x10-3
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Enzyme Kinetics Marcos‚ Nelissa S. Institute of Chemistry‚ University of the Philippines‚ Diliman‚ Quezon City 1101 Philippines ABSTRACT The rationale of the experiment is basically founded in the concept of reaction rates as affected by enzyme‚ and how the enzyme works is competed by a competitive inhibitor‚ thereby impeding the forward reaction. In this experiment‚ o-diphenol oxidase‚ an enzyme that causes the browning in fruits‚ was extracted from banana and reaction rate of this was established
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Enzymes are naturally occurring biological catalysts that are extremely efficient and specific. Enzymes accelerate the rate of a reaction by factors of at least a million as compared to the same reaction without the enzyme. Most biological reaction rates are not perceivable in the absence of the enzyme. The term enzyme was first used by a German pshysiologist Wilhelm Kühne in 1897. There are over 700 different kinds of enzymes that have been identified. Enzymes can be classified into several categories
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BIOCHEMISTRY 304 Enzyme Kinetic Sample Problems #1 September 2004 1 Given the reaction k1 kp E + S ES E + P k-1 where k1 = 1 x 107 M-1 sec-1 k-1 = 1 x 102 sec-1‚ and kp = 3 x 102 sec-1 a) Calculate Ks b) Calculate Km (a) k-1 1 x 102 sec-1 Ks = k1 = 1 x 107 M-1 sec-1 = 1 x 10-5 M (b) k-1 + kp (1 x 102 sec-1) + (3 x 102 sec-1)
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Lecture 3: Enzyme kinetics Tue 17 Jan 2006 with the collaboration of Luna De Ferrari 1 Images from: D. L. Nelson‚ Lehninger Principles of Biochemistry‚ IV Edition‚ W. H. Freeman ed. A. Cornish-Bowden Fundamentals of Enzyme Kinetics‚ Portland Press‚ 2004 A. Cornish-Bowden Enzyme Kinetics‚ IRL Press‚ 1988 Computational Systems Biology Summary: • • • • • • 2 Simple enzyme kinetics Steady-state rate equations Reactions of two substrates Inhibition of enzyme activity pH
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Ah Seung Chong Molecular Biology CTW: Enzyme Kinetic Dr. Cruz 07/22/2010 Enzyme kinetics Introduction Enzymes are biological catalysts or assistants‚ without enzyme many of important processes of life could not happen. Most of enzymes are proteins that help speed up chemical reactions by lowering amount of activation energy needed for the reaction1. Enzymes are usually highly selective‚ only bind to specific substrate and convert it to product at a particular rate1. The rate of the reaction
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Lab: Tuesdays at 1pm Enzyme Kinetics Lab Introduction: Enzymes are proteins that will catalyze reactions to make the rate of the reaction occur faster than it would without. It can also make the reaction occur in the first place. Tyrosinase is an enzyme that has a variety of functions and activities. It produces pigments like melanin and others that would be apparent when a fruit is cut in half and it browns. (Bien-etre 3).There is that one function that stands out and the enzyme is continuously studied
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Abstract The main goal of the enzyme kinetics experiment was to see how the phosphatase-catalyzed hydrolysis of p-nitrophenyl produced p-nitrophenol in the presence of phosphate and fluoride ion inhibitors of various concentrations. The calculated Km constant was found to be 0.22 for all reactions. The Vmax values for each inhibition ion were 0.00986 for the phosphate ion and 0.00436 for the fluoride ion. The inhibitor constant‚ Ki‚ was determined to be 0.0967 for the phosphate ion. The inhibitor
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Enzyme Kinetics Examples and Problems 1. An enzyme is produced for producing a sun protection lotion. Given kinetic data for the enzyme reaction with Vm=2.5 mmol/m3.s‚ Km=8.9 mM and So=12mM‚ what would be the time required for 95% conversion in a batch reactor? 2. An enzyme was assayed at an initial substrate concentration of 10-5M. The Km’ for the substrate is 2x10-3M. At the end of 1 min‚ 2% of the substrate had been converted to product. a. What % of the substrate will be converted
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