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    Solubility Equilibrium

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    Title: Study of Solubility Equilibrium Abstract The effect of temperature on the solubility product constant‚ Ksp‚ of potassium hydrogen tartrate in water was investigated in the temperature range of 285K to 318K at normal atmospheric pressure. It was found that the solubility of potassium hydrogen tartrate decreases with a decrease in temperature and consequently a smaller volume of sodium hydroxide is needed to neutralize it. The molar solubility of potassium hydrogen tartrate was calculated

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    Equilibrium Experiment

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    Experiment 5: Shifting Equilibrium A solution is in equilibrium when the rate of forward reaction and the rate of reverse reaction are equal. This equilibrium may be disturbed when the concentration of the reactants‚ the concentration of the products or the temperature is changed. If the process involves gases‚ a change in pressure can also affect the position of equilibrium. The concept behind this is Le Chatelier ’s Principle which states that when a system is disturbed through application

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    07.04 Equilibrium: Lab Report Equilibrium Lab Report Before You Begin: You may either copy and paste this document into a word processing program of your choice or print this page. Data and Observations: Insert data tables for each part of the lab (Part I‚ Part II‚ and Part III). Part I Round Reactants Products 1 25 15 2 19 21 3 17 23 4 16 24 5 16 24 6 16 24 7 16 24 8 16 24 9 16 24 10 16 24 25+19+17+16(7)=173 15+21+23+24(7)=227 Product/Reactants==227/213=1

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    CH 127 – Chem 2 Lab Determination of an Equilibrium constant Goals The purpose of this experiment is to determine the equilibrium constant for the reaction Fe3+(aq) + HSCN(aq) –>FeSCN2+(aq) + H+(aq). The equilibrium constant expression Kc for Reaction is kc=FeSCN2+[H+]Fe3++[HSCN] Procedure *Preparation of the Beer’s law plot Prepare five solutions of FeSCN2+(aq) of known concentrations between 1x10-5M and 1x10-4M by diluting various volumes of 4.62x10-4 HSCN. Calculate the Final concentration

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    Determination of an Equilibrium Constant Abstract: In this experiment‚ two reactions were run to determine the molar absorptivity and the equilibrium constant of FeSCN2+. The main principles used in this lab are equilibrium‚ LeChatlier’s Principle‚ Beer’s Law and Spectrocopy. The first reaction was run to completion using LeChatier’s Principle and the second reaction was run to equilibrium. A spectrophotometer was used to measure absorbances. Using a graph of absorbance versus concentration

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    Rdr4 Chemical Equilibrium

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    bDATES PERFORMED: JANUARY 8‚ 2013 CHEMICAL EQUILIBRIUM D.M. TAN1 AND P.B. ALEGRO2 1DEPARTMENT OF MINING‚ METALLURGICAL‚ AND MATERIALS ENGINEERING‚ COLLEGE OF ENGINEERING 2 INSTITUTE OF CHEMISTRY‚ COLLEGE OF SCIENCE UNIVERSITY OF THE PHILIPPINES‚ DILIMAN QUEZON CITY‚ PHILIPPINES RECEIVED JANUARY 15‚ 2013 RESULTS AND DISCUSSION A. Iron- Silver Equilibrium The first part of the experimentation focuses in the iron-silver system. Silver nitrate (AgNO3) was added to ferrous

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    ceiling create shortage. How to overcome it? According to the book “Economic Theory in the Malaysian Context”‚ the definition of price ceiling is a legally established maximum price a seller can charge. It means that the price is lower than the equilibrium market price and it cannot go above the ceiling price. The reason that government imposes ceiling price on item such as beef‚ flour‚ sugar and many more is because to ensure that consumers are able to buy these goods at a reasonable price thus prevent

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    chemical equilibrium is already achieved. A reaction is said to be at equilibrium when the following conditions exist. 1. 2. 3. Several factors such as temperature‚ concentration and pressure affects the rate of reaction which can cause an effect in the chemical equilibrium. A general rule is used to predict the direction in which an equilibrium reaction will move which is called the Le Chatelier’s Principle. It states that if an external stress is applied to a system at equilibrium‚ the system

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    Discovering the equilibrium constant for a reaction is very helpful for understanding that reaction. Knowing the equilibrium constant of a reaction is important because it allows you to calculate how much product will ultimately be formed during a reaction. Moreover‚ it also tells you how a particular mixture of chemicals will react. This is because chemical reactions always occur in the direction which will make the ratio of their products to reactants equal to the equilibrium constant.

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    Experiment 1: Study of Solubility Equilibrium Data Treatment and Analysis Section 1: Solubility Product Constant Temperature (˚C) | Volume of NaOH used (mL) |   | |   | Titration 1 | Titration 2 | Average | 28 | 12.7 | 12.8 | 12.75 | 9 | 10.5 | 10.5 | 10.5 | 19 | 11.3 | 11.2 | 11.25 | 40 | 16.2 | 16.2 | 16.2 | 50 | 22.8 | 22.9 | 22.85 | Table 1: The volume of NaOH used in the titration at various temperatures. No. of moles of KHC4H4O6 = 1.45 g ÷ 188.177g/mol = 7.71 x 10-3mol

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