CSEC 630 – Lab Assignment Q1. Which tool or technique from the above list would be most effective for a cryptanalyst to use to decipher a text encrypted with the Caesar cipher‚ and why? Floating frequency is the most effective tool used to decipher a text encrypted with the Caesar cipher. Floating frequency replace one letter of the plaintext with another to produce the cypher text‚ and any particular letter in the plaintext will always‚ in the simplest and most easily breakable of these cyphers
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utilization of mathematics‚ the understanding of the mechanics of gravity and the harnessing the power of the atom. With all these pivotal discoveries and huge technological advancements‚ there have been many that have been overlooked‚ such as “The Potato.” Since I was a child‚ I have always been interested in topics that kids and even adults would find inexorably boring and absurd. My parents were at one time concerned at my unorthodox interest. At one time‚ I remember myself enraged when my dad
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are endocytosis‚ exocytosis‚ and phagocytosis. Passive transport does not require energy it is powered by the concentration gradient of the molecule. Examples of passive transport are diffusion‚ facilitated diffusion‚ filtration‚ and osmosis. In our Osmosis Lab I used a Grade a large egg from the grocery store. Its circumference is 5 ½ inches it is smooth with no cracks. I carefully place the egg in a clear plastic cup and fill the cup with vinegar. I immediately notice bubbles covering the egg
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Use the balance to determine the mass of the rectangular solid. Record the mass to the nearest 0.01 g in the data table. Volume: Use the metric ruler to measure the length‚ width‚ and height of the rectangular solid. Record these measurements to the nearest 0.1 cm in the data table. Calculate the volume using the following formula: Volume (cm3) = length (cm) x width (cm) x height (cm)
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partially supported because glucose left the bag and is proven by the positive test on the surrounding water. Also the beaker turned orange because of osmosis which attests to glucose leaving the bag. Iodine Potassium Iodine and water entered the bag. This was proven by the color change in the starch test as the bag turned black also because of osmosis. The only thing that the hypothesis lacked was that starch did not move at all. The beaker stayed yellow before and after because the bag is not permeable
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APPENDIX Statistical Tables Table 1 Standard Normal Curve Areas Table 2 Percentage Points of Student’s t Distribution Table 3 t Test Type II Error Curves Table 4 Percentage Points of Sign Test: C␣‚n Table 5 Percentage Points of Wilcoxon Rank Sum Test: TL and TU Table 6 Percentage Points of Wilcoxon Signed-Rank Test Table 7 Percentage Points of Chi-Square Distribution: 2␣ Table 8 Percentage Points of F Distribution: F␣ Table 9 Values of 2 Arcsin ͙ ˆ Table 10 Percentage Points
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of this molecular movement. Diffusion is the random movement of molecules from an area of higher concentration to areas of lower concentration. Osmosis is a special kind of diffusion where water moves through a selectively permeable membrane that only allows certain molecules to diffuse though (Lab Manual 7e‚ 2010). Diffusion or osmosis occurs until dynamic equilibrium has been reached. This is the point where the concentrations in both areas are equal and no net movement will occur
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How Do Different Factors Affect Osmosis Aim: To discover The Different factors that affect osmosis. Factors that affects the rate of osmosis in a potato: * Time * Temperature * Molar * Sucrose solution * NaCl solution * Concentration of liquid * Age of the potato * Variety of the potato * Potassium‚ K(AQ) Factor Chosen: Different Molar of Sucrose Solution In this investigation I will change the molar of sucrose solution to find the increase or decrease
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906g + 4.03176g + 31.9988g = 147.01456g or 147.0 g CaCl2 1g CaCl2 * 2H2O x (1 mol CaCl2 *2H2O/147g CaCl2 *2H2O) = 0.0068 mol of CaCl2*2H2O Molar mass was then calculated for Na2CO3: Na2 = 22.9898g*2 = 45.9796g C = 12.0107g O3 = 15.9994g*3 = 47.9982g 45.9796g + 12.0107g + 47.9982g = 105.9885g or 105.99g Na2CO3 Then using the molar mass of Na2CO3 and the 0.0068 mol of CaCl2*2H2O to calculate the grams required of Na2CO3 for the experiment: 105.99g/mol Na2CO3 * 0.0068 mol of CaCl2
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Introduction Diffusion and osmosis are two types of passive transport. Diffusion is a random movement of molecules from an area of high concentration to an area of low concentration. Osmosis is a type of diffusion that diffuses water through a selectively permeable membrane. There were two parts to the experiment‚ the dialysis tubing lab and the potato lab. In the first experiment‚ the dialysis tubing acted as a semi-permeable membrane. A semi-permeable membrane is a membrane
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