Quarter 1 Exam Answer the questions below. Make sure to show your work when applicable. Solve the absolute value equation. Check your solutions. | 5x + 13| = –7 5x + 13 = -7 5x = -20 X = -4 Simplify the expression below. 6n2 - 5n2 + 7n2 6 – 5 + 7 = 8 =8n2 The total cost for 8 bracelets‚ including shipping was $54. The shipping charge was $6. Write an equation that models the cost of each bracelet. 8 x + 6 = 54 $8.00 each bracelets The total cost for 8 bracelets
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Chapter 7: Intro to Sampling Distributions Sampling Error = x̄ - μ Z-Values for a sampling distribution of x̄ : Z = Z-Values adjusted with Finite Population Correction Applied if: the sample is large relative to the population (n is greater than 5% of N) and sampling Is without replacement Z = Using the Sampling Distribution for Means Compute the Sample Mean Define the sampling distribution μx̄ = Define the probability statement of interest P(z30 will give sampling distribution that
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Teaching Suggestion 5.1: Wide Use of Forecasting. Forecasting is one of the most important tools a student can master because every firm needs to conduct forecasts. It’s useful to motivate students with the idea that obscure sounding techniques such as exponential smoothing are actually widely used in business‚ and a good manager is expected to understand forecasting. Regression is commonly accepted as a tool in economic and legal cases. Teaching Suggestion 5.2: Forecasting as an Art and a Science. Forecasting
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formula 5670 + 2(5670)(.035) + 5670(.035)2 P = $5670 and r = 3.5% = .035 The interest rate with decimals P + 2Pr + Pr2 expanded formula 5670 + 2(5670)(.035) + 5670(.035)2 The expanded equation with values entered 6073.84475 The answer or $6‚073.84 is the rounded answer
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Population Growth Population Data The table below shows the population data for England and Wales between the years of 1801 and 1951. Census was not taken in 1941 because of the Second World War. |Year |Population | |1801 |8‚892‚536 | |1811 |10‚164‚256 | |1821 |12‚000‚326 | |1831
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better estimates of what will happen in the future; this is the main purpose of forecasting. Some firms use subjective methods‚ seat-of-the pants methods‚ intuition‚ and experience. There are also several quantitative techniques‚ moving averages‚ exponential smoothing‚ trend projections‚ and least squares regression analysis. Eight steps to forecasting: * Determine the use of the forecast—what objective are we trying to obtain? * Select the items or quantities that are to be forecasted
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Unit 8 Exponential Functions Review Packet Short Answer Graph the exponential function. 1. 2. 3. An initial population of 505 quail increases at an annual rate of 23%. Write an exponential function to model the quail population. 4. Write an exponential function for a graph that includes (1‚ 15) and (0‚ 6). 5. For an annual rate of change of –31%‚ find the corresponding growth or decay factor. 6. Graph . 7. The half-life of a certain radioactive material is 85
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beer foam based on the changing of height while the foam is collapsing. Theory A quantity is said to be subject to exponential decay if it decreases at a rate proportional to its value. Symbolically‚ this process can be expressed by the following differential equation‚ where N is the quantity and λ (lambda) is a positive number called the decay constant. Figure 1 Figure 1 Exponential laws are common to many physical phenomena. Examples are the amplitude of an oscillator subject to linear friction
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1 .256879 1.5 .38183 2 Stander Deviation H(m) Deviation .5 .3063564 1 .4208522 1.5 .5068326 2 .618042 Equation Used Percentage Error = (Abs(measured value-calculated value)/calculate value)*100% What we can see from the results and the theory of the idea of the ball dropping is that the time it takes form 1 meter and 2 meters aren’t twice as large. What we can see is that it is an exponential increase in a small amount. In theory this is proven that the time is not double just because the distance
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57x56/512=513/512= 5 4. 5. To find the equation of the exponential function that pass through (0‚-1)‚(-1‚-3)‚(-2‚-9) with x-axis as asymptote: Formula: y=a(bx) y-intercept (0‚-1) 1) Point 1 (-1‚-3) 2) Point 2 (-2‚-9) (-3)=ab-1 (-9)=ab-2 -3/b-1=a (-9)/b-2=a Find b- Since a=a Therefore -3/b-1= (-9)/b-2 -3(b-2)= -9(b-1) -3(b-2)-9(b-1)=0 b-1(-3b-1-9)=0 b-1=0 or (-3b-1-9)=0 1/b=0 -3b-1=9 1(0)=b b-1=3 b=0 1/b=3 1=3b b=1/3 Since the plotted curves of exponential function never go above the x-axis
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