formulation F3‚ F4‚ F5 and F6 were found to have satisfactory in-vitro floatability. In case of F1 and F2‚ in-vitro floatability was found to be less than satisfactory‚ mainly due to the comparatively low concentration of Kollidon SR. Drug release form F1 and F2 was comparatively faster than F3‚ F4‚ F5 and F6. It was found that the drug release got slower with increase in the concentration of Kollidon SR. We can conclude that
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crosses. First Cross: The fact that all F1 offspring are black suggests that the parents of the first cross were genotype BB x bb (where B=black and b=albino). The gametes produced by the black parent would have carried the B allele‚ while those produced by the albino parent carried the b allele. The F1 offspring of such a cross would be Bb‚ and since black is dominant over albino‚ all the F1 animals would have had black fur. +1 point Second Cross: Since some of the F1 offspring are albino‚ that means that
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they produced offspring‚ the parental genotypes could be hypothesized based on phenotypic observations and ratios of the F1 and F2 generations. I then could check my observations by testing it using the Chi squared (X2) test. A. Miniature Wings – (Sex-Linked Recessive) To determine the inheritance of miniature wings I first crossed a female wild-type with a mutant male. The F1 generation results were 609(WT) females; 596(wild-type) males. 1:0 ratio of wild-type to mutants. The F2 generation results
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sinusoidal in the sum. In some contexts‚ the fundamental is usually abbreviated as f0 (or FF)‚ indicating the lowest frequency counting from zero.[1][2][3] In other contexts‚ it is more common to abbreviate it as f1‚ the first harmonic.[4][5][6][7][8] (The second harmonic is then f2 = 2⋅f1‚ etc. In this context‚ the zeroth harmonic would be 0 Hz.) All sinusoidal and many non-sinusoidal waveforms are periodic‚ which is to say they repeat exactly over time. A single period is thus the smallest The
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squares to aid in the prediction. If the P generation consists of a purebread red eyed fly(dominant) and a purebread sepia eyed fly (recessive)‚ then the F1 generation will be heterozygous and produce an F2 generation with mostly red eyed‚ but some sepia eyed flies. Prediction: Since the P generation and its F1 offspring is red eyed‚ and the F1 generation had some heterozygous flies‚ it can be predicted that the eye color is an autosomal trait. Also‚ certain colors are not restricted to a certain
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homozygous for white is crossed with one homozygous for yellow‚ what will be the apearance of the F1? of the F2? of the offspring of a cross of the F1 back to its white parent? of the offspring of a cross of the F1 back to its yellow parent? Parents: WW (white) x ww (yellow) F1: all white (Ww) F2: 3/4 white (1/4 WW + 1/2 Ww) : 1/4 yellow (ww) F1 white (Ww) x white parent (WW) offspring: all white (1/2 WW + 1/2 Ww) F1 white (Ww) x yellow parent (ww) offspring: 1/2 white (Ww) : 1/2 yellow (ww) 3. A white-fruited
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to close or cease operations. The same was granted by the Ministry of Labor and Employment. Although it has stopped operations‚ RANSOM has continued its personality as a corporation. For practical purposes‚ reinstatement of the 22 strikers has been precluded. As a matter of fact‚ reinstatement is not an issue in this case.A motion of execution was filed by the Union against AC Ransom but the former was unable to collect due to theinability to find leviable assets of the company. The Union subsequently
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J.P. Thavamaniet al. / IJAIR ISSN: 2278-7844 EDGE PRODUCT NUMBER OF CROWN GRAPH J.P.Thavamani Department of Mathematics‚ M.E.S. College‚ Nedumkandam‚ Idukki‚ Kerala‚ India. Emil: thavamaniprem@yahoo.co.in D.S.T.Ramesh Department of Mathematics‚ Margocis College‚ Nazareth‚ Tuticorin‚ Tamilnadu‚ India Abstract A labeling of a simple graph G is an assignment of integers to the edges subject to certain conditions. A bijection f: E P where P is a set of positive integers is called
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Long Hedge • Suppose that F1 : Initial Futures Price F2 : Final Futures Price S2 : Final Asset Price • You hedge the future purchase of an asset by entering into a long futures contract • Exposed to basis risk if hedging period does not match maturity date of futures 8 Long Hedge • Cost of Asset = Future Spot Price - Gain on Futures • • • • • • • Gain on Futures = F2 - F1 Future Spot Price = S2 Cost of Asset= S2 - (F2 - F1) Cost of Asset = F1 + Basis2 Basis2 = S2 - F2
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in eye colour and wing shape. Table 1: Eye Colour Alleles Parents | Eye Colour | F1 | F2 | | | Wild x Wild | Wild | 1235 | 1160 | | | Brown x Wild | Brown | 0 | 306 | | | | Wild | 1190 | 892 | | | Purple x Wild | Purple | 0 | 325 | | | | Wild | 1208 | 897 | | | Sepia x Wild | Sepia | 0 | 285 | | | | Wild | 1204 | 864 | | | | | | | | | Parents | Eye Colour | F1 | F2 | | | Male | Female | Male | Female | White x Wild | White | 574 | 0 | 273
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