in size‚ its surface area to volume ratio will decrease. However‚ the smaller the organism is‚ the greater its surface area to volume ratio will be. A small uncellular organism would have a large surface area in which diffusion (the movement of molecules) can take place. Diffusion is essential in order to supply oxygen and get rid of carbon dioxide across the outer cell surface membrane. However‚ as an organism gets bigger‚ its surface area to volume ratio gets larger therefore meaning that a specialised
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ACTIVITY 1: Simulating Dialysis (Simple Diffusion) Answers 1. The molecular weight of urea is approximately 60. Which of the membranes can it pass through? a. 50 MWCO membrane b. 100 MWCO membrane c. 200 MWCO membrane d. Both the 100 and 200 MWCO membranes D. Both the 100 and 200 MWCO membranes 2. True or False: A solution containing glucose will diffuse faster through a 200 MWCO membrane if it is heated. True 3. The molecular weight of carbon C is 12; the molecular weight of hydrogen
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concentration gradient on the diffusion rate. It was hypothesized that the greater the stronger the concentration gradient‚ the faster the rate of diffusion would be. To test this‚ dialysis tubes were submerged in different concentration fructose solutions. We weighed the tubes at specific time intervals to measure the rate of diffusion of water in each different solution. The results illustrated that increased concentration gradient increases the rate of diffusion of water in the tubes. We concluded
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removed and final masses recorded‚ and the percent change was calculated. The conclusion developed from the data and knowledge was that the higher the temperature of the water‚ the more osmosis occurred. Introduction Osmosis is the diffusion of water through a selectively permeable membrane from an area which is more concentrated to less concentrated. The objective of this lab was to determine if certain factors affect the amount of osmosis through a cell membrane‚ which in other
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11/22/13 Title: The Effects of Surface Area to Volume ratio in Agar Introduction: What is an efficient way to maximize mass but minimize diffusion time in cell? Answer: An efficient way to maximize mass but minimize diffusion time in a cell is to increase its surface area. If you increase the surface area of a cell relatively to its volume‚ then the diffusion time will decrease. Materials: Agar cubes‚ bromothymol blue- pH indicator‚ vinegar‚ ruler‚ spatula‚ beaker. Methods: I used agar cubes
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required as a medium. A visking tubing is a semi-permeable membrane‚ therefore it will be used to act as the ‘cell’ for the experiment. This is because the phospholipid bilayer of the cell membrane of an actual cell is selectively permeable‚ allowing diffusion‚ osmosis and active transport to occur. The content of the visking tubing (the sucrose solution) will be acting as the cytoplasm of the cell which contains minerals‚ water‚ protein etc. If a visking tubing of sucrose is submerged in a hypotonic
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Pg. 25 Once drug goes into mucosal cells‚ the concentration gradient will decrease. Blood supply to mucosal cell keeps removing drug continuously so the drug conc is smaller & this (heavy vascularisation) maintains constant gradient so that the drugs are constantly removed into the blood stream pH in stomach about 2 Implication: weak acids absorbed readily‚ weak bases not absorbed as readily Implication: some of the drugs may not be able to suvive that acidic environment. & they may disintegrate
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Investigating the effect of surface area to volume ratio on Osmosis As far as living organisms are concerned‚ they are all made up of cells whereas‚ the membrane surrounds all those cells. The cell membrane has the key responsibility to maintain a stable interval environment. Even though‚ Cell membrane is made up of phospholipids bilayer and has that great amount flexibility making it unbreakable while transportation of substances. However‚ certain substances such as‚ dissolved gases‚ sugars‚ salt
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Student Name: I. Diffusion Define the following terms. Solvent Solute Solution. Diffusion Concentration gradient Dynamic equilibrium EXERCISE 1 – Factors influencing rate of diffusion Predict how molecule size and temperature will affect the outcome of this experiment. Record the data from the information in the lab. Potassium Permanganate R.T. Methylene Blue R.T. Time (min) Total Diameter (mm) Distance of Diffusion * (mm) Rate (mm/min)
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Exercise 1: Cell Transport Mechanisms and Permeability: Activity 2: Simulated Facilitated Diffusion Lab Report Pre-lab Quiz Results You scored 75% by answering 3 out of 4 questions correctly. 1. Molecules need a carrier protein to help them move across a membrane because Your answer : c. they are too large. Correct answer: d. they are lipid insoluble or they are too large. 2. Which of the following is true of facilitated diffusion? You correctly answered: c. Movement is passive and down a concentration
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