1. Prepare a lactase enzyme solution by dissolving one lactase enzyme tablet in 200 ml of water in a clean 250 ml beaker. Stir until the tablet has dissolved. Use labeling tape to label the beaker: “Lactase Enzyme Solution.” 2. Prepare a “denatured” enzyme solution by pouring 20 ml of your enzyme solution into a heat resistant tube. The test tube must have the words “Kimax” or “Pyrex” on it. If it does not‚ it is not heat resistant and may break! Use labeling tape to label the test tube: “Denatured
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An experiment was run to determine which enzyme (pectinase‚ and cellulase or combinations of the two enzymes) maximizes juice production and would be most cost effective. The proposed hypothesis was if the enzyme‚ pectinase‚ is added to apple juice‚ then the more juice will be extracted than if cellulase were added because pectinase holds the cell wall together and if it is separated apart from each other‚ then the more juice would be able to flow out. The experimental data show that during the ten
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temperature was above 40Ëšc the enzyme did not work as efficiently‚ even with the extra energy‚ as they had become deformed. Where the enzyme does not work so well or does not even work at all the active site if the enzyme had changed. The enzyme had not died as it is not a living organism. With the shape of the active site changed the enzyme is unable to perform the "lock and key" action the enzyme is meant to do in order to catalyse a reaction. The specified enzyme is shaped to "lock" on to
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Title: Enzyme Activity Aim: To investigate the activity of the enzyme catalase in liver and potatoes‚ and to investigate the effect of temperature‚ surface area‚ pH and certain chemicals on the activity of catalase. Equipment: Dilute hydrochloric acid solution x 1ml 10 volume hydrogen peroxide x 100ml Copper sulphate solution x 1ml Aluminum nitrate solution x 1ml Zinc nitrate solution x 1ml dilute NaOH solution x 1ml Mortar and pestle x 1 25ml Beaker x 1 Hot plate x1
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Lab report nº4 The aim of this experiment was to observe the change of enzyme reaction with different concentration of solution. For this experiment we used potato enzymes (catalase) and hydrogen peroxide in concentrations of 100%‚ 80%‚ 60%‚ 40%‚ and 20% According to P.George: “When catalase is added to hydrogen peroxide‚ there is an initial rapid evolution of oxygen which lasts for about two minutes‚ depending on the peroxide concentration. After this‚ oxygen is given off at a steady rate which
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conclusion that certain environmental factors affect the enzyme activity rate. For the first experiment‚ where we tested the increase in concentration of enzyme with the substrate‚ we found that higher concentration of enzyme increases the rate of reaction of the enzyme. This is because more enzyme molecules are present‚ which allow more substrate molecules to get into the active sites of the enzyme (Sattler W& Esterbauer H). When calculating the absorbance of different enzyme concentration‚ it was noticeable
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The environmental factors that effected the rate of enzyme reactions were the enzyme concentration‚ pH‚ and temperature. These environmental factors help enzymes break down the poisonous chemicals into harmless substance. When we tested the liver with 2ml of hydrogen peroxide for a normal reaction it showed that it was exothermic. We added more hydrogen peroxide and the reaction rate of the liver was 3. We learned that the catalase is reusable because the liver reacted both times when we put in
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Introduction The purpose of this lab is to determine which pigments in a plant support or effect photosynthesis‚ based on starch production‚ which wavelengths of light are involved in photosynthesis‚ and identify plant pigments found in a plant leaf by means of paper chromatography. Life on Earth is dependent entirely on the energy from the Sun‚ not only to keep the planet at a suitable temperature but also to provide the energy required to sustain life. The energy of the Sun‚ in the form of
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Affect of enzyme concentration to the rate of reaction Aim: With the experiment of protein solution‚ in this case egg white added to different pepsin concentrations (0%‚ 0.2%‚ 0.4%‚ 0.6%‚ 0.8%‚ 1.0%) shows‚ as the egg white is a protein and the pepsin works as an enzyme‚ how a higher pepsin concentration and therefore a larger amount of enzymes effect the rate of reaction. Hypothesis: An increased concentration of pepsin speeds up the time the mixture needs to come clear. Introduction:
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Hypothesis: If pH is increased or decreased past the enzyme’s optimum pH‚ the number of products produced by the enzyme will decrease because the enzyme will become denatured. Variables: The Independent variable is the pH of the environment. The uncertainty of pH is ± 1. pH is a unitless value. The Dependent variable is the number of products produced. The uncertainty of this this measurement is ± 1 product. In order for this experiment to be controlled‚ many variable were identified and held constant
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