"Filtration and pore size" Essays and Research Papers

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    to water. • The size of the molecule‚ the larger the molecule the slower the rate of diffusion. 2. Why do you think the urea was not able to diffuse through 20 MWCO? How well did the results compare with your predictions? The urea was not able to diffuse through the 20 MWCO because the membrane pores are too small and the urea molecules are large. The molecular weight of Urea is 60.07 g/mol which is too large thus the molecules were not able to pass through the pores of the 20 MWCO. The

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    7–9) 9. Smaller MWCO numbers translate to smaller pore sizes‚ which correlate with lower filtration rate. Powdered charcoal did not appear in the filtrate using any membrane. Increasing the force driving filtration increases filtration rate. Increasing the pressure gradient effectively increases the filtration rate. By examining the filtration results‚ we can predict that the molecular weight of glucose must be greater than NaCl but less than

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    Describe two variables that affect the rate of diffusion. Your answer: Two variables that affect the rate of diffusion are the MWCO membrane and the solute concentration. Increasing the membrane size and solute concentration will also increase the average diffusion rate. Decreasing the membrane size and solute concentration will reduce diffusion rates and can even prevent all diffusion. 2. Why do you think the urea was not able to diffuse through the 20 MWCO membrane? How well did the results

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    Review Sheet 1

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    which solute had the highest molecular weight? Albumin 2. Which solute displayed the highest rate of diffusion through the 200 MWCO membrane? Na+Cl 3. Using the data from Chart 1‚ explain the relationship between the rate of diffusion and the size of the solute. The larger the solute the smaller the rate of diffusion Facilitated Diffusion The following refer to Activity 2: Simulating Facilitated Diffusion. 4. Did any of the substances travel against their concentration gradient? Explain

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    Experiment simulations examine substances that move passively through a semipermeable membrane‚ and those that require active transport. Those that move passively through the membrane will do so in these simulations by facilitated diffusion and filtration. The plasma membrane’s structure is composed in such a way that it can discriminate as to which substances can pass into the cell. This enables nutrients to enter the cell‚ while keeping unwanted substances out. Active transport requires that the

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    Physioex 9 exercise 1

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    PHYSIO EX 1 Simulating Dialysis (Simple Diffusion) 1. Describe two variables that affect the rate of diffusion. The temperature of the solutions and the difference in concentration of the ion or molecule between the sides of the membrane 2. Why do you think the urea was not able to diffuse through the 20 MWCO membrane? How well did the results compare with your prediction? Since the chemical formula for urea is (NH2)2CO and its molecular weight is about 60. It will not diffuse through the

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    Membrane Processing

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    capable of separating substances when a driving force is applied across the membrane. Membrane filtration enables to separate particles with a diameter smaller than the pore diameter in the membrane from the liquid feed‚ by applying a driving force (pressure) over the membrane. The membrane technology consists principally of Microfiltration (MF)‚ Ultrafiltration (UF)‚ Nano filtration (NF) and Reverse Osmosis (RO).MF is essentially employed as a clarifying operation to remove macro-materials

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    done over simple diffusion‚ facilitated diffusion‚ osmosis‚ filtration‚ and active transport by changing and observing different variables and how they affect transport through the membrane. Obtained was the understanding of the changing of the molecular weight cut off in a membrane‚ and how it does not play a part directly in changing the rate of diffusion‚ but instead determined if diffusion was accomplishable at all. Knowledge on the size of molecules in relation to how they behave through these

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    protein lab

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    precipitate seen at the top of the solution. Lead Acetate Cloudy solution with small specks of white precipitate. Ice cold ethanol Cloudy at the bottom and about 0.5 cm of the top of the solution was clear. Table 4: The results of Gel Filtration Chromatography Eluate Component Volume collected in mL First Blue dextrin 3.00 Second Brown cytochrome 7.00 Third Clear phosphate buffer 5.00 Table 5: The result of Electrophoresis of Amino Acids

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    Cell Transport Mechanisms

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    contains more nonpenetrating solute particles than the interior of the cell. c. it contains the same amount of nonpenetrating solute particles as the interior of the cell. 3. Which of the following would require an input of energy? a. diffusion b. filtration c. osmosis d. vesicular transport 4. Circle the correct term. In pinocytosis / phagocytosis‚ parts of the plasma membrane and cytoplasm expand and flow around a relatively large or solid material and engulf it. 5. Circle the correct term. In active

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