1) Net velocity = 3 cos 55°= 1.72‚ 3 sin 55°-2 = .46 1.72 + .46 = 1.78 m/s Direction traveled will be 14.97° NW. 2) Total distance from you: √50km2 + 2.1km2 + 1.5km2 = 50.067 km from you. Relation to x-axis: = 90° + arccos(2.1/50.067) = 177.59° Relation to y-axis: = arccos(1.5/50.067) = 88.28° 3) Horozontal distance covered is 0+ 1100 * 0.32 = 352m traveled horizontally Vertical distance traveled is -1/2(-9.8)(.32)2 = .502 m traveled vertically 4) If he is 8m from the pool edge and 20m
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change in energy. Here‚ the object starts with kinetic energy [KE = (mv^2)/2] and friction brings it to rest by doing an equivalent amount of work. Work is‚ in this case‚ the product of the force of friction and the distance the object slides while coming to rest. Therefore‚ the distance the object slides is directly proportional to the kinetic energy of the object‚ and inversely proportional to the force of friction‚ i.e. d = (mv^2)/(2F). The 2-kg mass is half the mass of the 4-kg mass‚ and from
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Introduction to sheet metal forming processes INTRODUCTION TO SHEET METAL FORMING PROCESSES The documents and related know-how herein provided by SIMTECH subject to contractual conditions are to remain confidential. This documentation and related know-how shall not be disclosed‚ copied or reproduced by any means‚ in whole or in part‚ without the prior written permission of SIMTECH. © 1999 SIMTECH. All rights reserved Product names are mentioned for identification only and may be registered
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The First and Second Conditions for Equilibrium The first condition for equilibrium: The second condition for equilibrium: • • ΣF = 0 ΣΓ = 0 • In when both of these conditions are satisfied in static systems all forces and torques sum to zero. In problems where the first and second conditions of equilibrium are satisfied‚ the best strategy is to create FBD’s for both the first and second conditions‚ derive equations based on these FBD’s and then see what useful information may be gleaned from
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doing 5000J of work in the process. During this time‚ the car moves 25.0m. Neglecting friction between the car and road‚ find (a) v and (b) the horizontal force exerted on the car. 25) A daredevil on a motorcycle leaves the end of a ramp with a speed of 35.0 m/s as in the figure P5.25. If his speed is 33.0 m/s when he reaches the peak of the path‚ what is the maximum height that he reaches? Ignore friction and air resistance. 31) A horizontal spring attached to a wall has a force constant
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not disapear after a few hours‚ this may be a pressure sore and should not be ignored. If you think you have found pressure sores‚ contact your GP surgery as soon as possible and seek advice. As people age their skin becomes fragile. Quite moderate friction on the skin can over time cause pressure sores. When helping the person to move be careful not to drag them across the bed or chair. Also make sure there are no rough seams in their clothes or anything in their pockets that could rub. Check their
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SINGH 4th Year 4th Year Ph.no: 9789825190 Ph.no: 8122663328 sharma.moumita4@gmail.com k.anupkumarsingh@gmail.com ABSTRACT: Introduction Process Industries handle fluids (liquids and gases) and solids. While much is known about how to characterise and specify a fluid system‚ the subject of solid particle characterisation‚ storage of solids and flow characteristics of solids are complex and have received considerable research. There have been many cases of sudden
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Fluid Balance Explain in detail the fluid compartments of the body‚ including distribution of fluid and electrolytes within each compartment and the movement between compartments. In the average person water constitutes 60% to the total body weight.: 42L in a 70kg individual. 40% is intracellelular fluid‚ while remaining 20% is extracellular. The extracellular fluid can be divided into plasma (from intravascular compartment) and interstitial fluid intracellular fluid (28 L‚ about 35% of lean
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INTRODUCTION The friction material in the automotive brake system has been considered as one of the key components for overall performance of a vehicle. This is because it plays crucial roles in various aspects of the brake performance such as a stopping distance‚ pedal feel‚ counter disk wear and brake induced vibrations. A great deal of effort has been given to improve the performance of the friction material and multiphase composites have been used as a brake friction material from the early
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same time 7. What forces were acting on the objects dropped in the air? What force was acting on the objects dropped in the vacuum? The force that was acting on the objects that dropped in the air was friction. The force that was acting on the object when it dropped in the vacuum was friction also Part two: Comparing Forces 1. Choose two forces and compare and contrast these forces. You must provide two ways that they are
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