questions: force and motion I problem 1 The figure below is an overhead view of a 12 kg tire that is to be pulled by three ropes. One force (Fl‚ with magnitude 50 N) is indicated. Orient the other two forces F2 and F3 so that the magnitude of the resulting acceleration of the tire is least‚ and find that magnitude if (a) F2 = 30N‚ F3= 20 N; (b) F2= 30 N‚ F3 = 10 N; and (c) F2 = F3 = 30 N. problem 2 A weight-conscious penguin with a mass of 15.0 kg rests on a bathroom scale (see figure below).
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published what are known today as Newton’s three laws of motion. If these laws didn’t exist‚ motion and life would not exist. His three laws are accurately relative to what "normal" speeds are on earth. Newton’s first law is most commonly referred to as the law of inertia. The law states that an object that is at rest will stay at rest unless an unbalanced force acts upon it‚ and vice-versa. If an object is moving and there is no force to move the object in a different direction‚ then the said
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Lab II‚ Problem 3: Projectile Motion and Velocity Oct. 06‚ 2013 Physics 1301W‚ Professor: Hanany‚ TA: Vladimir Abstract A ball is tossed obliquely. The vectors of position and velocity are measured. The acceleration is calculated. Introduction A toy company is now making an instructional videotape on how to predict the position. Therefore‚ in order to make the prediction accurate‚ how the horizontal and vertical components of a ball’s position as it flies through the air should
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constant. If a ball is attached to the end of string and swung at a constant speed (i.e. only the direction of the velocity is changing not the magnitude) then there must still be an acceleration. The acceleration is directed towards the center of the motion. This acceleration is call centripetal acceleration! 2.6.2 State the expression for centripetal acceleration. The acceleration of any object moving in a circle at a constant speed is given by the equation: (1) a⃗ =v2r It is important to note
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ASP 0501 EXERCISES – circular motion 1 A car travels at a constant speed around a circular track whose radius is 2.6 km. The car goes once around the track in 360 s. What is the magnitude of the centripetal acceleration of the car? 2 An astronaut in a chamber moves on a circular path‚ much like a model airplane flying in a circle on a guideline. The chamber is located 15 m from the center of the circle. At what speed must the chamber move so that the astronaut is subjected to 7.5 times the acceleration
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Intermolecular forces exist between independent particles‚ such as atoms‚ ions‚ or molecules. They can be forces of either attraction or repulsion. The amount of charge‚ how it is distributed‚ and the length of time that a charge distribution exists can affect the strength of intermolecular forces. And despite having variable force strengths‚ all intermolecular forces are considered weak compared to chemical bonds‚ or intramolecular forces. Chemical bonds are not only stronger; they are also more
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law of motion: For every action‚ there is an equal and opposite reaction. How this applies to our bottle rockets that we constructed‚ is that when we release‚ the water and air pressure comes out of the bottom. That pushes against the ground‚ the equal and opposite reaction is the earth pushing back up. Whatever object has less mass moves. In this case‚ the rocket has less mass than what it is pushing against; the earth. When we created our rockets‚ we had to keep all 3 laws of motion in mind
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Newton’s second law of motion (Car vs Suv) According to newton’s second law of motion‚ Acceleration is produced when a force acts on a mass. The greater the mass is‚ the grater the acceleration is needed to move forward. This law basically states that a force applied to the objects changes its velocity overtime in the direction of the force that is applied‚ the acceleration is directly proportional to the force‚ as an example‚ if pushing on an object‚ causing it to accelerate‚ and then you push
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HSC PHYSICS 2011 HSC PHYSICS 2011 PENDULUM MOTION BY NATHAN LOCKE Image taken from http://www.practicalphysics.org/go/Experiment_480.html Pendulum Motion Aim: To determine the rate of acceleration due to gravity by using a pendulum. Background Information: Equation One: T=2πlg Where T = the period of the pendulum (s). This is the time taken for the pendulum to return to its starting position. l = length of the pendulum g = the rate of acceleration due to gravity (ms-2) * In
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Projectile Motion Purpose: An object in a projectile motion move horizontally with no acceleration and vertically with the gravitational acceleration at the same time. This experiment is to investigate projectile motion using experiments‚ equations and comparing the expected and experimental data. Procedure: Case I: Use formulas to find equation of horizontal Range (R) in a projectile motion. Rearrange equation for Rmax‚ and find the angle Adjust the launches angle to angle Launch
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