"The Force Table" is a simple tool for demonstrating Newton’s First Law and the vector nature of forces. This tool is based on the principle of “equilibrium”. An object is said to be in equilibrium when there is no net force acting on it. An object with no net force acting on it has no acceleration. By using simple weights‚ pulleys and strings placed around a circular table‚ several forces can be applied to an object located in the center of the table in such a way that the forces exactly cancel
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Objective: To study the relationships between position‚ velocity‚ and time‚ with acceleration held constant‚ of an object moving in one-dimensional motion with minimum friction. A motion sensor will be used to measure various aspects of vector quantities. Description: An Air Track is positioned along the edge of the table. It is a long straight metal beam with many small holes that are roughly each 2mm in diameter. It is positioned at an angle to allow the gliders to glide down the slope
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Units‚ 12e 2 Force Vectors Part 2 Copyright © 2010 Pearson Education South Asia Pte Ltd Chapter Objectives • Cartesian vector form • Dot product and angle between 2 vectors Copyright © 2010 Pearson Education South Asia Pte Ltd Chapter Outline 1. 2. 3. 4. 5. Cartesian Vectors Addition and Subtraction of Cartesian Vectors Position Vectors Force Vector Directed along a Line Dot Product Copyright © 2010 Pearson Education South Asia Pte Ltd 2.5 Cartesian Vectors • Right-Handed
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Experiment 3 Vectors J. Rodriguez‚ J. Panis‚ Y.Magsipoc‚ A. Castillo‚ A. Ordoñez‚ M. Tombado‚ J. Semilla‚ K. Almeniana‚ and P. Bugacia Industrial Engineering Department‚ College of Engineering Adamson University‚ Ermita‚ Manila In this experiment‚ the students will determine the resultant of different forces using different methods: graphical method; and getting the equilibrant of forces using component method the force table. Each of the three methods has their own way of getting the resultant
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Addition of Force Vectors Abstract The purpose‚ of this experiment‚ was to prove that there is a relation between the magnitude of the resulting vector‚ and the angle between the vectors that are being added. The test was performed by creating a balance between three weights tied to strings on a pulley that transferred the string on top of a graduated disc‚ which made easy the measurement of the angles between them. After performing the experiment‚ my group concluded that there is a relation
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Chapter 1 Vectors‚ Forces‚ and Equilibrium 1.1 Purpose The purpose of this experiment is to give you a qualitative and quantitative feel for vectors and forces in equilibrium. 1.2 Introduction An object that is not accelerating falls into one of three categories: • The object is static and is subjected to a number of different forces which cancel each other out. • The object is static and is not being subjected to any forces. (This is unlikely since all objects are subject to the force of gravity
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Conclusion: Category 1: Momentum was found that after the collision was less than before the collision by 10%. This was not what has been expected‚ so the difference was fairly significant. This happened because of friction‚ when the two pucks collided‚ they have lost a bit of their momentum‚ so the momentum after the collision differed. Kinetic energy differed more than what was expected‚ it was significantly less after the collision‚ the difference before and after the collision was 63.7%‚
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Forces and Newton’s Laws of Motion Topics: • Motion and Newton’s first law • • • • • What is a force? Identifying forces Newton’s second law Free‐body diagrams Newton’s third law N t ’ thi d l Sample q p question: These ice boats sail across the ice at great speeds. What gets the boats moving in the first place? What keeps them from going even faster? Slide 4-1 What Causes Motion? In the absence of any forces acting on it‚ an object will continue moving forever.
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Parallel Forces Objective: Find FA and FB on the apparatus which are parallel to both Fulcrum A and B. Calculations: Theoretical FB Στ = 0 +FB 0.5 - (0.1kg x g x 0.1m) - (0.2kg x g x 0.4m) - (0.05kg x g x 0.7m) - (0.1kg x g x 0.3m) = 0 -[{(0.1kg x 0.1m) + (0.2kg x 0.4m) + (0.05kg x 0.7m) + (0.1kg x 0.3m)}x 9.8] + 0.5FB = 0 0.5FB = [(0.1 x 0.1) + (0.2 x 0.4) + (0.05 x 0.7) + (0.1 x 0.3)]x 9.8 FB = FB = 3.04 N Experimental FB FB = mpanB g - mfulcrumB g FB = (0.385kg x 9.8)
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Physics Lab Report Experiment M3 Centripetal Force School: La Salle College Class: 6G Group members (Group 7): Carson Ho‚ Tang Yui Hong‚ John Yu‚ Justin Kwong Date: 1 / 10 / 2014 Report is written by: Tang Yui Hong 6G (27) Title Centripetal Force Objective To verify the equation for centripetal force Apparatus Instrument Descriptions 1 rubber bung circular‚ cylinder screw nuts and wire hook / 1 small paper marker / 1 rule 1 metre safety goggles / adhesive
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