tetraiodide were calculated. Recrystallization is to further improve the purity of tin tetraiodide. The solvent is carefully chosen to be toluene in order to maximize the recovery of tin tetraiodide during recrystallization. Experimental method1 Approximately 2.50g iodide and 1.01g tin were weighed on a balance and were placed in an Erlenmeyer flask. Approximately 10ml toluene was added to the flask. The mixture was heated on a hot plate at almost boiling temperature and was stirred using a stirring rod
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DPOP and NPOP together evaluate the risk posed to humans by fire at landfills. DPOP measures the distance between the 297 landfill and the nearest building used by people for residential‚ occupational‚ educational‚ or recreational purposes. DPOP 298 score is calculated using Equation 30. For distance greater than 3057 m‚ DPOP = 0. If the distance is 0‚ then maximum 299 DPOP = 4.613. 300 DPOP = 4.613 x exp(-0.0005 x distance) (30) 301 3.8 Population within 3 km radius (NPOP) 302 NPOP‚ as per Equation
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closed polygon or a ring and an example is a cyclohexane. Another way to classify hydrocarbons depends on the type of bonding that exists between the carbons. There are hydrocarbons that contain only carbon-to-carbon single bonds and they are called alkanes. There are also hydrocarbons that contain only carbon-to-carbon single bonds but it is different from alkanes because their carbon atoms are bonded together to form rings. They are called cyclohexanes. Alkanes and cycloalkanes are also known as
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electron clouds of the groups or atoms. This arises‚ especially in structure D‚ when the hydrogens attached in the axial methyl substituents interact with one another. For cyclohexanes it is best when any of the substituents lie in equatorial position as much as possible‚ because it gives way to less steric strain. When the cyclohexanes are poly-substituted‚ not all the isomers can occupy all equatorial positions‚ yet the most stable isomer will have substituents in equatorial positions. The trans isomers
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color Br2/CH2Cl 2 the solution turned orange. Orange color held. Alkene Alkene used was pentene. Originally clear liquid. After addition‚ solution turned yellowish at first but then turned clear after a few minutes of sitting. Alkyne Alkyne used was toluene. Originally clear liquid. After addition‚ solution turned orange. Orange maintained longer than alkene but eventually turned clear. Unknown Originally clear liquid. After addition of unknown‚ turned orange but eventually faded to clear color after
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Angela Pierre Chem 112 Lab Due: 03/05/2015 Lab Report 14 Questions 1. Part A.3. Some of the cyclohexane solvent vaporized during the temperature versus time measurement. Will this loss of cyclohexane result in its freezing point being recorded as too high‚ too low‚ or unaffected? Explain. -The freezing point will be higher because the loss of solvent means that the molarity of solute is too high. The melting point will be lower than expected. 5. Part B.2. The solute dissociates slightly in the
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Absolut Vodka’s Absolute Global Marketing On a lovely morning of September 2009‚ with the fiftieth “beep”‚ Steven scanned the last bottle of the limited edition Absolut Vodka 2009 on the spirits Shelf of Selfridges London. The latest special-edition bottles of Absolut - packaged in a dramatic heavy-metal rock style‚ wrapped with golden studs and gray leather‚ rapidly become a spot light among the shelf‚ the whole spirit of Rock n’ Roll are simple illustrated by the new design‚ and just as its normal
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pipettes Safety: safety glasses must be worn to prevent injury to the eyes. Ensure room is well ventilated whilst using the hydro carbons. Method: 1. Place 1 ml of sample A (cyclohexane) into a test tube containing 4 mls of the bromine water solution. Record observations of any reaction. 2. Place 1 ml of sample A (cyclohexane) into a test tube containing 4 mls of the potassium permanganate solution. Record observations of any reaction. 3. Place 1 ml of sample B (cyclohexene) into a test tube containing
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COMPARATIVE INVESTIGATION OF ORGANIC COMPOUNDS Abstract Organic compunds were examined to a comparative investigation to differentiate the properties of each sample. The physical state at room temperature‚ odor and color of the sample were noted by simple observation. In terms of solubility in H2O‚ 5% NaOH solution and 5% HCl solution‚ the samples were classified as to miscible‚ slightly immiscible or immiscible for liquid; and very soluble‚ soluble‚ partially soluble or insolubse for solid. The
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second stage is its subsequent oxidation to adipic acid with an excess of strong nitric acid in the presence of copper and vanadium catalysts. Only 3-8 % conversion of cyclohexane is obtained in the first step. Recycling of the large amount of cyclohexane unreacted and separation of cyclohexanol and cyclohexanone from cyclohexane present major problems. In the second step the highly corrosive nature of nitric acid and the nitrous oxide gas produced create reactor material issues and serious environmental
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