to ride on. This is familiar to people who play air hockey‚ and it’s been used in lower speed transit before‚ such as the people mover in the Detroit Airport. The low pressure in the tube means that it doesn’t take a lot of power to overcome air friction and can be sustained by on board batteries (using numbers gleaned from their work with the Tesla S)‚ and the big power drain from acceleration is accommodated by Linear Induction Motors (many existing transit designs use LIMs‚ such as the Vancouver
Premium Friction
SUMMARY OF FRICTION The maximum force of static friction that exists between two surfaces is proportional to the normal force and mostly independent of area of contact. This situation is shown here: N = the total normal force (force perpendicular to the horizontal surface) which is essentially the weight of the object. The coefficient in that equation is called the coeffecient of static friction and that depends on the material: When the object is actually moving‚ the friction is said to be kinetic
Premium Friction Force Classical mechanics
EFFECT OF SURFACE AREA ON AIR FRICTION Design Background Information: Air resistance‚ also called drag‚ is the forces that are in opposition to the relative motion of an object through the air. Drag forces act opposite to the oncoming flow velocity. Size and shape are the two factors that affect air resistance. Air resistance depends on the surface area‚ so‚ as the surface area increases‚ the air resistance increases. When an object is falling‚ air resistance acts to push it back up. This is
Premium Force Drag equation Drag
the revolution and rotation of the ball mill grinding media along the axis of the cylinder in the cylinder body‚ between the grinding media and its contact with the cylinder area produce squeezing and grinding the peel force‚ ore and ore milled. Friction between the ball mill ball and cylinder when the cylinder rotates‚ the ball is brought up and rise to a certain height‚ the ball itself‚ gravity‚ and finally along the whereabouts of a certain orbit. ball mill:http://www.china-xingbang.com/
Free Force Classical mechanics Torque
Physics Experiment 105 FRICTION Name: Alviar‚ Renée Hannah C. Program/ Year: AR – I Course Code/ Section: PHY10-2L – A2 Student No.: 2012170402 Group No.: 5 Date of Performance: February 18‚ 2013 Date of Submission: March 4‚ 2013 Instructor: Prof. Morris Martin M. Jaballas GRADE: DISCUSSION During Part A (Determination of the Coefficient of Friction) of this experiment‚ as we determine Wb and Wp‚ we are then able to calculate for the coefficient of friction (µ) using the formula:
Premium Friction Force Classical mechanics
motion. This relationship can be viewed in the formula: Force = mass (acceleration) The key to keeping the mousetrap car accelerating is to keep the forces acting upon it unbalanced. The force of the mousetrap car has to be larger than the force of friction working against the car. Because the force provided by the mousetrap is rather minuscule‚ and the force needs to strong enough to move the mousetrap car‚ we are faced with our next obstacle. We have to make the mass of the object light enough to
Premium Automobile Classical mechanics Force
all choices before answering. face of the table? Assume the boxes each have masses of 2.0 kg‚ the coefficient of static friction is µs between table and box‚ and the acceleration due to gravity is 10 m/s2 . 001 10.0 points A block accelerates 3 m/s2 down a plane inclined at angle 27.0◦. The acceleration of gravity is 9.81 m/s2 . 1. The force of the static friction would have a vertical component in this situation‚ and that is impossible since it must be parallel to the table surface
Free Force Friction
1.6 kJ 2. A horizontal force of 150 N is used to push a 40.0-kg packing crate a distance of 6.00 m on a rough horizontal surface. If the crate moves at constant speed‚ find (a) the work done by the 150-N force and (b) the coefficient of kinetic friction between the crate and surface. 900J‚ 0.383 3. A block of mass 2.50 kg is pushed 2.20 m along a frictionless horizontal table by a constant 16.0-N force directed 25.0° below the horizontal. Determine the work done by (a) the applied force‚ (b) the
Free Force Friction
1) Block B in Fig. 6-31 weighs 603 N. The coefficient of static friction between block and table is 0.32; angle θ is 33°; assume that the cord between B and the knot is horizontal. Find the maximum weight of block A for which the system will be stationary. Fig. 6-31 A)150 N B)175 N C)125 N D)200 N 2) In Fig. 6-33‚ two blocks are connected over a pulley. The mass of block A is 7.8 kg and the coefficient of kinetic friction between A and the incline is 0.13. Angle θ of the incline is 44°
Premium Force Mass Classical mechanics
The Physics of Braking Systems By James Walker‚ Jr. of scR motorsports Copyright © 2005 StopTech LLC Author’s disclaimer: mechanical systems operating in the physical world are neither 100% efficient nor are they capable of instantaneous changes in state. Consequently‚ the equations and relationships presented herein are approximations of these braking system components as best as we understand their mechanizations and physical attributes. Where appropriate‚ several examples of limiting conditions
Premium Force Friction Energy