Identification of an Unknown Organic Compound The objective of this lab was straightforward. We were given an unknown compound and we were to perform an IR spectroscopy and as well as NMR spectroscopy. With the IR spectroscopy‚ I was able to name the functional groups I have on my compound and further confirmed my assumptions by looking at the NMR spectroscopy after. The unknown number I was given was number 203. The molecular weight of the compound was 121. From the molecular weight‚ I calculated the molecular
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words: diazo compounds‚ boron‚ hydrazine‚ transition-metalfree reactions‚ 1‚2-migration 1 Introduction Diazo compounds are useful building blocks in organic synthesis as a result of their diverse reactivity in various reactions and functional group transformations.1‚2 In most cases‚ diazo compounds are used as the precursors of free carbene or metal carbene species C (Scheme 1). Typical reactions of metal carbenes include X–H insertions (X = C‚ N‚ O‚ S‚ etc.)‚ cyclopropanation‚ ylide
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1 Haloalkanes and Haloarenes IIT-JEE Chemistry Siddhivinayaka Educational Academy Rajendra Nagar Chowk Link Road Bilaspur Ph-07752- 237799/238799 Website : www.bajpaigroup.com. e-mail - info@bajpaigroup.com CHAPTER 23 LEARNINg OBJECTIvES (i) Name haloalkanes and haloarenes according to the IUPAC system of nomenclature from their given structures. (ii) Describe the reactions involved in the preparation of haloalkanes and haloarenes and understand various reactions that they undergo.
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ETHERS Classification of Ethers: Symmetrical ethers – two groups attached to O are identical Ex. CH3CH2OCH2CH3 – diethyl ether Unsymmetrical ethers – two groups attached to O are not identical Ex. CH3CH2OCH3 – ethyl methyl ether Physical Properties of Ethers: Ethers have much lower boiling points compared to alcohols of comparable MWs. BPs of ethers increases with increasing MW. BPs of isomeric ethers increase with increasing alkyl chain length. BPs of ethers are about the
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The prescribed procedure produced nylon. The initial indication that nylon was being formed was through the combination of 0.02M of sebacoyl chloride in hexane and 0.05 M 1‚6 hexanediamine. Due to the fact there was an evident product formed after the combination of these two solutions‚ this simply shows that nylon was produced. The prescribed procedure produced nylon due to the fact that there was a present product of the reaction within the IR spectrum. The main peaks of frequency for the unknown
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PID#_________________________ 1. Amine Basicity (5 points). Place the following compounds in order of their basicity with #1 being the most basic and #4 being the least basic. Work carefully. There will be no partial credit or regrades on this problem. 2. Functional Group Preparations (15 points). Give chemical equations for five methods for synthesizing 2-methyl-1-propanamine in a single synthetic step‚ not counting any workups. 3. Reactions of Amines (15 points). Draw the organic products of the following
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CHAPTER I INTRODUCTION 1.1 HISTORY: Ethylene Glycol (1‚ 2 – ethanediol)‚ HOCH2CH2OH usually called glycol is the simplest Diol. Diethylene glycol and Triethylene glycol are Oligomers of Mono ethylene glycol. Ethylene glycol was first prepared by Wurtz in 1859; treatment of 1‚2 dibromoethane with silver acetate yielding ethylene glycol diacetate via saponification with potassium hydroxide and in
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All other chemicals were of analytical grade. Mice were randomly divided into groups‚ each containing six animals. On the day of the experiment‚ control group received 0.1% carboxy-methyl cellulose‚ p.o.‚ 1 h before the experiment. Chalcones (50 mg/kg) were suspended in 0.1% CMC and administered orally to animals 1 h before the test. The following two analgesic models
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Para-nitrobenzeneazoresorcinol dye and methyl orange belong to a class of dyes known as “azo colors” which contain the azo group linked to two aromatic nuclei. The nature of the aromatic substituent’s on both sides of the azo group (-N=N-) controls the colors of the azo compound as well as the water- solubility of dyes and how well they bind to a particular fabric. In addition to the azo group‚ the dyes
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Notes Aldehydes and Ketones The major similarity between an aldehyde and a ketone is the carbonyl group. A carbonyl group is a carbon atom doubly bonded to an oxygen atom. [pic] Both molecules have a carbonyl group‚ the difference the number of carbons bonded to the carbonyl carbon. An aldehyde will have none or one and a ketone will have two carbons. All aldehydes‚ except formaldehyde‚ will have a hydrogen atom on one side of the carbonyl carbon and at least on carbon on the other side
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