The Genetics of Fast Plants Kristin Phillips Dr. Orlando April 4‚ 2014 Abstract The experiment that was being completed was the genetics of plants using Fast Plants. The purpose of this project was to understand Mendel’s concept of a Dihybrid by performing similar crosses and calculated the phenotypes that are displayed. This project was conducted over many weeks by planting F1 seed and waiting for them to grow then cross-pollinating the F1 plants to produce the F2 seeds. Next students
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BACTERIAL TRANSFORMATIONS USING PVIB II. INTRODUCTION Transformation is the manipulation of a bacterial cell’s DNA in order to alter the cell’s genotype or phenotype by absorbing free DNA from its surroundings. In this lab‚ pVIB plasmid will be used. A plasmid is a segment of DNA that can incorporate itself into the bacterial DNA. Although is not required for growth of the bacterial cell‚ plasmids can provide advantages in stressful environments such as the ability to adapt as environmental
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Discussion Based on the results of the lab it can be seen that the metal in the lab can be identified as lead. The identity of the metal was determined by the heat energy calculations. The heat capacity that was found matched closely to that of the lead. There were several possible sources of error that could be found throughout the lab. Some of the main errors as seen in question 7 that could have affected the results of the lab were the amount of water transferred with the hot metal‚ the
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In this lab‚ we will measure the heat of combustion‚ or calorimetry‚ of a candle and compare the found quantity with known values for other hydrocarbons. The calorific value is the total thermal energy released when a substance goes through complete combustion with oxygen. In order to achieve the purpose of this lab‚ we must first determine the mass of the tea candle. Then‚ we will determine our room temperature‚ measure about 100 mL of chilled water‚ and then pour the water into the given empty
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Specific heat is the property of the material that an object is made of. The greater the material’s specific heat and the mass‚ the more energy must be added to change its temperature. The goals of this lab were to calculate the specific heat of water and compare to the known value of 4.19J/°Cg. Another goal was to calculate the efficiency of the hot pot used for the experiment and to estimate the cost to heat water for a cup of tea and to bath in a bathtub. The thermal energy E= cm Δ T‚ required
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Specific Heat Lab Objective: Find the specific heat of the unknown metal given using calorimetry. Background Theory: In every reaction‚ energy is transferred between a system and its environment. A system encompasses the substances that are involved in a reaction‚ and everything else in the universe other than the system is called the environment. The standard SI unit of energy is Joules (J). Temperature is the level of excitement of the atoms in a substance. In most cases‚ energy is
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ME 4053 Heat Exchanger Homework‚ 6 pts towards Thermal Fluids Lab grade Due at the beginning of your Heat Exchanger Lab Name: Phillip Ross Crumpton Attention: This is an individual assignment and collaborations are not allowed. Please pay special attention to the number of significant digits. 1. Measurements are taken in the ME4053 heat exchanger lab. From the measurements‚ the heat rate from the hot water is calculated to be 3743 W‚ and the heat rate to the cold water is calculated
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BIO208 Genetics Lab What is PCR and How Does It Work? BIO208 Genetics Lab: What is PCR and How Does It Work? EXPERIMENT OBJECTIVE: The objective of this experiment is for students to gain handson experience in the principles and practice of Polymerase Chain Reaction (PCR). BACKGROUND: Polymerase Chain Reaction (PCR)‚ discovered by Kary Mullis‚ has had an extraordinary impact on various aspects of biotechnology. PCR has revolutionized research and diagnostics-based molecular biology. PCR
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Heats of Reaction Lab Report Purpose: To measure the heats of reaction for three related exothermic reactions and to verify Hess’s Law of Heat Summation. NaOH(s) ( Na+(aq) + OH-(aq) ΔH = -10.6kcal/mol NaOH(s) + H+(aq) + Cl-(aq) ( H2O + Na+(aq) + Cl-(aq) ΔH = -23.9kcal/mol Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) ( H2O + Na+(aq) + Cl-(aq) ΔH = -13.3kcal/mol Background: Energy changes occur in all chemical reactions; energy is either absorbed or released. If energy is released in
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8/2/15 Lab Report Experiment to measure the latent heat of vaporisation of water Theory Latent heat of vaporisation is when a liquid is heated enough to start boiling‚ at this point‚ even if the source of heat keeps heating the liquid‚ the liquid’s temperature will not rise any further until all of the liquid is converted to gas. For example‚ if water is boiling in a kettle‚ and the kettle is left on whist the water is boiling‚ the water’s temperature will not exceed 100°C because all the heat energy
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