Physics 211 Experiment 1: Free Fall - Determining the acceleration of gravity Prior to Lab: Derive the numbered equations (Equations 1‚ 2 and 3) in the lab instructions using the definitions of velocity and acceleration (a=dv/dt and v=dy/dt). Object: The object of this experiment is to determine the value of the acceleration of gravity by measuring the rate of acceleration of a freely falling object. In addition‚ one will be able to compare theory with experiment for constantly accelerated
Premium Acceleration Kinematics Velocity
Science 10. P 393 Investigation 13A Time (sec) Displacement (cm down) Velocity ( down) 0 0 0 0.1 0.6 = Df – Di = 0.6 – 0 = 0.6 = 0.2 1 = Df – Di = 1 – 0.6 = 0.4 = 0.3 3.3 = Df – Di = 3.3 – 1 = 2.3 = 0.4 5.9 = Df – Di = 5.9 – 3.3 = 2.6 = 0.5 7.4 = Df – Di = 7.4 – 5.9 = 1.5 = 0.6 8.7 = Df – Di = 8.7 – 7.4 = 1.3 = 0.7 10.1 = Df – Di = 10.1 – 8.7 = 1.4 = 0.8 11.4 = Df – Di = 11.4 – 10.1 = 1.3 = 0.9 12.9 = Df – Di = 12.9 – 11.4 = 1.5 = 1.0 11.8 = Df – Di = 11.8 – 12.9 = -1.1 = 1
Premium Acceleration Velocity Kinematics
Group A: Model Answer GROUP A MODEL ANSWER Haines et al.‚ A neutron diffraction study of quartz-type FePO4: high-temperature behavior and α-β phase transition Z. Kristallogr. 218‚ 193-200 (2003). DO NOT PLAGIARISE THIS MODEL ANSWER Paragraph 1 This research paper discussed about the structural evolution of FePO4 from temperature range of 294K to 1073K. The cell parameters and atomic coordinates in the α phase tend to wars the value obtained in the high-temperature β-phase and exhibit first order
Premium Crystal structure Crystallography Molecular geometry
Graded Assignment Unit Test‚ Part 2: Polynomials and Power Functions Answer the questions. When you are finished‚ submit this assignment to your teacher by the due date for full credit. (8 points) 1. Solve the equation . Check your solution(s) and state the final solution set. Show all your work. Answer: (8 points) 2. Use successive differences to classify the function represented in the table. Show all your work. x –2 –1 0 1 2 h(x) 14 5 2 5 14 Answer: (9 points) 3. For the
Premium Polynomial Ring Analytic geometry
Linear Functions There are three different ways to write linear functions. They are slope-intercept‚ point-slope‚ and standard form. There are certain situations where it is better to use one way than another to solve a problem. It is important to understand and comprehend the mechanics of these three forms so that you know what form to use when solving a problem. The first form‚ point-slope‚ is written as y-y1=m(x-x1). M is the slope and x1 and y1 correspond to a point on the line. It’s good to
Premium Derivative Linear equation Function
Physics Lab Report#3 “Determining the period of a pendulum” Name: Fei Huo Date performed: October 1st‚ 2014 Period 5 Teacher: Mr. Glasel Purpose: The Purpose of this Lab was so that my classmates and I can examine what kind of factors affect the period of a pendulum. Introduction: In a simple form‚ the pendulum is a weight hung from a long string that Galileo discovered that it can be used to track the passage of time very accurately around 400 years ago. In this
Premium Pendulum Analytic geometry Dimension
Engineering Mechanics: Statics in SI Units‚ 12e 2 Force Vectors Part 2 Copyright © 2010 Pearson Education South Asia Pte Ltd Chapter Objectives • Cartesian vector form • Dot product and angle between 2 vectors Copyright © 2010 Pearson Education South Asia Pte Ltd Chapter Outline 1. 2. 3. 4. 5. Cartesian Vectors Addition and Subtraction of Cartesian Vectors Position Vectors Force Vector Directed along a Line Dot Product Copyright © 2010 Pearson Education South Asia Pte
Premium Analytic geometry Force Cartesian coordinate system
Objectives: To learn about motion through studying and matching graphs of position vs. time and velocity vs. time; to develop an understanding of the concepts of kinematics. Predict‚ sketch‚ and test motion graphs to better understand motion. Equipment: Computer Vernier computer interface Logger Pro Vernier Motion Detector Meter stick Masking tape Preliminary Questions: 1a. The pink line shows the position of an object at rest with respect to
Premium Kinematics Acceleration Derivative
Hyperbolas A hyperbola is the set of all points in a plane whose distances from two fixed points in the plane have a constant difference. The fixed points are the foci of the hyperbola. The line through the foci is the focal axis. The point on the focal axis midway between the foci is the center. The points where the hyperbola intersects its focal axis are the vertices of the hyperbola. The standard for of the hyperbola equation is: x2/a2 – y2/b2 = 1 and this is for when the hyperbola is centered
Premium Analytic geometry Euclidean geometry Line
FIELD WORK NO. 5 LAYING OF A COMPOUND CURVE USING TRANSIT AND TAPE OBJECTIVES: To be able to lay a compound curve by incremental chords and deflection angle method. To master the skill in leveling‚ orienting‚ and using transit effectively. To work cooperatively with one’s group mates and efficiently perform the required task. MATERIALS/INSTRUMENTS: 2 range poles Chalks 50 meter tape Theodolite METHOD/PROCEDURE: The professor gives the following data: I1= 60⁰ D1=
Premium Circle Curve Distance