Hydrated Crystals LAB PURPOSE: The purpose of this lab was to determine the percent of water in the given hydrate. MATERIAL/EQUIPMENT LIST: Crucible and cover Clay Triangle Crucible Tongs PROCEDURE: 1. First‚ the crucible and crucible cover were cleaned and dried. 2. The crucible and crucible cover were then placed on the clay triangle and heated with the Bunsen Burner for 3 minutes. 3. After this‚ the crucible and crucible cover
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SCIT 1407/BIOL 2401 Tissue Lab Practical 1 I. EPITHELIAL TISSUE: Only exists in three cell shapes – flat or squamous‚ cuboidal & columnar. This tissue covers or lines other tissues or produces tubes. Epithelial tissue always rests on a basement membrane. The characteristics are: lack of visible interstitial space‚ many cells‚ and no blood vessels. A. Simple Squamous: (kidney slide). Look in the outer edge or cortex of the kidney to find a Bowman’s capsule. The lining of the Bowman’s
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Blood Splatter Analysis Lab Independent Variable & Dependent Variable: Independent: Blood Spatter Dependent: Diameter (size of blood splatter) Problem Statement: What height did the blood at the crime science fell from Hypothesis: Anna Garcia might have tripped which caused her blood stain to reach the maximum height of the stool‚ which means her blood splatter fell lower than her height. Materials: Gloves Eye Droppers with blood Journal Yard Stick Clear ruler Blank piece
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Conor Westerman LAB 7 1. List whether the student was positive or negative for each characteristic and include whether the characteristic is dominant or recessive. (6 points) a. Blood type A+ b. Widow’s peak yes‚ + c. Free ear lobes yes‚ + d. Tongue rolling yes‚ + e. Hitchhiker’s thumb yes‚ + f. Left thumb dominance yes‚ + g. Little finger bend No‚- h. PTC taster yes‚ + i. Mid-digit hair no‚ - j. Facial dimples yes‚ + k. Freckles no‚ - l. Cleft chin no‚ - (+)=dominant (-)=recessive 2. Can the student
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Caroline Guidry Dr. Beverly A. Clement Organic Chemistry 2423‚ Section 304 25 October 2017 Lab 6: Natural Products I The main goal of this experiment was to employ isolation techniques to derive chemicals from two different natural sources and study their properties (Clement 91). The two natural sources used in this experiment were an orange (the peel contains limonene‚ which is a terpene) and a dichloromethane solution of clove oil (which contains eugenol‚ an acetogenin). To isolate the eugenol
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was used to run the IR spectrum. However‚ since there was a fire alarm for this lab‚ we were not able to obtain the IR spectrum of our product. Also‚ the solution was not filtered
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AP BIOLOGY Lab 5 Cellular Respiration Objective: To calculate the rate of CR from the data. To then relate gas production to respiration rate. Then test the rate of CR in germinating versus non-germinating seeds in a controlled experiment and then test the effect of temperature on the rate of CR in the germinating versus non-germinated seeds in a controlled experiment. Analysis: 1. The CR is higher in the germinating peas in the cold water rather than in the beads or non-germinating peas
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pull Gummy Bear out after two days and repeat steps 1-6 Results Day Bear Color Length Width Thickness Volume Mass Density 1 Red 2 cm 1 cm 1 cm 2.0 2 grams 1.0 2 Light Pink 5 cm 3.5 cm 2 cm 35.0 15.1 grams 4.31 Amount of change Lighter 3 cm 2.5 cm 1 cm 33.0 13.1 grams 3.31 Lab Notes Gummy Bear got larger as it sat in the water Gummy Bear got lighter as it sat in the water Conclusion Analysis My hypothesis was
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There are several purposes to the amino acid lab experiment. One reason is to help us understand the concept of acids and bases and how they interact with one another. Another purpose is to understand what occurs when placed with the existence of buffers. Lastly‚ the experiment is to help us understand the applications of titrations and how it can be used in a real world setting‚ in this case‚ the identification of an amino acid. One must understand that amino acids all have special characteristics
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In the Stoichiometry Challenge Lab we compared the theoretical results of the reaction between sodium carbonate (Na2CO3) and sulfuric acid (H2SO4) with the actual data we found. I hypothesised that If the mole ratio between Na2SO4 and H2SO4 is 1:1 then when I react 0.5 grams of Na2SO4 (reactant with H2SO4) I should get 0.669 grams of Na2SO4. The actual reaction between .05 grams of Na2CO3 and 5 mL of of H2SO4 produced 0.79g of Na2SO4. When I were testing the reaction‚ I measured out the reactants
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