"H2o2 decomposition" Essays and Research Papers

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    were used to fill the second and third test tubes‚ where distilled water was added to the second test tube and NAOH to the third test tube. Each test tube was let to set on the rack for 5 minutes‚ after which H2O2 was added to each test tube to the 7 cm mark. Each test tube was swirled post H2O2 addition and set on the rack for 20 seconds before measuring the height of the bubbles formed by the reaction.

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    catalyst because they are able to speed up reaction rates without being destroyed or altered. They are able to encourage chemical reactions by decreasing the energy of activation. The main function of enzyme catalase is to convert hydrogen peroxide (H2O2) in our bodies into oxygen and water. This can be visually seen when hydrogen peroxide is put on a wound and the peroxide bubbles. Enzymes can also be found in plant cells and fungi. (Huston.) In this experiment we test the many variables that can

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    Yocidophilus Case Study

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    with L. delbrueckii ssp. bulgaricus alone generated seven- to nine-fold higher quantities of H2O2 than those prepared with S. thermophilus alone or with both species .Marty-Teysset et al. [2000] reported that L. delbrueckii ssp. bulgaricus creates H2O2 mainly due to the action of NADH: H2O2 oxidase ‚ while the presence of S. thermophilus helps decompose H2O2 via NADH peroxidase ‚ an enzyme converting H2O2 into water to regenerate NAD+ [Smart & Thomas‚1987]. Rybka & Kailasapathy [1995] also observed

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    Abstract The aim of this experiment was to investigate the effect of temperature on the enzyme catalase. The original research question was exploring the effect temperature would have on a yeast catalase reacting with hydrogen peroxide (H2O2). To address the latter question a series of experiments were conducted. The various temperatures experimented with were as follows: 22 degrees Celsius (room temperature)‚ 0 degrees Celsius (freezing)‚ 100 degrees Celsius (boiling)‚ and 37 degrees Celsius.

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    Tahmaseb and poured a generous amount into the tube labeled D. We then took the 5 mL graduated cylinder and the dropper labeled “H” and started dropping drops of Hydrogen Peroxide or H2O2 until it measured 1 mL of H2O2. We then took that 1 mL of H2O2 and poured it in test tube labeled C‚ we then proceeded to measure 1 mL of water and also added it to the test tube labeled C. This would give us a 50% concentrate solution. Since we had 2 mL and only needed 1 mL of

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    Quantitative Analysis: % Copper in an Ore May 3‚ 2006 Abstract: In this experiment we were given an unknown sample of ore. Using the spectrophotometric analysis and the electrogravimetric analysis‚ we found the unknown percentage of copper in the unknown sample of ore was to be 17.6% by mass. Introduction: Chemical analysis takes place under two different scenarios. In one case‚ you need to find out the chemical identity of some material. The first kind of analysis‚ in which the chemical

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    steps 1-8(1.5% H2O2)‚ add 3 drops of 11.5 pH to the hydrogen peroxide before pouring it into the beaker with the paper towel. Do the same for 3 drops of 3.5pH. Again use the same concentration mix with 1.5% H2O2 and repeat steps 1-8‚ but this time place the concentration on a hotplate set at two. Start timer as soon as its on the hotplate. Repeat again steps 1-8 but the mixture will be .3g yeast to 5 mL glucose‚ incubation time is the same. With this mixture test 30mL 1.5% H2O2 and 3%‚ separately

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    temperature baths that were used to test the difference in enzyme activity on fresh liver were; 4 °C‚ room temperature which was 22°C‚ body temperature which is 37°C‚ and 77°C. The total time of each trial was 2 and a half minute‚ 1 minute for the H2O2 to acclimatize to the temperature‚ 1 and a half minutes for the reaction to occur. Catalase causes Hydrogen Peroxide to break down into water and oxygen. Therefore the difference of enzyme rate reaction was determined by putting liver into hydrogen

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    experiments as shown below: Experiment Materials 1 Add 1 small spatula of iron powder to 1cm3 distilled water followed by 4cm3 H2O2 2 Add 1 small spatula of iron filings to 1cm3 distilled water followed by 4cm3 H2O2 3 Add 4 iron nails to 1cm3 distilled water followed by 4cm3 H2O2 4 Add 1cm3 of liver tissue extract‚ 1cm3 distilled water followed by 4cm3 H2O2 5 Add 4cm3 H2O2 to 1cm3 distilled water followed by 1cm3 of liver tissue extract Results and observations: Experiment Observations 1 The iron

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    Formal Lab Report 2 Final

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    Purpose: Cells produce toxic wastes‚ in this experiment hydrogen peroxide‚ and without some sort of molecule to break it down the cell will die‚ along with the organism itself. However with the aid of an enzyme‚ catalase‚ hydrogen peroxide is able to be broken down into an intermediate and thereafter harmless substances water and oxygen. The goal of this lab is to measure the reaction rate of this process in different substances such as a liver‚ a vegetable‚ and breast tissue. By using variables

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