he number theory or number systems happens to be the back bone for CAT preparation. Number systems not only form the basis of most calculations and other systems in mathematics‚ but also it forms a major percentage of the CAT quantitative section. The reason for that is the ability of examiner to formulate tough conceptual questions and puzzles from this section. In number systems there are hundreds of concepts and variations‚ along with various logics attached to them‚ which makes this seemingly
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* MY FAMILY INCOME AND ITS MONTLY ALLOCATION MONTLY INCOME (RM) | NUMBER OF FAMILY MEMBERS | CATEGORIES | ALLOCATION OF INCOME (RM) | ALLOCCATION OF INCOME (%) | 600 | 3 | FOOD | 150 | 25.00 | | | UTILITY | 100 | 16.67 | | | TRANSPORTATION | 100 | 16.67 | | | EDUCATION | 150 | 25.00 | | | RECREATION | 50 | 8.33 | | | OTHERS | 50 | 8.33 | TOTAL | 600 | 100 | * PERCENTATION OF FAMILY
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English 101C- WB 10/04/12 Uncontrollable Numbers Today‚ magazines are causing uproar with targeting consumers with outrageous numbers to gain attention. Seeyle states‚ “A trip to the newsstand these days can be a dizzying descent into a blizzard of numbers.” Reading through the article‚ the author adventured through numbers in sales‚ and how people can be addicted to these certain number strategies. She claims that in most popular magazine distribution all numbers sell. Seeyle looks into most of many
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35/62 Answer: Probability = 35/62 This can be understood in a different way Let the number of games played be 100 Out of these 100 games‚ 70 games were played at night and 30 during day Out of 70 games played at night no of games won = 50% x 70 = 35 games and the number of games lost = 50% x 70 =35 Out of 30 games played during day‚ no of games won = 90% x 30 = 27 games and the number of games lost = 10% x 30 = 3 Thus total games won = 35 + 27 = 62 (Total games lost =
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p.m.‚ berries are no longer received. Rate of Arrival = 1500bbls/her = 20*75 = 1500 bbls/hour = 20 trucks/hr (since the average truck delivery is 75 bbls) Total number of trucks that arrived = 12 hours*(20 trucks/hr*70%) = 168 trucks Total waiting hours = Sum up (# Trucks Waiting (field/column shown above)) = 552 Average waiting number of hours per truck 552/168 = 3.28 hrs/truck Time # Trucks Waiting Berries waiting in bins Total berries waiting (trucks and bins) 7 a.m. 0 14 14 8
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Shouldice Hospital – A Cut Above 1.) How well is the hospital currently utilizing its beds? The hospital stay cycles have been provided: | Mon Beds | Tue Beds | Wed Beds | Thu Beds | Fri Beds | Sat Beds | Sun Beds | Available Beds | 90 | 90 | 90 | 90 | 90 | 90 | 90 | Monday Admission | 30 | 30 | 30 | | | | | Tuesday Admission | | 30 | 30 | 30 | | | | Wednesday Admission | | | 30 | 30 | 30 | | | Thursday Admission | | | | 30 | 30 | 30 | | Friday Admission | |
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TMAN 625 Midterm Exam‚ Spring 2012 Name Question 1 2 3 4 5 6 7 8 9 10 Late Total Score 0 0 0 0 0 0 0 0 0 0 0 0 Week 1 2 2 3 3 3 4 4 5 5 TVOM‐qualitative Annual Annuity Annual Loan Loan Annuity stocks verses bonds Discounted Payback PW‚ FW‚ AW IRR independent ‐ cost only IRR mutually exclisive TMAN625 Midterm Exam‚ Summer 2012 Name Eric D. Choi Question 1 2 3 4 5 6 7 8 9 10 Late Total Score 0 0 0 0 0 0 0 0 0 0 0 0 Question 1 Score 0 Explain where or when
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1. A sample of 20 employee’s salaries from a large company results in the following salaries (in thousands of dollars) for this year. 28 31 34 35 37 47 42 42 49 41 42 60 52 52 51 72 67 61 75 77. What is the interquartile range (in thousands) of this data set? (A) 21.5 (B) 10 (C) 50 (D) 23 (E) correct answer is not given 2. Please refer to the previous question. Suppose each employee in the company receives $3‚000 raise for next year. The interquartile range (IQR) of the salaries will: (A)
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be 1. 4. Suppose all possible investment opportunities in the world are limited to the five stocks listed in the table below. What does the market portfolio consist of (what are the portfolio weights)? Stock Price/Share ($) Number of Shares Outstanding (millions) A 10 10 B 20 12 C 8 3 D 50
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1 mm Trial 3 (±0.5 mm) 16.2 mm 17.2 mm 18.5 mm 20.3 mm 21.5 mm 23.1 mm 24.5 mm Notes • The starting temperature of the 200ml of water for all three trials was 30 °C. Processed Data ! ! ! ! ! Let T be the trial and a subscript the trial number. ! Averagelength of bubble = (T1 + T2 + T3) ÷ 3 At 30.0 °C ! Averagelength of bubble at 30.0 °C = (16.1 mm + 16.3 mm + 16.2 mm) ÷ 3 ! Averagelength of bubble at 30.0 °C = 16.2 mm Temperature 30.0 °C 40.0 °C 50.0 °C 60.0 °C 70.0 °C 80.0 °C 90.0
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