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    Surface Marking of Lung

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    to two inches above the anterior extremity of the first rib‚ and is indicated by a curved line drawn from the upper border of the sterno-clavicular articulation to the junction of the inner and middle thirds of the clavicle‚ the highest part of the curve being from 1/2 inch to 1 1/2 inches above the clavicle. The apex of the right lung is 1/2 inch higher than that of the left. The subclavian artery lies on the cervical pleura covering the apex of the lung. The anterior border of the right lung is

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    Julkj

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    center point and the petals are the elements that radiate in a circular fashion. This card fit into my theme of music because I used a music note as the center point. 2 - Movement Movement in design comes from the kinds of shapes‚ forms‚ lines‚ and curves that are used to give the illusion of movement or motion by directing the eye of the viewer from one part of the design or picture to other. I demonstrated movement in my card because I placed a banner of piano keys in a curved line across the top

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    Lesson 9: d-t & v-t Graphs Graphing the motion of objects gives us a way to interpret the motion that would otherwise be difficult. ● Graphs will also allow you to show a large amount of information in a compact way. Essentially you need to be able to sketch and interpret two main kinds of graphs in kinematics: 1. Displacement – Time Graphs ● Sometimes called d-t graphs‚ or position – time graphs. 2. Velocity – Time Graphs ● Sometimes called v-t graphs. Displacement - Time (d-t) Graphs

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    Psy of Art

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    Required book “the Structure of paintings” By Michael Leyton Easier to get an A by reading the book. The Final will be the only exam of the course. The final tests both the book and lectures notes The book will read by homework assignments. Homework assignments will be reading the book. IMPORTANT‚ never use ratemyprofessors.com for this class‚ because it damages the marking cm The course = The book Main Topics 1. How to read the composition of a painting 2. How the composition relates

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    Good Continuation

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    [pic] KAUNAS UNIVERSITY OF TECHNOLOGY INTERNATIONAL STUDIES CENTER Aesthetics in Product Design Good Continuation Student: Gintarė Plėtaitė‚ UA-6 Lecturer: Arvydas Palevičius Kaunas 2009 Content Introduction..........................................................................................................................3 What is the law of continuation?......................................

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    INTRODUCTION ABOUT ADOBE PHOTOSHOP TOOLS AIM: To study about the adobe Photoshop tools TOOLS: Marquee Tool: It makes rectangular‚ elliptical‚ single row‚ and single column selections. Move Tool: moves selections‚ layers‚ and guides. Lasso Tool: make freehand‚ polygonal (straight-edged)‚ and magnetic * (snap-to) selections. Magic Wand Tool: selects similarly colored areas. Crop Tool: trims images. Slice Tool: creates slices. Slice Select Tool: selects slices. Healing

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    Term Paper

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    5x  7 y  7  0 [4] 2. If x  3  5 ‚ express x  integers. 6 in the form p 3  q 5 when p and q are x [3] x 2  5x . 3 [4] 3. (a) Find the least integral value of x for which 1  x 2  (b) The straight line y=3p+1 intersects the curve y  x  points. Find the values of p. p2 at two distinct x [5] x 4. (a) Solve the equation log 2 ( x  8 )  log 4 9  1  log 2 ( ) [5] 4 5 a (b) Given that ( 3 2 x1 )  3( 5 x2 )

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    The Koch Snowflake

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    The Koch Snowflake Math Mock Exploration Shaishir Divatia Math SL 1 The Koch Snowflake The Koch Snowflake is a fractal identified by Helge Von Koch‚ that looks similar to a snowflake. Here are the diagrams of the first four stages of the fractal - 1. At any stage (n) the values are denoted by the following – Nn - number of sides Ln - length of each side Pn - length of perimeter An - Area of snowflake Mentioned below are the values of these above variables‚ for the first 4 stages

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    Methods of Projection

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    Methods of Projection I. Arithmetic Straight Line Yc = a + Yi – 1 Where: Yc = initial Value (1st year) Yn = Final Value (last year) N = number of years Yi = value for the year past a = Yn - Yc N – 1 = 5975147 – 5413182 5 – 1 = 140‚ 491.25 Historical Values |  |Y |a |Yi – 1

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    do not know an absolute result with any of the masses of the weight. Besides‚ if we used 0g as our control‚ the cart won’t even move. Hypothesis Under these conditions I believe that the results shown in the distance vs. time graph will have a curve showing increasing speed or in other words‚ increasing velocity over time. Therefore‚ the results shown in the velocity vs. time graph will have a positive linear slope. The acceleration vs. time graph will then have no slope and just a straight line

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