Preparation of the NaOH Solution Mass of NaOH before standing = NaOH before standing (g) – beaker (g) = 111.490 g – 110.970 g = 0.520 g Mass of NaOH after standing = NaOH after standing (g) – beaker (g) = 111.500 g – 110.970 g = 0.530 g Standardization of the NaOH solution TRIAL I Volume of NaOH solution = Final reading of buret - Initial reading of buret = 13.80 mL – 0.00 mL = 13.80 mL Converting the Volume (mL) to Volume (L) Volume (liters) = Volume (mL) x
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Drain cleaner is mostly made up of the strong base NaOH but also has other substances in it to efficiently clean a lodged pipe such as aluminum‚ sodium nitrate‚ and sodium chloride. All the homeowner ahs to do while using drain cleaner is to pour I down the clogged drain and maybe run some water‚ inside the pipe the chemicals go to work for you. But even though it sounds simple precaution must be taken in order to prevent injury to our body. NaOH must be produced correctly before it can be used
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because there was more mass to pull as more books were added. This shows newtons 1st law because the books wanted to stay at rest‚ but as more force was added they moved. The 2nd law is seen because the more mass there was‚ the more force was required to accelerate the books. The 3rd law is there because as you pull on the spring balance‚ it pushes pulls back on you‚ which lets it move. The eggs connect to the first law because the hard boiled egg is easier Egg 1 mass: 60.6 to start and stop‚ but the
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Germain Henri Hess (August 7‚ 1802–November 30‚ 1850) was a Swiss-born Russian chemist and doctor who formulated Hess’s Law‚ an early principle of thermochemistry. Born in Geneva‚ Switzerland‚ his father was an artist and in 1805 moved the family to Russia to find work. Beginning in 1822‚ Hess studied medicine at the University of Tartu. He qualified as a physician in 1825. Hess turned to chemistry after a meeting with Jöns Jakob Berzelius‚ the famous Swedish chemist‚ and went to Stockholm University
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Formula: for NaoH N NaoH = grm KHP / ml NaoH x KHp /1000ml Formula: for HCL (NV) HCL = (NV) NaoH or N HCL V HCL = N NaOH V NaoH N HCL = VNAOH (NNaoH) / VHCL (for more info page 62-63 of the photocopy) KHP = Potassium hydrogen phthalate = KHC8H4O4 = Mw - 204.23 Trial 1: NNaoH = 1grm / 20.6 x 204.23 /1000 = 1grm / 4.21 = 0.24 normal NHCL = 20.6 (0.24) / 39.5 = 4.94 / 39.5 = 0.125 or 0.13 Trial 2: NNaoH = 1grm / 20.8 x 204.23 /1000
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Erica Chan Sinh Nguyen Dat Nguyen Wed 2:00-5:00 02/19/2014 OHM’S LAW I. Purpose The purpose of this lab is to help understand how voltage‚ current and resistance are closely related to one another. The outcome from this lab is to be able to differentiate when to use ohmmeter and voltmeter for the individual circuit. II. Theory Ohm’s Law states that the electric current through a material is directly proportional to the voltage across a piece of material (such as wire) while the resistance is held
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Lab: Newton’s Law of Motion Section #: 404 Group #: 3 Experiment #: 3 Date :October 16‚ 2012 Newton’s Law of Motion Your signature indicates that you have completely read the entire report and agree with everything here in. Failure to sign will result in a zero for your personal grade unless a formal exception is filed with your TA. Please Print and Sign Full Name Principal investigator: Skeptic ________________________________________________________ Researcher:
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Hess’s Law and the Molar Enthalpy of Combustion for Magnesium Purpose: The purpose of the lab ultimately is to find the molar enthalpy of magnesium. This is done by finding the enthalpy changes of reactions (2) and (3). The enthalpy changes of reactions (2) and (3) along with the enthalpy change given for reaction (4) can be used to arrive at a value of the molar enthalpy of combustion of magnesium by using Hess’s Law. Hypothesis: By using Hess’s law to calculate the molar enthalpy of combustion
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Lab 2: Reaction Order and Rate Laws Khadijah Maraheel Location: My apartment September 27th-28th 2017 Course Number: Chem112 Abstract: The purpose of this lab is to find the rate law of the reactants and the reactions order. My beginning thought was I would find whole numbers but that would be to easy. My answers were all with decimals. I found that my rate law Is k (HCl)1.36 (Na2S2O3)0.84. I was expecting the solution to change color but I never thought it would turn
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tubes * Put 2mL of 40% NaOH solution to test tubes 1‚ 2 and 3 and on test tubes 4 and 5‚ put 10% NaOH solution * Add 10 drops of the following solution: * Tube 1: formaldehyde * Tube 2: benzaldehyde * Tube 3: acetaldehyde * Tube 4: acetaldehyde * Tube 5: acetone * Transfer all test tubes in a boiling water bath for 10 minutes * Record all observations Results: Sample | NaOH | Observations | 1. Formaldehyde | 40% NaOH | Alcohol-like odor |
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