Chemistry 1211 Prof. Dan Schwartz Exam #2 Thursday‚ 3/13/2003 7:00 – 8:30 P.M. There is a single correct choice for each question. Answer all questions on the Scantron sheet by filling in the proper bubble with a #2 pencil. If you change an answer‚ erase the undesired mark thoroughly. Be sure to fill in the boxes for your student number‚ name and lab section; then correctly fill in the corresponding bubbles beneath them. A periodic table and other useful information are attached to the back
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until it is equal to 0.275 atm‚ what would the new volume of that gas be? 5) Atmospheric pressure on the peak of Mt. Everest can be as low as 150 mm Hg‚ which is why climbers need to bring oxygen tanks for the last part of the climb. If the climbers carry 10.0 liter tanks with an internal gas pressure of 3.04 x 104 mm Hg‚ what will be the volume of the gas when it is released from the tanks? 6) Part of the reason that conventional explosives cause so much damage is that
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f f fg gf gf f gdgfdgfd gfdgfdgfdgfd gfdg fdg dfg dfgfg dfg fdg g r tre trjw ykuted n JULS H R‚ LUT‚ gj hgmfgbnhgnvcn h g f gf h h h hg hg hg hg h hj j y gfd vx j kh i ut yr t sf sf h k k uk u r re sd u i o iuy tr yui j hg f y i o uy tf f ghjk l kj hygtfd John F Kennedy’s Death Was a Plan Jessica Moon Mrs. Zoch English 10 Period 1 11 February 2014 I. Introduction
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ELECTROLOYSIS OF WATER: DETERMINATION OF THE FUNDAMENTAL ELECTRONIC CHARGE PURPOSE: The fundamental electronic charge of water will be determined. A system of collecting the formation of H2 and O2 using two inverted glass collections tubes and a 1-L beaker filled with water will be setup. An electrolyte (H2SO4) will be added to water to make it an electrical conductor. A small amount of electricity will be applied to the water (roughly 400 mA) to oxidize the oxygen and reduce the hydrogen
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The P/E ratio (price-to-earnings ratio) of a stock is a measure of the price paid for a share relative to the annual net income or profit earned by the firm per share. It is a financial ratio used for valuation. P/E ratio shows current investor demand for a company share. P/E ratio has units of years. P/E is the most popular metric of stock analysis. The reciprocal of the PE ratio is known as the earnings yield. There are various P/E ratios‚ all defined as:
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stand promoting one choice over the other? C. STAKEHOLDERS Shirley Rickert –Chief Financial Officer of HGS Carl Switzer – Chief Executive Officer of HGS Scott Beckett – Vice President‚ HGS Oil and Gas Product Division Walter Albright – Vice President‚ HGS Research and Development Jerry Tucker – Senior R&D Scientist of HGS Brian Hanrahan – Senior Financial Analyst of HGS D. COURSES OF ACTION 1. Shirley should take side with Scott Beckett in not considering selling Plastiwear
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Does Exercise Affect Blood Pressure and Heart Rate? Hypothesis If an individual is put through vigorous exercises‚ then his/her blood pressure and heart rate will be affected because of the increase in activity. Dependent Variables Heart Rate (measured in bpm) Blood Pressure (measured in mmhg) Independent Variables Height Weight Physical Fitness Speed on completing exercise Controlled Variables Types of Exercise Materials Cufflink Heart Monitor Test Subjects 1-5 Procedure
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------------------------------------------------- ------------------------------------------------- ------------------------------------------------- ------------------------------------------------- ------------------------------------------------- ------------------------------------------------- ------------------------------------------------- Molar Volume of a Gas Lab Report ------------------------------------------------- ------------------------------------------------- -------------------------------------------------
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high-copper alloys • Dispersalloy (Caulk) – admixture of spherical Ag-Cu eutectic particles with conventional lathe-cut – eliminated gamma-2 phase Classification According to content – Silver amalgam: Silver more than 65% – Copper amalgam: 70% Hg and 30% Cu According to presence or absence of Zn Zinc containing alloys – more than 0.01% Zn Zinc free alloys – less than 0.01% Zn Classification • According to Copper content – Low copper alloys (2-4-6% Cu) – High copper alloys (9-30% Cu)
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However in example 6‚ the H2O molecule given in the question is in the liquid state. Thus liquid water has to be converted into steam first. To convert 2 moles of liquid water into 2 moles of steam‚ an additional 82 kJ of energy is required. By using Hess’s Law‚ ΔH + 2(799) + 2(41) + 4(460) = 4(410) + (496) ΔH = -888 kJ mol-1 Alternative: energy absorbed during bond breaking = 4(410) + 2(496) = 2632 kJ energy released during bond forming = 2(799) + 4(460) + 2(41)
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