INTRODUCTION For this experiment we studied an oxidation-reduction reaction of magnesium and hydrochloric acid solution. We compared the experimental measured amount of a product and the amount predicted by the theoretical calculation of a balanced equation: Mg (s) + 2HCl (aq) → MgCl2 (aq) + H2 (g) PROCEDURE First we obtained a strip of pre-cut magnesium ribbon‚ cleaned it with steel wool to remove any signs of oxidation from the strip (which would alter our results)‚ and then weighed it (individual
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Week 10: Oxidation and Reduction Reactions: The Reactions of Copper Data: Part I: Preparing a solution of copper (II) nitrate Initial mass of copper wire: .520g Mass of copper wire after vigorously scouring: .518g Observations of Copper (II) ribbon mixed with HNO3: Solution turned green. Thick brown gas formed. Copper (II) bubbled vigorously. Cu (II) dissolved‚ solution appeared green/blue. After the addition of H2O a blue crusty precipitate formed. Part II: Synthesis of solid copper
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“Kinetics of Ethanol Oxidation” laboratory experiment utilized Beer’s law and spectroscopy to monitor concentration and the rate of ethanol oxidation through the LoggerPro System. This data then helped determine the kinetic rate constant‚ k‚ and the order of the reaction. First‚ the wavelength of maximum absorbance was determined using the LoggerPro interface and a Vernier colorimeter. Beer’s law was then used to determine the molar absorptivity. Finally‚ a kinetic study of ethanol oxidation was completed
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Acidity’s effects on Fruit Browning Aim: To test whether the acidity of the surface area of an apple has an effect on the rate of enzymatic browning over 70 minutes. Hypothesis: the more acidic the surface area the longer it takes for the fruit to oxidise. Variables: Independent: acidity of surface area of the apple Dependent: the progression of melanin (brown pigment) after 70 minutes Controlled/fixed: time of day‚ knife used to cut fruit‚ portion of fruit‚ environment
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Bleach Oxidation of 9-Hydroxyfluorene The purpose of this experiment was to oxidize an alcohol (9-hydroxyfluorene) to a ketone (9-fluorenone) using aqueous sodium hypochlorite (bleach) as the oxidizing agent‚ while introducing techniques used in microscale experiments. Reaction: Results 1. Recrystallized Product Yield Product yield = (actual yield/theoretical yield) x 100% 3mL 9-hydroxyfluorene x (1mL/1000mL) x (0.09 mol/L) = 2.7 x 10-4 moles 0.05g 9-fluorenone / (180.20g/mol) = 2.77 x 10-4
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Illustrating the Oxidation States of Mn & V © KCl http://hk.geocities.com/fatherofchemistry Procedure © KCl http://hk.geocities.com/fatherofchemistry Discussion Part A: Making Mn(VI) from Mn(VII) and Mn(IV) 1.> Explain why only one of the three mixtures reacted to give green Mn(VI). [ANS] By Le Chatelier’s Principle‚ only the alkaline medium will shift the equilibrium to right and yield green MnO42-. 2.> What happened when acid was added
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Purpose: The purpose of this lab is to identify the different features that come about by using oxidation reduction and recording the observations‚ these tests will help determine the specific qualities each solution has. Materials: 1 Paper towels 1 Well-Plate 1 Tweezers‚ plastic Experiment Bag Oxidation-Reduction Activity Series 1 Copper (II) Sulfate‚ 1 M - 3 mL in Pipet 1 Iron (III) Chloride‚ 2 M - 3 mL in Pipet 1 Iron Metal‚ 2 pc in Bag 2"x 3" Magnesium Metal (ribbon) - 2 Small Pieces in Bag
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(FAs) can ultimately be degraded through different pathways which include alpha‚ beta‚ and omega-oxidation. Alpha-oxidation occurs at carbon 2 of the chain‚ b-oxidation at C3‚ and omega-oxidation at methyl end of the fatty acid. The location of each mechanism also differs as alpha- oxidation occurs in peroxisomes only‚ beta-oxidation can take place in both peroxisomes and mitochondria. Omega-oxidation occurs in the endoplasmic reticulum of the various tissues. The importance of the differentiation
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8.07 Work File: Oxidation Reduction Reactions 1. What is the difference between an oxidizing agent and a reducing agent? The oxidation number (overall charge of the atom) is reduced in reduction and this is accomplished by adding electrons. The electrons‚ being negative‚ reduce the overall oxidation number of the atom receiving the electrons. Oxidation is the reverse process: the oxidation number of an atom is increased during oxidation. This is done by removing electrons. The electrons‚ being
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moles/1000 mL = .0005 moles/10 mL = moles of hydroxylammonium chloride Ratio of Fe+2 to NH3OH+ = 2:1 2e- + 2Fe+3 --> 2Fe+2 so transfer of 2 electrons NH3OH+ --> something + 2e- Oxidation number of N in NH3OH+ is -1‚ therefore the oxidation number for N on the product side must be +1 because it gains 2 electrons. N2O has an oxidation number of +1 for N‚ so that would work. Data:Equation 1: NH3OH+ + 2Fe+3 --> something + 2Fe+2 Equation 2: 8H+ + 5Fe+2 + MnO4- --> 5Fe+3 + Mn+2 + 4H2O Equation 3: 6H+ +
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