Thermodynamics- Enthalpy of Reaction and Hess’s Law Objectives: 1. To calculate the heat of reaction of a given reaction using the concepts derived from Hess’s Law. Pre-lab Questions: 1. Define Heat of Reaction. The enthalpy change associated with the completion of a chemical reaction. 2. Define Specific Heat. The energy it takes to raise the temperature of 1 gram of a substance by one degree Celsius. 3. Calculate the heat of reaction assuming no heat is lost to the calorimeter. Use correct
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Thermodynamics is the branch of science concerned with the nature of heat and its conversion to any form of energy. In thermodynamics‚ both the thermodynamic system and its environment are considered. A thermodynamic system‚ in general‚ is defined by its volume‚ pressure‚ temperature‚ and chemical make-up. In general‚ the environment will contain heat sources with unlimited heat capacity allowing it to give and receive heat without changing its temperature. Whenever the conditions change‚ the thermodynamic
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EXERCISE: Diffusion and Osmosis Laboratory Objectives After completing this lab topic‚ you should be able to: 1. Describe the mechanism of diffusion at the molecular level. 2. List several factors that influence the rate of diffusion. 3. Explain why diffusion is important to cells. 4. Describe a selectively permeable membrane‚ and explain its role in osmosis. 5. Define hypotonic‚ hypertonic‚ and isotonic in terms of relative concentrations of osmotically active substances. 6. Discuss
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Ronald Wilson Pd:4th 11/16/12 Introduction In this experiment diffusion and osmosis is the main idea. When using diffusion and osmosis you are trying to separate different solute concentrations on either side of the membrane. Only a solute’s relative concentration‚ or water potential‚ affects the rate of osmosis. The higher the concentration of solutes‚ the faster water will flow through the membrane to equalize the concentration. The way we describe the movement from higher to lower concentration
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Addictive substances are becoming Substance abuse and addiction can changes ones life drastractly. To me substance abuse is when one over uses or depends on an addictive substance‚ and can not find a way to get away from it. Substance addiction is different than substance abuse and to me it means when someone out of control‚ which leads to harmful consequences. Many can say my siblings and I was ”sheltered” as children‚ but I believe my parents raised my three brothers and myself without bringing
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Lab Activity No. __ Diffusion and Osmosis I. Introduction Diffusion is the transfer of molecules (or ions) from an area of higher concentration to a lower concentration‚ while osmosis is the transfer of water from a higher concentration to a lower concentration. II. Objectives 1. Demonstrate diffusion and osmosis across membrane. 2. Examine the relation of membrane permeability to diffusion and osmosis. III. Materials 2 thistle tubes‚ 2 big beakers‚ 4 tube clamps to fit iron stands
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Example 1 Nozzle Flow - Steam Steam at 1.5 bar and 150 deg C enters a nozzle at 10 m/s and exits at 1 bar. Assuming the flow is reversible and adiabatic‚ determine the exit temperature and velocity. If the exit nozzle area is 0.001 m2‚ evaluate the mass flow rate of the steam through the nozzle. P1 = 1.5 bar T1 = 90 deg C V1 = 10 m/s A2 = 0.001 m2 P2 =1 bar T2 = ? V2 = ? mdot = ? V2 = sqrt(V1*V1+2*(h1-h2)) mdot = rho*A2*V2 = A2*V2/v2 T2 382.60 m/s 0.22 kg/s 111.81 degC Superheated
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Title : The application of Thermodynamics In Industry. Student Names Student ID’s MUHAMAD NORSAM BIN HASHIM 2012901165 SYAFIQ BIN SULAIMAN 2012503549 Lecture Name : ASNIDA YANTI ANI Date of Submission : 3/9/2014 Introduction: Thermodynamics is an exciting and fascinating subject that deals with energy‚ which is essential for sustenance of life and thermodynamics has long been an essential part of engineering and science all
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Thermodynamics-Enthalpy of Reaction and Hess’s Law Purpose To demonstrate the principle of Hess’s Law and to find the heat capacity of the coffee cup calorimeter using three different reactions. Data Tave = (46.4-45.2)/2 = 45.8 qwater = -(100g)(4.184)(46.56-45.8) = -318 J Ccal = 318J/(46.56-21.2) = -12.53J/g*C Tinitial = (27.1+23.8)/2 = 25.45 qrxn = -(100g)(4.18)(38.43-24.45)+(-12.53x12.98) =-5400J/.1mol(1J/1000kJ) = -54.0 kJ/mol Tinitial = (26.0-24.5)/2 qrxn =-(100g)(4
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APPLICATION OF THERMODYNAMICS THERMODYNAMIC OF GASES (ADIABATIC CHANGE) In thermodynamic of gases‚ we can study about the changes to the internal energy of gas and factors affecting the internal energy. Thermodynamic also involves work done and heat supplied or lost by a gas. THERMODYNAMICS The study of temperature‚ heat‚ and related macroscopic properties comprises the branch of physics. Thermodynamics deals with processes which cause energy changes (internal energy) as a result
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