reveals any potential problems Hard Stop Good for patient safety Hard Stop Bad for slowing down process‚ lowering efficiency Insurance check was done after DUR. Checking to make sure insurance still valid‚ script matches drugs on formulary‚ customer not trying to refill too soon‚ etc. In most cases‚ script would still be filled even if there was a problem with insurance - customer would simply be told to pay full amount at pickup. Potential Data Entry Problems: Tech couldn’t read handwriting
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Any Phone in India. No Hidden Fees. Try for Only $2!www.PhoneIndia.com * LED Lights WholesalerAll LED Light with CE Certification Export to >100 countries. Buy Now!www.ChineseLight.com * Multichannel BankingInnovate with CR2 ’s latest solution for ATM‚ Internet & Mobile bankingwww.CR2.com Popular Articles About Core Banking BHUBANESWAR Now‚ post offices to have core banking facilities October 10‚ 2009 | TNN BHUBANESWAR: Post offices will no longer use age-old methods of transferring
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9‚ 10 4‚ 8‚ 9‚ 10 6‚ 7‚ 10‚ 11‚ 13‚ 14‚ 15 5‚ 6 *6. Sale-leaseback. 20 12 15‚ 16 7‚ 8 *This material is dealt with in an Appendix to the chapter. ASSIGNMENT CLASSIFICATION TABLE (BY LEARNING OBJECTIVE) Learning Objectives Brief Exercises Exercises Problems 1. Explain the nature‚ economic substance‚ and advantages of lease transactions. 2. Describe the accounting criteria and procedures for capitalizing leases by the lessee. 1‚ 2‚ 3‚ 4 1‚ 2‚ 3‚ 5‚
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ESSAY SCAFFOLD WHY WAS THE WHITLAM GOVERNMENT DISMISSD? INTRODUCTION Answer the question and outline your arguments in support. eg. The Whitlam Government was dismissed by the Governor-General‚ Sir John Kerr‚ on 11 November‚ 1975. There were a number of reasons why the dismissal occurred. These included the growing unrest in Australian society brought about by the failing economy; the growing unpopularity of the Labor government brought about by its spending and economic policies‚ and the
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1. Solution is a homogeneous mixture composed of only one phase. In such a mixture‚ a solute is a substance dissolved in another substance‚ known as a solvent. Suspension is a heterogeneous mixture in which the particles are large enough to be seen by a microscope or the unaided eye and eventually‚ they settle out of the mixture. A colloid is a substance microscopically dispersed throughout another substance. Unlike colloids‚ suspensions will eventually settle. The suspended particles are visible
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E-Commerce Solution “Key Process” GROUP MEMBERS Deepak Subedi Pankaj Pokhrel Regan Shrestha Saurav Shrestha Roshan Magar Urmila Suwal Key Process Technology Requirement Hardware Software Security Maintenance Back end system Supply sources Distribution channels Supply sources Supply sources •Integration of key business process from end user through original supplier that provide products‚ services and information that add value for customers. •Some of world class companies such
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CHAPTER 7 CORPORATIONS: REORGANIZATIONS SOLUTIONS TO PROBLEM MATERIALS Status: Q/P Question/ Learning Present in Prior Problem Objective Topic Edition Edition 1 LO 1 IRS Letter Ruling Unchanged 1 2 LO 1 Reorganizations follow tax law Unchanged 2 3 LO 1 Types of reorganizations Unchanged 3 4 LO 2 Comparing like-kind exchange to corporate New reorganization 5 LO 2 Four-column template Unchanged 5 6 LO 1‚ 2‚ 3 Reorganization: tax attributes Unchanged 6 7
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“Suggested Solutions to Exercise” in Financial Accounting for Management by Ramachandran & Kakani Authored by Ram Kumar Kakani‚ “Copyright with Tata McGraw Hill Education Private Limited‚ 2011” CHAPTER 2 Balance Sheet Note: Answers to only half the questions have been provided. It gives you an opportunity to work on the rest problems and discuss about the relevant solutions. You are requested to complete this chapter before attempting the questions. MULTIPLE CHOICE QUESTIONS 1. 2. 3. 4. 5. 6. 7
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answers to the following questions. (a) If events A and B are mutually exclusive and collectively exhaustive‚ are Ac and Bc mutually exclusive? Solution Ac ∩ Bc = (A ∪ B)c = Ωc = ∅. Thus the events Ac and Bc are mutually exclusive. (b) If events A and B are mutually exclusive but not collectively exhaustive‚ are Ac and Bc collectively exhaustive? Solution Let C = (Ac ∪ Bc )c ‚ that is the part that is not contained in Ac ∪ Bc . Using De Morgan’s Law C = A ∩ B = ∅. Thus‚ there is nothing that is
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the message signal frequency is ωm. (a) Determine the modulation index m. Solution: Amax = 25 Amin = 5 − 25 − 5 = = 0.67 + 25 + 5 (b) Write an expression for the modulated signal φ(t). Solution: 1 1 ) = (25 − 5) = 10 = ( − 2 2 1 1 ) = (25 + 5) = 15 = ( + 2 2 = + cos = cos + ( ) cos Assignment 1 Sol Page: 1 of 12 = 15 cos + 10 cos cos (c) Derive time domain expressions for the upper and lower sidebands. Solution: = 15 cos + 10 cos cos = 15 cos + 5 cos( + ) + 5 cos( − ) Upper sideband: 5 cos(
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