Exercise 36 1. The researchers found a significant difference between the two groups (control and treatment) for change in mobility of the women with osteoarthritis (OA) over 12 weeks with the results of F(1‚ 22) = 9.619‚ p = 0.005. Discuss each aspect of these results. The F-value is high enough at the 5% level of significance to suggest a significant difference between the control and treatment groups. The p-value 0.005 < 0.05 hence this suggests a rejection of the null hypothesis
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EXERCISE 36 Questions to be graded 1. The researchers found a significant difference between the two groups (control and treatment) for change in mobility of the women with osteoarthritis (OA) over 12 weeks with the results of F(1‚ 22) = 9.619‚ p = 0.005. Discuss each aspect of these results. * The F-value suggests that there is a significant difference between the results of the control and treatment groups. The P-value of 0.005 is < the alpha of 0.05. This suggest that the groups are significantly
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1. The researchers found a significant difference between the two groups (control and treatment) for change in mobility of the women with osteoarthritis (OA) over 12 weeks with the results of F(1‚ 22) 9.619‚ p 0.005. Discuss each aspect of these results. Answer: Since the F value is significant‚ based on the p-value of 0.005 which is less than 0.05 which is sufficient to reject the null hypothesis. This suggests that there is a difference in the control and treatment groups. 2. State the null
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Marcia Landell Applied Statistics Week 6: Analysis of Variance (ANOVA) Exercise 36 Analysis of Variance (ANOVA) I 1. A major significance is identifiable between the control group and the treatment group with the F value at 5% level of significance. The p value of 0.005 is less than 0.05 indicating that the control group and the treatment group are indeed different. Based on this fact‚ the null hypothesis is to be rejected. 2. Null hypothesis: The mean mobility scores for the control group and
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EXERCISE 36 6. Can ANOVA be used to test proposed relationships or predicted correlations between variables in a single group? Provide rationale for your answer. ANOVA cannot be used to test proposed relationships or predicted correlations between variables in a single group because it is designed to test for correlations and interactions amongst groups‚ i.e. in the test group of patients with OA you are testing the correlations between those who do not use GI and PMR and those that do. Although
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Questions to be Graded 1. What are the two groups whose results are reflected by the t ratios in Tables 2 and 3? Answer: The two groups that are reflected by the t rations in table 2 and 3 are the Program effects of cardiovascular risk factors (Table 2) and program effect on Health behavior (Table 3). 2. Which t ratio in Table 2 represents the greatest relative or standardized difference between the pretest and 3 months outcomes? Is this t ratio statistically significant? Provide a rationale
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Researchers routinely choose an alpha level of 0.05 for testing their hypotheses. What are some experiments for which you might want a lower alpha level (e.g.‚ 0.01)? What are some situations in which you might accept a higher level (e.g.‚ 0.1)? EXERCISE 20 Questions to be Graded 1. Which patient scored the highest on the preoperative CVLT Acquisition? What was his or her T score? 2. Which patient scored the lowest on postoperative CVLT Retrieval? What was this patient’s T score? 3. Did the patient
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Name: Zipporah Gachoya Class: HLT 362V Date: 08/10/2013 ■ Ex Questions to be graded: Exercise 31 6. What is the smallest‚ significant t ratio listed in Table 2? Provide a rationale for your answer. t = 2.03* the smallest t ratio listed in Table 2. It indicates that the cholesterol level change was statistically significant from pretest to 3 months. It is greater than the given value of p<0.05 7. Why are the larger t ratios more likely to be statistically significant? They
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Exercise 36 Answers 1. Since the F value is significant‚ based on the p-value of 0.005 which is less than 0.05 which is sufficient to reject the null hypothesis. This suggests that there is a difference in the control and treatment groups. 2. Since the p- value is less than 0.05 and therefor the null hypothesis can be rejected. This presents that the mean‚ difficulty and mobility scores‚ must be different 3. The result was statistically significant with a probability score of p < 0.001.
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EXERCISE 36 Questions to be Graded 1. The researchers found a significant difference between the two groups (control and treatment) for change in mobility of the women with osteoarthritis (OA) over 12 weeks with the results of F (1‚ 22) = 9.619‚ p = 0.005. Discuss each aspect of these results. Answer: The F value suggests there is a significant difference between the results of the control and treatment groups. The P-value of 0.005 is < the alpha of 0.05.This suggest that the groups are significantly
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