formula. To determine the molecular formula of a compound‚ we need to know both the empirical formula and the molar mass of the compound. Benzene‚ for example‚ has an empirical formula of CH. In a molecule of benzene‚ the number of carbon atoms (C) and hydrogen atoms (H) are the same. The molar mass of benzene is 78.11 g/mol. We can determine the molecular formula of benzene by first calculating the molar mass of the empirical formula‚ which is 13.02 g/mol. We then determine the number of empirical units
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Discussion The reactivity series is a list of metals arranged in order of their reactivity based on displacement reactions‚ reduction of their oxides by hydrogen or carbon‚ the relative ease of decomposition of their compounds and reactions with oxygen‚ dilute acids and water. The higher up a metal is in the reactivity series‚ the more reactive it is. In the experiment conducted‚ the three metals‚ magnesium‚ zinc and copper each had to undergo displacement reactions and reactions with water‚ oxygen
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Amrita VISHWA VIDYAPEETHAM (University established u/s 3 of UGC Act 1956) Amrita Entrance Examination – Engineering PHYSICS‚ CHEMISTRY & MATHEMATICS Question booklet Version Code Question booklet no. Number of pages Number of questions Time 120 : 3 hrs Max. Marks : 360 Registration number Name of the candidate Signature of the candidate INSTRUCTIONS TO THE CANDIDATES GENERAL 1. Any malpractice or attempt to commit malpractice in the examination hall will lead
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The prescribed procedure produced nylon. The initial indication that nylon was being formed was through the combination of 0.02M of sebacoyl chloride in hexane and 0.05 M 1‚6 hexanediamine. Due to the fact there was an evident product formed after the combination of these two solutions‚ this simply shows that nylon was produced. The prescribed procedure produced nylon due to the fact that there was a present product of the reaction within the IR spectrum. The main peaks of frequency for the unknown
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an isomer‚ differs from (1^H) in that: 3^H has 2 more neutrons than 1^H Nitrogen has 7 electrons and thus can form a maximum of ___ covalent bonds with other elements 3 Carbon has 6 electrons while hydrogen has 1 electron. How many covalent bonds can form between a carbon atom and hydrogen atoms 4 In the lab you are culturing human cells in order for the cells to survive they must be cultured in a solution containing 25 mM glucose. You must make 500 ml of this solution. First‚ calculate
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will dissolve in the hydrochloric acid to produce hydrogen gas. This is because magnesium is higher than hydrogen in the reactivity series. Therefore‚ when the two reactants are combined‚ a displacement reaction occus and the magnesium displaces the hydrogen‚ forming magnesium chloride and hydrogen gas. Mg (s) + 2HCl (aq) -> MgCl 2 (aq) + H 2 (g) Magnesium + Hydrochloric acid -> Magnesium Chloride + Hydrogen Aim The aim of this investigation is to observe
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Reactions of pyridine Introduction: 1. Pyridine structure: 2. Iupac name: Pyridine‚ other name: Azine & Azabenzene. *Important commercial alkyl pyridinium compound is α - methyl- pyridine (2)‚ βpicoline (3)‚ γ- picoline ( 4 ) ‚ 2‚6 - lutidine ( 5 ) ‚ 3‚5 - dimethyl- pyridine ( 6 ) ethyl-2 - methyl- pyridine ( 7 ) and 2‚4‚6 - collidine ( 8 ) . In general‚ the alkyl -substituted pyridine as many other precursors used in pyridine E-commerce. From these further alkyl substituted pyridine
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Elements Atomic No At. Mass Valency Elements At.No. At.Mass Valency Hydrogen(H) 1 1 (+1) Silicon(Si) 14 28 (+4) Lithium(Li) 3 7 (+1) Germanium(Ge) 32 73 (+4) Sodim(Na) 11 23 (+1) Tin(Sn) 50 119 (+4‚+2) Potassium(K) 19 39 (+1) Lead(Pb) 82 207 (+4‚+2) Rubidium(Rb) 37 85 (+1) Nitrogen(N) 7 14 (-3‚+5) Cesium(Cs) 55 133 (+1) Phosphorus(P) 15 31 (+3‚+5) Francium(Fr) 87 223 (+1) Arsenic(Ar) 33 75 (+3) Beryllium(Be) 4 9 (+2) Antimony(Sb)
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Gases PURPOSE This experiment has two parts. The purpose of part A of the experiment is to determine the atomic mass of a metallic element whereas the purpose of part B of the experiment is to determine the rate of diffusion of both gases hydrogen chloride and ammonia by measuring the distances travelled by the two gases in the same time period. For part A the reaction of the metal with the aqueous acid is as follows: M(s) + n H3O+ -----> M+n(aq) + n/2 H2(g) + n H2O EQ.1
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CSEC CHEMISTRY NOTES ON PERIODIC TRENDS From Chemistry for CSEC by Tania Chung-Harris and Mike Taylor Chemistry for CAPE by Susan Maraj and Arnold Samai Periodic Trends in Group II Elements in Group II The elements in Group II are called alkaline earth metals. Be‚ Mg‚ Ca‚ Sr‚ Ba‚ Ra Beryllium‚ Magnesium‚ Calcium‚ Strontium‚ Barium‚ Radium These elements bond by metallic bonds (intramolecular forces) to form giant metallic structures. The size of the
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