In my coursework I will investigate about enzymes in potatoes reacting with Hydrogen Peroxide. In particular I will investigate the effects of changing the surface area of a potato when added to Hydrogen Peroxide. This is because‚ when increasing the surface area of the potatoes it will increase the rate of reaction because there will be more surface area on which particles from the potato and the Hydrogen Peroxide will collide on‚ and with more surface area there would be more particles carrying
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Determination of the Enthalpy for Decomposition of Hydrogen Peroxide Objective: To construct a coffee cup calorimeter‚ measure its calorimeter constant‚ and determine the enthalpy of decomposition and formation of hydrogen peroxide. Background: This experiment is a classic thermodynamics lab. In it‚ we attempt to measure the enthalpy (H) of a chemical reaction. The main obstacle is that this is a quantity that cannot be measured directly. It instead is observed as heat from one substance is transferred
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Biology investigation: Liver and hydrogen peroxide By Cuong Tran Abstract: The purpose of this investigation was to determine the optimum temperature for enzyme activity. The stated hypothesis was that 37oC would be the optimum temperature for liver enzymes to break down hydrogen peroxide into water and oxygen. The dependent variable was to measure the amount of foam being produced‚ while testing 4 different temperatures with 3 repetitions each. Out of the 12 trials only 2 outliers were found
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Chemistry Catalyst Report Aim I am trying to investigate the effect of the mass of magnesium dioxide used on the speed of the reaction of 2H2O2(aq) 2H2O(l) + O2(g). I hypothesize that the speed of the reaction is proportional to the rate of decomposition. Independent Variable The mass of MnO2 used Dependent Variable The rate of decomposition through the amount of mass lost Controlled Variables Environment of the experiment Stay in the same place to carry out the experiment and finish the
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when combined with hydrogen peroxide? Aim: To see find out how the amount of catalase correlates with the amount of gas created when in combination with hydrogen peroxide. Materials: 15g of liver 25 ml of hydrogen peroxide 1 scale 1 bucket 1 100ml graduated cylinder 1 250ml flask with bung 1 50cm tube (able to fix onto top of flask) 1 stopwatch 1 100ml beaker 1 funnel 1 pipette 1 microscopy kit Variables: Independent: This is the amount of liver added to the hydrogen peroxide. The initial weight
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First recognized as a chemical compound in 1818‚ hydrogen peroxide is a clear‚ colorless liquid most often used for cleaning or disinfecting(Britannica‚ 2013). Since pure hydrogen peroxide is unstable‚ it is found in stores as an aqueous solution. The chemical formula for hydrogen peroxide is H₂O₂ which means there are two hydrogen atoms and two oxygen atoms in the compound(Liebeskind‚ 2013). Seed germination is simply the process in which a seedling sprouts from a seed and begins it’s growth. The
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investigate the factors that affect the rate of reaction of the enzyme catalyse‚ an enzyme found in food such as potato and liver. Catalyse is used to remove hydrogen peroxide from cells. The enzyme speeds up the rate of decomposition of hydrogen peroxide into water and oxygen. The reaction is: Catalyse is able to speed up the process because the enzyme lowers the activation energy of the reaction. This means that the free energy required for the reaction to take place is made smaller by the presence
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Aim: To investigate the effect of hydrogen peroxide concentration on enzyme catalase Indroduction: Enzymes are proteins. They function as biological catalysts. They lower the energy barrier of a reaction so that the reaction can take place at body temperature. Also‚ they can speed up Metabolic reactions without being changed or used up. During a reaction‚ an enzyme molecule combines temporarily with the substrate. When the reaction is complete‚ the enzyme molecules returns to its original dorm
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What happens? For many reactions involving liquids or gases‚ increasing the concentration of the reactants increases the rate of reaction. In a few cases‚ increasing the concentration of one of the reactants may have little noticeable effect of the rate. These cases are discussed and explained further down this page. Don’t assume that if you double the concentration of one of the reactants that you will double the rate of the reaction. It may happen like that‚ but the relationship may well
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Decomposition of Hydrogen Peroxide by Potassium Iodide Brief Description: Two solutions are mixed resulting in an eruption of foam resembling a huge stream of toothpaste. This is the classic “Elephant Toothpaste” reaction. Purpose/Goal: Procedure presents an example of a catalyzed reaction. Explanation of Experiment: The rapid evolution of oxygen gas is produced by the following reaction: 2 H2O2 (aq) = 2 H2O (l) + O2 (g) + heat The decomposition of hydrogen peroxide in the presence
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