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    Chemistry

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    Isotopes and average atomic mass Isotope: element variations with different atomic mass but same atomic number Isotopic Abundance: the relative amount in which each isotope of an element Calculating: given 2 isotopes of an element [B: 10.01u] [B: 11.01u] 1) Given average atomic mass: 10.81u If given percentages‚ you can find average atomic mass by adding each portion 2) Set variables for unknown values Let x represent % abundance for 10/5 B Let 1-x represent % abundance for 11/5 B Calculate:

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    Chemistry

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    1. (a) The diagram below represents the industrial fractional distillation of crude oil. (i) Identify fraction A. (ii) What property of the fractions allows them to be separated in the column? (2) (b) A gas oil fraction from the distillation of crude oil contains hydrocarbons in the C15 to C19 range. These hydrocarbons can be cracked by strong heating. (i) Write the molecular formula for the alkane with 19 carbon atoms. (ii) Name the type of reaction involved in cracking. (iii) Write

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    Chemistry

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    Scuba diving is a form of underwater diving in which a diver uses a scuba set to breathe underwater. According to the Professional Association of Diving Instructor (PADI)‚ a “DEEP DIVE” is considered to be anything from 18 meters (60 ft) to 30 meters (100 ft). A scuba diver moves around underwater by using swim-fins attached to the feet‚ however external propulsion can be provided by a diver propulsion vehicle. Scuba diving may be performed for a number of reasons; either for recreational purposes

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    Chemistry

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    FINAL SUMMATIVE PRESENTATIONS This evaluation will involve working in groups of 3 to prepare a written report‚ poster and a demonstration of food preparation of your chosen topic. PART A: WRITTEN REPORT This should give the reader background information on your selected topic. This information will be shared with the class as an ongoing commentary in addition to your demonstration. The report will be typed using proper report format with a title page and subheadings. It should

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    CHEMISTRY

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    Keghan Chapter 8 MULTIPLE CHOICE QUESTIONS Topic: Structure Elucidation 1. An alkene adds hydrogen in the presence of a catalyst to give 3‚4-dimethylhexane. Ozonolysis of the alkene followed by treatment with zinc and acetic acid gives a single organic product. The structure of the alkene is: CH3 A) CH3CH=C-CHCH2CH3 (cis or trans) CH3 CH3 B) CH3CH2C=CCH3 (cis or trans) CH2CH3 C) CH3 CH2=CCH2CHCH2CH3 CH3 CH2 D) CH3CH2CCHCH2CH3 CH3 CH3 E) CH3CH2CHCHCH=CH2

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    chemistry

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    CELL STRUCTURE CELL THEORY: Structural and functional unit of all living things New cells arise from already existing cells Cells contain information that instructs growth. This information can be passed onto new cells. MICROSCOPES: There are two main types of microscopes: Light and Electron Electron Micrographs- shown in colour LIGHT ELECTRON Uses beam of light Magnification = x1500 Resolution = 200 nm  Wide range of specimens can be used  Samples are fairly quick + easy to prepare

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    Chemistry Kinetics

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    Research for Kinetics Coursework http://www.google.co.uk/#sclient=psy-ab&hl=en&rlz=1R2ADRA_enGB386&source=hp&q=An+investigation+into+the+kinetics+of+the+reaction+between+potassium+peroxodisulphate+and+potassium+Iodide&pbx=1&oq=An+investigation+into+the+kinetics+of+the+reaction+between+potassium+peroxodisulphate+and+potassium+Iodide&aq=f&aqi=&aql=1&gs_sm=e&gs_upl=4649l5023l3l5663l2l0l0l0l0l0l0l0ll0l0&rlz=1R2ADRA_enGB386&bav=on.2‚or.r_gc.r_pw.&fp=4cbda8eccdfde5e1&biw=1280&bih=600 http://www.chemistry-react

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    IB DIPLOMA PROGRAMME PROGRAMME DU DIPLÔME DU BI PROGRAMA DEL DIPLOMA DEL BI M07/3/BUSMT/SP1/ENG/TZ0/XX 22075013 BUSINESS AND MANAGEMENT STANDARD LEVEL PAPER 1 Thursday 17 May 2007 (afternoon) 1 hour 30 minutes INSTRUcTIONS TO cANDIDATES  Do not turn over this examination paper until instructed to do so.  Read the case study carefully and then answer all the questions. 2207-5013 2 pages © IBO 2007 http://www.xtremepapers.net –2– 1. 2. (a) 4. Draw an organizational chart for

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    Chemistry

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    Module 4: 10. Strong Bases: NaOH‚ KOH‚ Na2CO3‚ NaHCO3‚ Na3PO4‚ NaHPO4‚ Strong Acids: Fe(NO3)3‚ HCL‚ HNO3‚ Al(NO3)3‚ NiCl2‚ H2SO4 11. Acidic Neutral Basic NaCl KNO3 NaOH HC2H3O2 Na2CO3 NaC2H3O2 NaHCO3 Fe(NO3)3 NaNO3 Na3PO4 HCl MgSO4 KOH HNO3 Na2SO4 NaHPO4 CuSO4 NaNO2 CoCl2 Al(NO3)3 NiCl2 H2SO4 KCl NH4Cl 12. CuSO4 CuCO3.Cu(OH)2(s) + 2 H2SO4(aq) ----> 2 CuSO4(aq) + CO2(g) + 3 H2O(l) Na3PO4 Na3PO4 (aq) + 3H2O (l) --> H3PO4 (aq) + 3NaOH

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    Chemistry

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    Experiment 9 : 
The effect of substrate concentration on enzyme activity Objective To find out the relationship between the substrate concentration and the rate of reaction by determining the number of bubbles produce Hydrogen peroxide (H2O2) is a by-product of biochemical metabolism. An accumulation of hydrogen peroxide can be deadly‚ so it has to be decomposed. One of the decomposing factors is an enzyme called Catalase. Catalase breaks hydrogen peroxide into water and oxygen. The chemical

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