AP/IB Biology Lab Assessment The effect of various fruit and vegetable cell membranes on their water potential Independent variable: Type of fruit or vegetable. (Produce used: Russet potatoes‚ Pascal celery‚ Gala apple‚ Navel orange‚ and Imperator carrot). The fruit or vegetable will be placed in six 56.7 gram cups‚ ranging with sucrose molarities of 0 (distilled water)‚ 0.2‚ 0.4‚ 0.6‚ 0.8‚ 1.0‚ with 5 trials‚ leading to 30 cups for each produce variable. Dependent variable: The water potential
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Biology Enzymes IA Design Introduction: Enzymes are globular proteins‚ they are responsible for most of the chemical activities of a living organism. They act as catalysts‚ substances that affects the reaction of other substances without being destroyed or altered during the process. They are extremely efficient in the body system of living organisms‚ one enzyme may catalyse over a thousand chemical reactions every second. But there are certain conditions that need to be fulfilled in order for the
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Practice Math IA • Each set of steps above is composed of 1x1 squares • Show what 4 steps and 5 steps look like • ‘n’ represents the number of steps • Find the area for n= 1‚2‚3‚4‚5 Step 1: Step 2: Step 3: Step 4: Step 5: 12 = 1 12 x 3 = 3 1 2 x6 = 6 1 2x10 = 10 12x 15 =15 |Steps (n) |Area
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IB Mathematics SL Year 1 Welcome to IB Mathematics. This two-year course is designed for students who have a strong foundation in basic mathematical concepts. The topics covered in this course include: * Algebra * Functions * Equations * Circular functions * Trigonometry * Vectors * Statistics * Probability * Calculus ------------------------------------------------- Resources: * Textbook: Mathematics SL 3rd edition. Haese Mathematics 2012 ISBN: 978-1-921972-08-9
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M11/5/MATME/SP1/ENG/TZ1/XX 22117303 mathematics STANDARD level Paper 1 Candidate session number 0 0 Wednesday 4 May 2011 (afternoon) Examination code 2 1 hour 30 minutes 2 1 1 – 7 3 0 3 instructions to candidates Write your session number in the boxes above. not open this examination paper until instructed to do so. Do You are not permitted access to any calculator for this paper. Section A: answer all questions in the boxes
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forming CH3COO- and H3O+. As a result of the reaction‚ the equilibrium amounts of CH3COOH and H2O will be less; for every mole of CH3COO- formed‚ one mole of CH3COOH and one mole of H2O will react. The equilibrium constant expression Kc for Reaction 1 is: Kc = [CH3COOH] / [H3O+][CH3COO-] The value of Kc is relatively constant at a given temperature. This means that mixtures containing CH3COOH and H2O will come to equilibrium with the same value of Kc‚ no matter what initial amounts of CH3COOH and
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from the management department for gathering the data of the factory The workers of the factory for taking their time off to fill the surveys Table of Contents 1. Research Proposal & Action plan 2. Executive Summary 3. Introduction 3.1. About the Company 3.2. Figure 1: Falling labour productivity 3.3. Current Motivation strategies: Lack of non-financial incentives 3.4. Investigation Aim 4. Results and Findings 5. Analysis and Discussion 5.1. S.W.O.T Analysis
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1) Started with 24 two 11 double with loam.. Are giving around 1 lace 90 thousand meters per month production capacity...with job work activities. Q) Tell me about your historical background 2) Current market situation is badly distorted because of lack of purchasing capacity of the consumers. Q)what is the current market situation of your company? 3) Its too tough competition in synthetic market Q)is is working in competition? 4) Strength:- having around 9 laces per month production so that
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the gravitational field. RAW DATA TABLE PROCESSED DATA TABLE DATA PROCESSING GRAPH t²/s² AGAINST HEIGHT FROM GROUND h/m JUSTIFICATION FOR UNCERTAINTIES AND CALCULATIONS 1) Uncertainty for metre rule * Half of the smallest division on the analog instrument = 0.01m/2 =0.005m 2) Uncertainty for time taken * Smallest division on a digital stopwatch =0.01s 3) Average time = 0.74+0.75+0.773 =0.75s (for
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Background Research Yeast are eukaryotic microorganisms just like other organisms‚ they must respire in order to survive. Respiration can be defined as the controlled release of energy from organic compounds to form adenosine triphosphate (ATP). The type of respiration that occurs is called aerobic respiration. It occurs when glucose and oxygen are present. It can be summarized by the equation: . Enzymes play a very significant part in respiration. During the different stages of respiration‚ enzymes
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