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    Bjt Exercise

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    circuit shown in Figure 3‚ (i) Draw the h parameter equivalent circuit. (ii) Derive the expression for voltage gain and input impedance in h parameters. (iii) If the transistor of Figure 3 has the following set of h parameters: hie = 2k; hfe = 100; hre = 5 × 10-4; hoe = 2.5 × 10-5 S Find the voltage gain and ac input impedance. Figure 3 Ans: Zin = 1.53k‚ Av = 375 (10 marks) Consider the circuit in Figure 4 below. Find the voltage gain of the amplifier

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    Microwave Lab M.Pdf

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    EXPERIMENT NO. 1 AIM :- To study wave guide components. APPARATUS REQUIRED :- Flanges‚ Twisted wave guide‚ wave guide tees‚ Directional Coupler‚ Attenuator‚ Isolators‚ Circulators‚ Matched terminator‚ Slide screw tuner‚ Slotted Section‚ Tunable probe‚ Horn antennas‚ Movable Short‚ Detector mount. THEORY:- A pipe with any sort of cross- section that could be used as a wave guide or system of conductors for carrying electromagnetic wave‚ is called a wave guide in which the waves are truly guided.

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    Ac Theory

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    Fourth Edition‚ last update June 29‚ 2002 2 Lessons In Electric Circuits‚ Volume II – AC By Tony R. Kuphaldt Fourth Edition‚ last update June 29‚ 2002 i c 2000-2002‚ Tony R. Kuphaldt This book is published under the terms and conditions of the Design Science License. These terms and conditions allow for free copying‚ distribution‚ and/or modification of this document by the general public. The full Design Science License text is included in the last chapter. As an open and collaboratively

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    Nt1310 Week 4 Lab Report

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    √ 240mA^2 + 180mA^2= 0.3 x 10^-3= 300mA θ= tan^-1(-IL/IR)= (-240mA/180mA)= -53° 300mA∟-53° 22. Calculate the total impedance for the circuit shown in Figure 11.38b. It= √IL^2 + IR^2= √800mA^2 + 120mA^2= 0.808949 x 10^-3= 808.95mA Zt= Vs/It= 120V/808.95mA = 148Ω θ= tan^-1(-IL/IR)= (-800mA/120mA)= -81.5= 82° 148∟82° 24. Calculate the magnitude and phase angle of the circuit impedance shown in Figure 11.39b. IL= Vs/XL= 4V/38Ω= 0.10526 x 10^-3= 105.26mA IR= Vs/R= 4V/240Ω= 0.01666 x 10^-3= 16.67mA IT=

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    3001 problems

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    3001 MULTIPLE CHOICE QUESTIONS in ELECTRONICS ENGINEERING Santos S. Cuervo‚ ECE Susana A. Tan‚ ECE Encoded by: ASI‚ Rannilo Jr. L. DAMIAN‚ Sarah Joy V. DIAZ‚ Chona O. GLORIA‚ Mac Arco J. TAJANLANGIT‚ Alvin L. TORIO‚ Ayra Kate E. UMBAO‚ Raissa Grace C. PART 1: COMPILED QUESTIONS PER TOPIC CHAPTER 1: ELECTRICITY AND MAGNETISM FUNDAMENTALS 1. Who discovered the relationship between magnetism and electricity that serves as the foundation for the theory of electromagnetism

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    selected they are very versatile in terms of resonant frequency‚ polarization‚ pattern and impedance. Microstrip single antenna has several advantages and also has several disadvantages such as low gain‚ narrow bandwidth with low frequency. So‚ these disadvantages can be overcome by constructing many patch antennas in array configuration. The design used inset feeding method based on quarter wave impedance matching technique. However it does not mention the radiation efficiency‚ directivity‚ VSWR and

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    substation layout

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    Single Line Diagram of Substations Substations Electric power is produced at the power generating stations‚ which are generally located far away from the load centers. High voltage transmission lines are used to transmit the electric power from the generating stations to the load centers. Between the power generating station and consumers a number of transformations and switching stations are required. These are generally known as substations. Substations are important part of power system

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    Fault Analysis

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    Power System Fault Analysis 2.0 Introduction The fault analysis of a power system is required in order to provide information for the selection of switchgear‚ setting of relays and stability of system operation. A power system is not static but changes during operation (switching on or off of generators and transmission lines) and during planning (addition of generators and transmission lines). Thus fault studies need to be routinely performed by utility engineers (such as in the TNB). Faults

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    basic electronics

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    What’s the difference between resistance and resistivity? Resistance is the obstruction offered to the flow of current by a conductor. Resistivity is the obstruction offered to the flow of current by UNIT AREA OF the conductor. So basically‚ resistance is the property of the object (say a copper wire)‚ whereas resistivity is the property of the substance (copper). And so resistance depends upon the properties of the object. Whereas resistivity depends upon the properties of the metal.

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    Opamp

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    for an application. 1.1 IDEAL OPERATIONAL AMPLIFIER 1.1.1 Properties of An Ideal Operational Amplifier The characteristics or the properties of an ideal operational amplifier are: i. Infinite Open Loop Gain‚ ii. Infinite Input Impedance‚ iii. Zero Output Impedance‚ iv. Infinite Bandwidth‚ v. Zero Output Offset‚ and vi. Zero Noise Contribution. The opamp‚ an abbreviation for the operational amplifier‚ is the most important linear IC. The circuit symbol of an opamp shown in Fig. 1.1. The

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