= 47R C1 = 100uF-16V C2 = 100nF-63V C3 = 470uF-16V D1 = 1N4007 D2 = Red LED D3 = Green LED Q1 = BC558 Q2 = BC548 IR = TSOP1738 IC1 = CD4017 RL1 = Relay 5V DC Circuit Operation: The 38kHz infrared rays generated by the remote control are received by IR receiver module TSOP1738 of the circuit. Pin 1 of TSOP1738 is connected to ground‚ pin 2 is connected to the power supply through R5 and the output is taken from pin 3. The output signal is
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different elements apart. Can we tell every element apart from this test? Not with our flame test‚ but the idea of spectroscopy allows us to do so with a good detector and knowledge of spectral lines. Each metal will have it’s own unique spectral lines that correspond to the distances between electron orbits. Water samples are tested for heavy metals and other contaminants using spectroscopy. Elemental compositions of stars and planetary atmospheres can be determined by the emission lines given off
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until the IR illumination conditions of that region nearly constant. For example‚ if the potentiometer is tuned inside room/building for maximum sensitivity and then taken out in open sunlight‚ it will require retuning‚ since sun’s rays also contain Infrared (IR) frequencies‚ thus acting as a IR source (transmitter). This will disturb the receiver’s sensing capacity. Hence it needs to be returned to work perfectly in the new
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Mustaqim Ahmed Period 4 September 18‚ 2013 Analysis of Food Dyes in Beverages Purpose: To determine the concentration of dye in a sports drink using spectroscopy and graphical analysis. We will be using beers law to find the unknown concentration of dye in a sports drink. Materials: Beakers‚ 50-mL‚ 2-3 ; Test tubes (13 x 100)mm 3-8 ; FD&C Blue 1 stock solution‚ 50-mL ; Lens tissues ; Pipets‚ serological‚ 10-mL ; Sample of consumer sports drink‚ 10-mL ; Spectrophotometer ; Test tube rack Procedure:
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among other things. By looking at the shape of the spectrum of light emitted by a star‚ we can tell something about its average surface temperature. i) If we observe a star’s spectrum and find that the peak power occurs at the border between red and infrared light‚ what is the approximate surface temperature of the star? (in degrees C) 3767 C ii) If we observe a stars spectrum and find that the peak power occurs at the border between blue and ultraviolet light‚ what is the surface temperature of
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mol–1dm3cm at 466.00nm and 210.39mol–1dm3cm-1 at 338.00nm. and the colour of the crystals obtained were orange. The crude product was then reacted with L-(+)-tartaric acid and 0.59g of the enantiomer [Λ-Co(en)3][(+)-tart]Cl∙5H2O was obtained. FT-IR spectroscopy was performed and the spectrum was analyzed. Green crystals of trans-[Co(en)2Cl2]Cl∙HCl∙2H2O was also synthesized and the cis-isomer was subsequently isolated by heating the aqueous solution in a steam bath. The UV-vis spectrum of trans-[Co(en)2Cl2]Cl∙HCl∙2H2O
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their father’s differences in child rearing dramatically affect their respective senses of security and happiness. Danny and Reuven‚ an Unbelievable Friendship On one side of the visible light spectrum is ultra-violet rays‚ and on the other‚ infrared rays. If two people were to stand on a visible light spectrum and represent their personalities based on where each other stand‚ David Malter would stand on one side‚ and miles away‚ possibly not even on the spectrum would be Isaac Saunders. The
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___________? a. Humble b. Arrogant c. Auspicious d. Joyful 8. What is the missing number? 1 4 9 ? 25 a. 15 b. 16 c. 18 d. None of these The rate of interest obtained is a. 12.5% b. 13.5% c. 15% d. 16 2/3% 10. The ozone layer restricts a. Visible light b. Infrared radiation c. X-rays and gamma rays d. Ultra violet radiation Ans: ( d ) Ans: ( c ) Ans: ( b ) 9. A man bought 20 shares of Rs 50 at 5 discount‚ the rate of dividend being 13 ½ . Ans: ( b ) Ans: ( b ) Part II: Descriptive type: Duration 45 Minutes
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Sydney Schell October 18th‚ 2012 Identifying Metallic Components Introduction: Spectroscopy is the study of the electromagnetic radiation emitted or absorbed by the atoms and molecules. A photon in short is light. Atoms produce light by putting energy in‚ the electron then becomes excited and goes up an energy level‚ the electron then falls back down to its ground state‚ and out comes a photon (light). The electromagnetic spectrum contains color that we can and cannot see. The color blue has
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