NURS 315 Pathophysiology Module 1 Genetics Case Study Name _____Tammy Bills_______________________________________________ Review the following case study and answer the questions for each part located at the end of the case. Submit as directed to the drop box. “In Sickness and in Health” by Barry Chess Page A Trip to the Genetic Counselor Part 1—Pedigree Construction Greg and Olga were both a little worried. Starting a family presented choices and responsibilities far more long-reaching
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PCB 3063 Spring 2012 Problem Set 1 ANSWERS 1. Determine the types of gametes produced by each of the following individuals: a. Aa 1/2 A‚ 1/2 a b. AaBb 1/4 AB‚ 1/4 Ab‚ 1/4 aB‚ 1/4 ab c. AABb 1/2 AB‚ 1/ Ab d. AaBBCc 1/4 ABC‚ 1/4 aBC‚ 1/4 ABc‚ 1/4 aBc 2. Use the Punnett square to determine the genotypes in the progeny of each of the following crosses: a. Dd x Dd b. AaBB x AaBB c. CcEE x CCEe Notice: in every case‚ each parent produces
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organization has an organizational behavior that varies from industry to industry. The United States Army is a unique organization that requires a closer look to determine how traditional organizational behavior is applicable. This paper provides an integrative approach to tying three organizational topics to the Army work environment. The first topic discussed is the consequences of distress. Each individual responds to stressful situations differently and the result is either eustress or distress.
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Abstract In this experiment‚ the nature of linkage isomers will be observed on the example of nitritopentaamminecobalt(III) Chloride and nitropentaamminecobalt(III) Chloride. Their relative stability will be compared on standard conditions and the infrared spectroscopy of both the isomers will be obtained to analyze the characteristic absorption bands for the nitro and nitrito group. Yield for nitritopentamminecobalt(III) Chloride was obtained to be = 1.9221 g(73.24 %) and yield for nitropentamminecobalt(III)
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Linkage isomerism in cobalt(III) complexes Author: M Hurley Abstract Preparation of nitrito-kO-complex was prepared by ligand substitution from a chloridio-complex chemically made. The nitro-kN-complex was then prepared by isomerisation of the nitrito-kO-complex. Visible absorption and infrared spectroscopy was then carried out on all three complexes. The molar absorption coefficients calculated were 38.0 cm-1 mol-1 L for the chloridio-complex‚ 76.0 cm-1 mol-1 L for the nitrito-kO-complex
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PS 1130A‚ Human Growth and Development Chapter 1 worksheet on genes Match the sentence with the word below. HUMAN GENETICS In humans‚ all cells (except eggs and sperm) contain 46 chromosomes. This diploid chromosomal number represents two complete (or nearly complete) sets of genetic instructions - one from the egg and the other from the sperm. At fertilization‚ the chromosomes for the same traits pair up (homologous chromosomes) (1)______Allele_____ - genes (Gene - segment of DNA that codes for
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Falkenberg T. Patients’ experiences and perceptions of integrative care for back and neck pain. Alternative therapies in health and medicine. 2012 May 1;18(3):25. • The researchers try to examine the impact of integrating integrative approaches into the more traditional western based pain management plans. 15 patients received integrative care vs. 11 patients in the traditional intervention group. Authors found improvement among the integrative arm compared to the traditional arm. • Comment: Good
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Lab 6. Drosophila cross( start) Melat Mebrahtu Lab Instructor: Professor Hicks Principles of Biology Lab II‚ Wednesday 1:00 am- 2:00 pm Abstract The goal of this experiment was to examine the Drophisila fly cross for which the result was seen in two weeks .The Drosophila melanogaster has been a model organism that was experimented in the laboratory. It is a small fruit fly that feeds on and lives on spoiled fruit. It is one of the most valuable organisms in genetics
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EXTENTION OF MENDELIAN INHERITANCE Objective The objectives of this experiment were to observe Mendel’s law with inheritance trait of the curly wing mutation and the interactions between the mutant genes of vestigial wings and curved wings in Drosophila. Results Part A Cross A (wildtype females X curly males) Male Female Wild type 1 2 Curly wing 0 1 Table 1. The number of the phenotypes and sex of offspring of the Cross A Cross B (curly females X curly males) Male Female Wild
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Purpose To provide practice in using appropriate methods to answer questions and solve problems about monohybrid inheritance. Questions Q1 Some forms of albinism‚ a genetic disorder‚ may be due to a single gene mutation. The allele for albinism is recessive to the allele for no albinism. A woman is heterozygous for albinism. Her male partner is homozygous for the ‘normal’ allele. a Does the woman suffer from the condition? no b What percentage of their children are likely to be carriers
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