Key Questions Unit 1 Lesson 1 1. a) (2x3)(-7x5)= -14x8 b) -45x5y7z9/9x7y7z5= -5z4/x2 c) (-5x4)3= (-53)(x12)= -125x12 d) (3x4y5z7)5/(-3x3yz4)7=243y18z7/-2187x= y18z7/-9x e) (xa+b)a-b/(xa-2b)a+2b= (xa^2-b^2)/(xa^2-4b^2)= x3b^2 2. a)6-2= 1/62=1/36 b)253/2=(2√25)3=53=125 c) -85/3=(3√-8)5= (-2)5= -32 d) 625(-3/4)=1/(4√625)3=1/53= 1/125 3. a) 93x272x813= (32)3x(33)2x(34)3= 36x36x312= 324 b) 57x253/1254= (57x(52)3)/(53)4= 57x56/512=513/512= 5 4. 5. To find the equation of the
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PRI: We introduce a probabilistic version of the well-known Rand Index (RI) for measuringthe similarity between two partitions‚ called Probabilistic Rand Index (PRI)‚ in which agreements and disagreements at the object-pair level are weighted according to the probability of their occurring by chance. We then cast consensus clustering as an optimization problem of the PRI value between a target partition and a set of given partitions‚ experimenting with a simple and very efficient stochastic optimization
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object. Mechanical system such internal combustion engine has a very large number of degrees of freedom. L. J. Sitnik‚ M. Magdziak-Tokáowicz‚ R. Wróbel‚ P. Kardasz In order to cope with this problem and avoid the large number of calculations‚ interpolation functions are used to bring physical system to state in which the number of degrees of freedom is known. Components are divided in regard to mass. Components with lower mass are treated as deformable bonds‚ and those with larger mass are treated
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The V-n diagram usually focuses on both positive and negative loads‚ however since there is little knowledge known about the box wing‚ for simplicity‚ the positive loads are assumed to be more significant. Hence‚ if the box wings are optimised with the positive loads‚ the negative loadings will also be covered due to its least significance. The 3.5g pull out of dive is known as the most extreme load which is closest to critical pressures for distortion‚ as shown in figure (3.4). Hence using this
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Kriging is an optimal interpolator that has a minimum error variance.(Hung‚ 2001) Empirical Bayesian Kriging is a Kriging-based interpolation method that accounts for uncertainty in semivariogram estimation by simulating many semivariograms from the input data. In addition‚ Empirical Bayesian Kriging can account for moderate nonstationarity by building local models on subsets of the
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Abstracts and Keywords List for each chapter for the Wiley new book: System Simulation Techniques with MATLAB and Simulink Dingyü Xue‚ YangQuan Chen ISBN: 978-1-118-64792-9 Hardcover 488 pages Chapter-01 Introduction to System Simulation Techniques and Applications Abstract: This introductory chapter presents a concise overview of system simulation techniques and developments of simulation software including some historical early simulation softwares and programs. Then‚ MATLAB history and characteristics
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Christian Wollenberg March 7‚ 2014 Mr. Jo Christian Heritage Augustine and the Pear Tree “There was a pear tree near out vineyard‚ full of fruit‚ but it was not tempting because of its taste or appearance. Many of us lewd young me went late one night (having prolonged our street sports as was our custom) to shake and rob that tree. We took huge loads‚ not so we could eat them‚ and after tasting the pears‚ we threw the‚ to the hogs. We did this because we wanted to and because it was prohibited
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Multiple Choice Questions (2*20 points) 1. What are the objectives of information extraction from remotely sensed data? A. Identification of similar pixels. B. Grouping of thematic information. C. Interpretation using prior knowledge. D. Making sense of geographic patterns. E. All of the above. 2. Principal components analysis is associated with which of the following? A. Data reduction. B. Training samples. C. Components and Eigenvectors. D. A and C. E. A‚ B and C. 3. What are
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......................................... vii Interpolation 1 • Laboratory Notebook.................................................................................. 1 Interpolation 2 • Observation of Properties .......................................................................... 5 Project A • Observations on Solids ............................................................................................................ 7 Interpolation 3 • Numerical Uncertainty .....................
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Example 6.4: Application of General Equation for a Closed System Question A gas is contained in a cylinder fitted with a movable piston as presented in Figure E6.4.1. Figure E6.4.1: A cylinder fitted to a moving piston If the cylinder is placed in boiling water with the piston held in a fixed position‚ 5 kcal of heat is absorbed by the gas‚ which equilibrates at 150oC and a higher pressure. The piston is then released‚ and the gas does 250 J of work in moving to its new equilibrium position
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