Experiment No. 4 Solubility Equilibrium- Common Ion Effect INTRODUCTION: The common ion effect is another example of Le Châtelier ’s Principle in action.The common ion effect tells us that the solubility of an ionic compound is decreased by the addition to the solution of another ionic compound that contains one of the ions involved in the solution It is also responsible for the reduction in solubility of an ionic precipitate when a soluble compound combining one of the ions of the precipitate
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Mateo Castro April 3‚ 2013 Lab Partner: Unur Abdul Kader T.A: Katie Experiment 22: Molar Solubility‚ Common-Ion Effect Abstract The purpose of this experiment was to determine the molar solubility‚ the solubility constant‚ and the effect of a common ion on the molar solubility of calcium hydroxide. To accomplish this the experiment was split into two parts; part A and Part B. in Part A of the experiment a standardized 0.05 M solution of HCl was titrated into a 25 mL solution of saturated
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Solubility product The Solubility product is related to SPARINGLY SOLUBLE SALTS ONLY!!!!! Examples are silver chloride‚ lead(II) chloride‚ calcium sulphate (in other words‚ it deals with salts commonly called insoluble salts) Consider a sparingly soluble salt MX Imagine the reaction that occurs when the solid is placed in water aMX (s) + H2O [pic] aMn+ (aq) + bXm- (aq) The equilibrium expression would be [Mn+]a [Xm-]b [MX]a [H2O]
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Lab Experiment # 11 The common ion effect in dissolution and precipitation Equilibria Introduction: Dissolution and precipitation reactions are very important chemical reactions because it is applied to many aspects of the industries in medicine‚ food‚ water etc. The objectives of this laboratory experiment is to become familiar with dissolution and precipitation equilibria‚ develop a lab technique suitable for the determination of the solubility for a sparingly soluble salt‚ Ba(NO3)2 (s) at room
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exchange of positive and negative ions between reacting solutions of two ionic compounds. Thus‚ in this example the precipitate must be either silver chloride‚ AgCl or sodium nitrate‚ NaNO3. Sodium nitrate dissolves readily in water and is therefore soluble. Thus we can conclude that silver chloride is the insoluble precipitate. We can represent the formation of this precipitate by a net ionic equation: Ag+ +NO3 ̄ +Na++Cl ̄→AgCl+NO3 ̄+Na+ Net: Ag+ (aq)+Cl ̄ (aq)→AgCl(s) Ions present in the solution but
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NO. 5 COMMON ION EFFECT Lopez‚ Pauline G. HIJ-2‚ Group No. 5‚ Ms. Jervee M. Punzalan Ramales‚ Ayane Mark Q. September 15‚ 2014 I. ABSTRACT The common ion effect involves how the solubility of a salt changes when some ion that is common to both added substance and the salt in question is introduced. The presence of a common ion hinders the ionization of a weak acid or a weak base hence this is known as the common ion effect. Simply put‚ the effect of the common
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Buffer solutions and common ion effect A buffer solution resists (or buffers) a change in its pH. That is‚ we can add a small amount of an acid or base to a buffer solution and the pH will change very little. How to calculate pH of buffer solution containing both acid and conjugate base? Dissociation constant definition 1.1 can be rearranged into or (note that due to sign change [A-] was moved to nominator). This is so called Henderson-Hasselbalch equation (or buffer equation)
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EXPERIMENT 2: COMMON-ION EFFECT AND BUFFERS MARVILE REA R. FERRER1 1DEPARTMENT OF MINING‚ METALLURGICAL & MATERIALS ENGINEERING‚ COLLEGE OF ENGINEERING UNIVERSITY OF THE PHILIPPINES‚ DILIMAN‚ QUEZON CITY 1101‚ PHILIPPINES DATE SUBMITTED: DECEMBER 13‚ 2012 DATE PERFORMED: DECEMBER 07‚ 2012 ______________________________________________________________________________________________________________ INTRODUCTION Monitoring the pH range of a laboratory reaction or a process is very
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The Effect of Temperature on Solubility By Aviraj Singh Rogers 2 Background: The solubility of most solid substances is generally said to increase as the temperature of the solvent increases. However‚ some substances‚ such as ytterbium sulfate‚ do the opposite. This can be explained through the Second Law of Thermodynamics which states that “in all energy exchanges‚ if no energy enters or leaves the system‚ the potential energy of the state will always be less than that of the initial state”
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Lab 3: Solubility of Organic Compounds Objectives: Understanding the relative solubility of organic compounds in various solvents. Exploration of the effect of polar groups on a nonpolar hydrocarbon skeleton. Introduction: The solubility of a solute (a dissolved substance) in a solvent (the dissolving medium) is the most important chemical principle underlying three major techniques you will study in the organic chemistry laboratory: crystallization‚ extraction‚ and chromatography.
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