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    Investigation of the factors affecting the period of vibration of a weighted cantilever Introduction The aim of the experiment is to find out how the period T of vibration of a weighted cantilever depends on the vibrating length L. Hypothesis: Assume the relationship between the vibrating period T and vibrating length L is in accord with the equation: T=kLn‚ where k and n are both constant values. According to the hypothesis‚ the vibrating period T and vibrating length L is a linear relationship

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    Conclusion: Category 1: Momentum was found that after the collision was less than before the collision by 10%. This was not what has been expected‚ so the difference was fairly significant. This happened because of friction‚ when the two pucks collided‚ they have lost a bit of their momentum‚ so the momentum after the collision differed. Kinetic energy differed more than what was expected‚ it was significantly less after the collision‚ the difference before and after the collision was 63.7%‚

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    MECHANICS I: Statics (Date of document: 1st October 2013) Course Code : MEMB123 Course Status : Core Level : Degree Semester Taught : 2 Credit : 3 Pre-requisites : None Assessments : Assignments + Quizzes 20% Midterm Test 20% Mini Project 10% Final Examination 50% Lecturers : Dr. Abreeza Manap Room BN-3-063‚ ext. 7234 E-mail: Abreeza@uniten.edu.my Yip Chan Heng Room BN-3-038‚ ext. 2251 E-mail: Chyip@uniten.edu.my Azieyanti Nurain Room BN-3-073‚ ext

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    Engineering Physics 1

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    WWW.MIAMI-BEST-MATH-TUTOR.COM E-MAIL: MIAMIMATHTUTOR@GMAIL.COM CONTACT NUMBER: (786)556-4839 More on Work and the Work-Energy Theorem Practice Problems 1. A 0.600-kg particle has a speed of 2.00 m/s at point A and kinetic energy of 7.50 J at point B. What is its speed at B? the total work done on the particle as it moves from A to B? kinetic energy at A? its WWW.MIAMI-BEST-MATH-TUTOR.COM PHYSICS.I.MORE.ON.WORK.ENERGY.7.2.PRACTICE.PROBLEMS PAGE 1 OF 8 2. A 0.300-kg ball has a speed of 15.0

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    12 year old sex

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    Floating Balloon Purpose : To demonstrate the principle of buoyancy of warm air. Additional information : The density variation between warm and cool air can be used to explain why warm air possesses higher buoyancy. As hot air contain atoms and molecules with higher kinetic energy than cold air‚ it has a lower density and rises up while the colder air goes downwards

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    Collisions

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    1) Introduction This Lab is about conservation of momentum. It is to investigate the difference of momentum before and after collisions. Using the photo gates record the velocity of each cart‚ comparing momentum and kinetic energy to find the law. The experimental apparatus are two red carts in approximately same weight and a gold cart in lower weight than the red ones‚ a stable air track (blow a constant stream of air out through numerous tiny holes) with low friction and two photo gates. 2) Project

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    General Paper

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    6 Worksheet (AS) 1 v A body moving with speed v collides v 2 elastically with another body travelling in v the opposite direction with speed . 2 Which row in the table below correctly gives the relative velocity of approach and the relative velocity of separation of the two bodies? [1] Relative velocity of approach A B C D Relative velocity of separation v 2 v 2 3v 2 3v 2 v 2 3v 2 v 2 3v 2 2 A body of mass m travels with a velocity 3v and collides with another particle of mass

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    Mechanics: Work‚ Energy‚ Momentum‚ Kinematics of Rotational Motion Jacque Lynn F Gabayno‚ Ph.D. Lecture Notes 1 Work as defined in Physics r r W =F s Force× Displacement = Force × Displacement *SI Units: 1 N.m = 1 Joules (i.e. same as the unit of energy) 2 Recall “Dot Product” The dot product allows us to multiply two vectors to get something that is SCALAR. r A r A For a constant force: r r r B = A B cos ! r B = Ax Bx + Ay By + Az Bz Only those along the direction of

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    During an experiment‚ there was a glass eye dropper placed into a bottle filled to the brim with water with the cap closed. The glass eye dropper floated in the bottle when the bottle was left alone. When the bottle was squeezed‚ however‚ the glass dropper sunk to the bottom. When the pressure was released from the bottle‚ the dropper floated back to the top of the bottle. The dropper floated at the top of the bottle when no pressure was applied‚ because the air inside the dropper was less dense

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    Informing & Persuading

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    University Author Note This paper was prepared for Principles of Speech Communication 120‚ Module 1 Homework Assignment taught by Instructor Deborah Zipnick. PART I: SHORT RESPONSE Write a response to the following prompt using proper APA Style. Prompt: You will select a topic for your informational speech. Limit the scope of your topic based on the idea that you can present the actual speech in four to seven minutes. Step 1: Review the information presented in Module

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