the detail becomes more developed in the following paragraphs. The closing paragraphs of the articles are similar in the way that the less important and less necessary information is added towards the end. They have both been written using the inverted pyramid structure‚ meaning the information is arranged in descending order of importance. The most important material is placed at the beginning of the story and the less important information follows. It is effective because it tells the reader
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PST201F/101/3/2015 Tutorial letter 101/3/2015 MATHEMATICS AND MATHEMATICS TEACHING PST201F Semester 1 and 2 Department Mathematics Education IMPORTANT INFORMATION: This tutorial letter contains important information about your module. BAR CODE Learn without limits UNISA 2 CONTENT 1 INTRODUCTION .............................................................................................................................................. 3 2 PURPOSE OF AND OUTCOMES FOR THE MODULE ......
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_______ a) Sector b) Segment c) Semicircle d) Triangle _____ 2. The line that intersects the circle at two distinct points is called _____ a) Tangent b) Segment c) Secant d) Ray _____ 3. The angle whose vertex lies on the circle and whose sides are two chords is said to be ____ a) Central b) Circumscribed c) Dihedral d) Inscribed _____ 4. The region bounded by two concentric circles is ______ a) An annulus b) A sector c) A segment d) A right triangle _____ 5. A dodecagon is a polygon of ____ sides
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handicrafts. And one part of these shapes and angles is the angle bisector. Angle bisector is a ray that divides an angle into two congruent parts. It is also called the internal angle bisector. And the angle bisectors of a triangle intersect at a point called the incenter of triangle. This angle bisector is usually used or applied by the students in math particularly in the field of geometry. But unfortunately‚ there’s no device that can help the students bisect an angle easier. That’s one of the reasons
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Angle HAB = 72° B F I 72˚ (a) What is the size of angle CBI? (b) The bar BH bisects the angle ABI. (i) (c) 2. G H A (1 mark) What is the size of angle IBH? (1 mark) What is the size of angle FHG? (1 mark) Name a triangle which is congruent to triangle CBI. (1 mark) The sloping sides of a flower bowl are part of a cone as shown. The radius of the top of the bowl is 10 cm and the radius of the bottom of the bowl is 5 cm. The height of the full cone is 24 cm. Not to scale 10 cm
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4. If the base of an isosceles triangles are produced both ways‚ show that the exterior angles so formed are equal. 5. In the figure‚ AD= AE‚ BD= CE and ∠AEC=∠ADB. Prove that AB = AC. 6. In the figure‚ ΔABC and ΔDBC are both isosceles triangles. Prove that‚ ΔABD = ACD. 7. Show that the medians drawn from the extremities of the base of an isosceles triangle to the opposite sides are equal to one another. 8. Prove that the angles of an equilateral triangle are equal to one another. 10.2
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5C Problems involving triangles cQ1. The diagram shows a sector AOB of a circle of radius 15 cm and centre O. The angle at the centre of the circle is 115. Calculate (a) the area of the sector AOB. (b) the area of the shaded region. (226 ‚ 124 nQ2. Consider a triangle and two arcs of circles. The triangle ABC is a right-angled isosceles triangle‚ with AB = AC = 2. The point P is the midpoint of [BC]. The arc BDC is part of a circle with centre A
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Surface area of sphere = 4ʌU 2 1 2 ʌU h 3 Curved surface area of cone = ʌUO r l h r The Quadratic Equation The solutions of ax2 + bx + c = 0 where D0‚ are given by In any triangle ABC C b A Sine Rule a x= B c −b ± (b 2 − 4ac) 2a a b c = = sin A sin B sin C Cosine Rule a2 = b2 + c 2 – 2bc cos A Area of triangle = 2 1 ab
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information to be manipulated too create two isosceles triangles. The first triangle and the one that is given‚ ∆OPA is an isosceles triangle therefore it can be concluded‚ thanks to the Isosceles Triangle Theorem that angle O and A are congruent to each other in this triangle. ∆OPA is not the only triangle that can be created‚ ∆OP’A is the second triangle created with a radius from C2. Therefore ∆OP’A is also an isosceles triangle. Now in both the triangles stated above‚ they share a common angle‚ O. With
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3 A tent has a groundsheet as its horizontal base. The shape of the tent is a triangular prism of length 8 metres‚ with two identical half right-circular cones‚ one at each end. The vertical cross-section of the prism is an isosceles triangle of height 2.4 metres and base 3.6 metres. (a) Calculate the area of the groundsheet. Give
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