Erin Bolton Chemistry Lab Report April 29‚ 2015 Lab: Reaction Rates Introduction: In this experiment we studied the reaction of potassium persulfate‚ K2S2O8‚ with potassium iodide‚ KI. All chemical reactions have an energy barrier to overcome before the reaction will proceed. We will record data based on the concentration‚ temperature and catalyst for each experiment. Once this has been completed it will be graphed. Procedure: Due to the chemicals being used having hazard gloves are used
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Once Upon a Time by Gabriel OkaraOnce upon a time‚ son‚they used to laugh with their heartsand laugh with their eyes:but now they only laugh with their teeth‚while their ice-block-cold eyessearch behind my shadow.There was a time indeedthey used to shake hands with their hearts:but that’s gone‚ son.Now they shake hands without heartswhile their left hands searchmy empty pockets.‘Feel at home!’ ‘Come again’:they say‚ and when I comeagain and feelat home‚ once‚ twice‚there will be no thrice-for then
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Purpose: The purpose of the ‘Rates of Reactions’ lab is to learn how to plan an investigative lab without outside help and to learn about the ‘Rates of Reactions’. This lab will require students to take responsibility for their own learning and use their prior knowledge to aid in the completion of this lab. In the lab prepared below‚ students will be learning about Rates of Reaction with varying concentrations of Alka-Seltzer with water. Hypothesis: I believe that the more water added to the canister
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volume). 3. [10 points] The following reaction is found to be first order in A: A −→ B + C If half of the starting quantity of A is used up after 56 seconds‚ calculate the fraction that will be used up after 6.0 minutes. 4. [15 points] The rate law for the decomposition of ozone to molecular oxygen 3 O3 (g) −→ 3 O2 (g) is rate = k [O3 ]2 . [O2 ] The mechanism for this process is k1 O3 O + O2 k−1 k 2 O + O3 −→ 2 O2 Derive a rate law from these elementary steps. Clearly
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A neutralization reaction of ethanoic acid and sodium hydrogen carbonate Cristina Li 17th April 2017 Introduction The hypothesis is the balloon will be bigger and bigger with the increase of vinegar. The chemical reaction between the baking soda and vinegar produces bubbles of carbon dioxide gas as part of this acid-base reaction. Sodium hydrogen carbonate (baking
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Affecting Rate of Reaction Introduction Hydrogen Peroxide (H2O2)‚ is the most simple peroxide and commonly used in several household items such as toothpaste or as an alternative to bleach. However hydrogen peroxide it is a very dangerous substance when accumulated in large amounts. If that situation occurs this substance must be decomposed. But how can we decompose this reaction? Well it decomposes by itself very slowly (2H2O2(aq) -> 2H2O(l) + O2(g))‚ but that would take too long. This reaction can
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experiment is to find out the rate of reaction between Hydrochloric acid (HCL) and Magnesium (Mg) in different temperatures. The products that will be formed are Magnesium Chloride (MgCl2) and Hydrogen (H2). Prediction: I predict that as the temperature increases the rate of reaction also increases. To further explore the fact I further predict that the rate of reaction will double for every 10° C rise in temperature. I further predict as the temperature rises by 10° C the rate of collisions will also
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catalyst in the form of a metal ion affect the rate of reaction in an iodide clock reaction with potassium peroxydisulphate ions? Background When peroxydisulfate ions (S2O82-) react with iodide ions (I-) in the presence of a starch indicator‚ they produce a dark blue solution. Reaction (1) S2O82- + 3I- I3- + 2 SO42- (peroxydisulfate ion) (iodide ion) (iodine ion) (sulfate ion) To determine the rate law for this reaction a series of changes in the concentration
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initial rate of reaction. I will measure the effect of the enzyme in 5 different concentrations against the controlled variable of the reactant. The enzyme which will be used is different concentrations of potato and the reactant used will be Hydrogen Peroxide. Hydrogen Peroxide which will be the buffer solution is a PH of 7.2. My hypothesis for the experiment is that as the concentration of the enzyme is increased the rate of reaction will be increased‚ producing oxygen at a faster rate. The results
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Title: Effect of a Catalyst on Reaction Rate II. Introduction: The basis of the experiment is the enzyme; an enzyme is a biological molecule that acts as a highly selective catalyst. By combining with a substrate‚ an enzyme is able to create a new product that helps the body function. (Ex. Lactose/Lactase) A substrate is a molecule an enzyme acts upon‚ the two combine at an area called an active site. This active site allows induced fit which allows the reaction to occur and a new product to be
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