km 5 93 3 106 mi 3.8 3 105 km 5 2.4 3 105 mi 3500 km < 2160 mi 1.4 × 106 km < 864‚000 mi LibraryPirate PHYSICS LABORATORY EXPERIMENTS S e v e n t h E d i t i o n Jerry D. Wilson Lander University Cecilia A. HernÁndez-Hall American River College Australia • Brazil • Japan • Korea • Mexico • Singapore • Spain • United Kingdom • United States LibraryPirate Physics
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Lecture Outline Chapter 2 Physics‚ 4th Edition James S. Walker Copyright © 2010 Pearson Education‚ Inc. Chapter 2 One-Dimensional Kinematics Copyright © 2010 Pearson Education‚ Inc. Units of Chapter 2 • Position‚ Distance‚ and Displacement • Average Speed and Velocity • Instantaneous Velocity • Acceleration • Motion with Constant Acceleration • Applications of the Equations of Motion • Freely Falling Objects Copyright © 2010 Pearson Education‚ Inc. 2-1 Position
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Raymond Ye Mr. Pettibone IB Physics 2 November 2013 Internal Assessment DESIGN Aspect 1: How does the time a rubber band spends stretching a force of 12.5 N affect the force required to break/snap the rubber band? IV- The time spent stretching the rubber band 12.5 N DV- The force required to break/snap the band Units for Independent Variable- Minutes Units for Dependent Variable- Newtons Aspect 2: Variables that will be kept the same include: -The force of the stretch -Conditions
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Wilson‚ College Physics‚ 6th Edition Chapter 9 Exercises MC = Multiple Choice Question‚ CQ = Conceptual Question‚ and IE = Integrated Exercise. Throughout the text‚ many exercise sections will include “paired” exercises. These exercise pairs‚ identified with red numbers‚ are intended to assist you in problem solving and learning. In a pair‚ the first exercise (even numbered) is worked out in the Study Guide so that you can consult it should you need assistance in solving it. The second exercise
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Experiment 9: THE TANGENT GALVANOMETER; PURPOSE: In this experiment we will measure the magnitude of the horizontal component of the Earth’s Magnetic field by the use of an instrument called a tangent galvanometer. INTRODUCTION: A tangent galvanometer consists of a number of turns of copper wire wound on a hoop. At the center of the hoop a compass is mounted. When a direct current flows through the wires‚ a magnetic field is induced in the space surrounding the loops of
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Therefore the sum of all the energies in the system is a constant. TMEinitial=TMEfinal 3. Explain the basic ideas that govern the design and operation of a roller coaster. A roller coaster is operated and designed through the application of Physics. The law of Conservation of Energy governs the changes in a coaster ’s speed and height. Simply put‚ the higher an object is off the ground‚ the more potential energy it has - that is‚ potential to gain speed as it falls. As it falls toward the ground
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1.1 GRAVITY AND GRAVITATIONAL FIELDS 1.1.1 Define weight as the force on an object due to a gravitational field. Weight is the force experienced by an object due to the presence of a gravitational field. This force is directly related to the strength of the gravitational field acting on an object and the mass of that object. m = mass‚ g = acceleration due to gravity m = mass‚ g = acceleration due to gravity Fg = mg Fg = mg 1.1.2 Explain that a change in gravitational
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little ways‚ to help preserve our only home. We are given an INVESTIGATORY PROJECT in our physics class to somehow lessen our environmental problem. Our project to be investigated is the HOMEMADEOR NATURAL INSECTICIDE. We all know‚ that our Ozone layer is getting thinner and thinner every time because of the chemicals we use daily. Now‚ to lessen the problem in our ozone layer‚ we are going to study about the use of natural insecticide. We can not only protect and help
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AAI/Kullu/Engg.(C)/RTI/ Dated : 20.06.2013 To Asstt. General Manager (Engg. –Civil)-II Airports Authority Of India Subject : Reply of RTI application. Sir‚ In reference to letter no – A.12034/20/2013‚-Cont Cell‚ dated 27.05.2013‚ regarding request for information by RTI application dated 15.05.2013‚ of Shri Prem Chand‚ 614‚ Gulabi Bagh‚ Delhi ‚ addressed to Ministry of Civil Aviation received through the MOCA vide letter no 50/152/2013-RTI (C&W)‚ dated 15.05.2013 for seeking
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Kinematics / Projectiles x =?vt ?v = (v + vo)/2 v = vo + at x = vot + ½at2 v2 = vo2 + 2ax y =?vt ?v ’ ½(vo + v) v = vo – gt y = vot – ½gt2 v2= vo2 – 2gy R = (v02/g)sin(2θ) Forces Fnet = ma Fgravity = mg Ffriction ≤ μsN Ffriction = μkN Circular Motion Fnet = mv2/r ac = v2/r v = 2πr/T f = 1/T T = 1/f Gravitation F = GM1M2/R2 g = GM/R2 T2/R3 = 4π2/GM = constant GM = Rv2 Energy W = Fdcosθ KE
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